我尝试了Adam Boduch的代码来输出一个很深的差异-这完全没有经过测试，但碎片在那里:

function diff (obj1, obj2, path) {
    obj1 = obj1 || {};
    obj2 = obj2 || {};

    return _.reduce(obj1, function(result, value, key) {
        var p = path ? path + '.' + key : key;
        if (_.isObject(value)) {
            var d = diff(value, obj2[key], p);
            return d.length ? result.concat(d) : result;
        }
        return _.isEqual(value, obj2[key]) ? result : result.concat(p);
    }, []);
}

diff({ foo: 'lol', bar: { baz: true }}, {}) // returns ["foo", "bar.baz"]

这是我对这个问题的解决办法

const _ = require('lodash');

var objects = [{ 'x': 1, 'y': 2, 'z':3, a:{b:1, c:2, d:{n:0}}, p:[1, 2, 3]  }, { 'x': 2, 'y': 1, z:3, a:{b:2, c:2,d:{n:1}}, p:[1,3], m:3  }];

const diffFn=(a,b, path='')=>_.reduce(a, function(result, value, key) {

    if(_.isObjectLike(value)){
      if(_.isEqual(value, b[key])){
        return result;
      }else{

return result.concat(diffFn(value, b[key], path?(`${path}.${key}`):key))
      }
    }else{
return _.isEqual(value, b[key]) ?
        result : result.concat(path?(`${path}.${key}`):key);
    }
    
}, []);

const diffKeys1=diffFn(objects[0], objects[1])
const diffKeys2=diffFn(objects[1], objects[0])
const diffKeys=_.union(diffKeys1, diffKeys2)
const res={};

_.forEach(diffKeys, (key)=>_.assign(res, {[key]:{ old: _.get(objects[0], key), new:_.get(objects[1], key)} }))

res
/*
Returns
{
  x: { old: 1, new: 2 },
  y: { old: 2, new: 1 },
  'a.b': { old: 1, new: 2 },
  'a.d.n': { old: 0, new: 1 },
  'p.1': { old: 2, new: 3 },
  'p.2': { old: 3, new: undefined },
  m: { old: undefined, new: 3 }
}
*/

对于无意中发现这条线索的人，这里有一个更完整的解决方案。它将比较两个对象，并给出所有属性的键，这些属性要么只存在于object1中，要么只存在于object2中，要么同时存在于object1和object2中，但值不同:

/*
 * Compare two objects by reducing an array of keys in obj1, having the
 * keys in obj2 as the intial value of the result. Key points:
 *
 * - All keys of obj2 are initially in the result.
 *
 * - If the loop finds a key (from obj1, remember) not in obj2, it adds
 *   it to the result.
 *
 * - If the loop finds a key that are both in obj1 and obj2, it compares
 *   the value. If it's the same value, the key is removed from the result.
 */
function getObjectDiff(obj1, obj2) {
    const diff = Object.keys(obj1).reduce((result, key) => {
        if (!obj2.hasOwnProperty(key)) {
            result.push(key);
        } else if (_.isEqual(obj1[key], obj2[key])) {
            const resultKeyIndex = result.indexOf(key);
            result.splice(resultKeyIndex, 1);
        }
        return result;
    }, Object.keys(obj2));

    return diff;
}

下面是一个输出示例:

// Test
let obj1 = {
    a: 1,
    b: 2,
    c: { foo: 1, bar: 2},
    d: { baz: 1, bat: 2 }
}

let obj2 = {
    b: 2, 
    c: { foo: 1, bar: 'monkey'}, 
    d: { baz: 1, bat: 2 }
    e: 1
}
getObjectDiff(obj1, obj2)
// ["c", "e", "a"]

如果你不关心嵌套对象并且想要跳过lodash，你可以替换_。isEqual用于正常的值比较，例如obj1[key] === obj2[key]。

作为对亚当·博杜赫的回答的补充，这个问题考虑到了性质的差异

const differenceOfKeys = (...objects) =>
  _.difference(...objects.map(obj => Object.keys(obj)));
const differenceObj = (a, b) => 
  _.reduce(a, (result, value, key) => (
    _.isEqual(value, b[key]) ? result : [...result, key]
  ), differenceOfKeys(b, a));

此解决方案返回一个具有修改过的属性的对象。

_.reduce(a, (r, v, k) => { return _.merge(r, _.isEqual(v, b[k]) ? {} : { [k]: v }); }, {});

下面是一个使用Lodash的简单解决方案:

_.differenceWith(a, b, _.isEqual);

注意，两个输入都需要是数组(可能是一个对象的数组)。