我有一些UTF-8编码的数据生活在Javascript Uint8Array元素的范围内。是否有一种有效的方法来解码这些到一个常规的javascript字符串(我相信javascript使用16位Unicode)?我不想一次添加一个字符,因为字符串连接会变得CPU密集。
当前回答
Uint8Array to String
let str = Buffer.from(key.secretKey).toString('base64');
String到Uint8Array
let uint8arr = new Uint8Array(Buffer.from(data,'base64'));
其他回答
到目前为止,对我来说最简单的方法是:
//1. Create or fetch the Uint8Array to use in the example
const bufferArray = new Uint8Array([10, 10, 10])
//2. Turn the Uint8Array into a regular array
const array = Array.from(bufferArray);
//3. Stringify it (option A)
JSON.stringify(array);
//3. Stringify it (option B: uses @serdarsenay code snippet to decode each item in array)
let binArrayToString = function(binArray) {
let str = "";
for (let i = 0; i < binArray.length; i++) {
str += String.fromCharCode(parseInt(binArray[i]));
}
return str;
}
binArrayToString(array);
使用base64作为编码格式效果很好。这就是它是如何实现通过url在Firefox发送传递秘密。您将需要base64-js包。下面是Send源代码中的函数:
const b64 = require("base64-js")
function arrayToB64(array) {
return b64.fromByteArray(array).replace(/\+/g, "-").replace(/\//g, "_").replace(/=/g, "")
}
function b64ToArray(str) {
return b64.toByteArray(str + "===".slice((str.length + 3) % 4))
}
var decodedString = decodeURIComponent(escape(String.fromCharCode(...new Uint8Array(err)))); var obj = JSON.parse(decodedString);
对于ES6和UTF8字符串
decodeURIComponent(escape(String.fromCharCode(...uint8arrData)))
这应该可以工作:
// http://www.onicos.com/staff/iz/amuse/javascript/expert/utf.txt
/* utf.js - UTF-8 <=> UTF-16 convertion
*
* Copyright (C) 1999 Masanao Izumo <iz@onicos.co.jp>
* Version: 1.0
* LastModified: Dec 25 1999
* This library is free. You can redistribute it and/or modify it.
*/
function Utf8ArrayToStr(array) {
var out, i, len, c;
var char2, char3;
out = "";
len = array.length;
i = 0;
while(i < len) {
c = array[i++];
switch(c >> 4)
{
case 0: case 1: case 2: case 3: case 4: case 5: case 6: case 7:
// 0xxxxxxx
out += String.fromCharCode(c);
break;
case 12: case 13:
// 110x xxxx 10xx xxxx
char2 = array[i++];
out += String.fromCharCode(((c & 0x1F) << 6) | (char2 & 0x3F));
break;
case 14:
// 1110 xxxx 10xx xxxx 10xx xxxx
char2 = array[i++];
char3 = array[i++];
out += String.fromCharCode(((c & 0x0F) << 12) |
((char2 & 0x3F) << 6) |
((char3 & 0x3F) << 0));
break;
}
}
return out;
}
与其他解决方案相比,它更简洁,因为它不使用任何hack,也不依赖于浏览器JS函数,例如,也可以在其他JS环境中工作。
查看JSFiddle演示。
请参见相关问题:这里和这里