在这个答案的更新3中已经明确表示,这个符号:

var hash = {};
hash[X]

实际上并不散列对象X;它实际上只是将X转换为一个字符串(如果它是一个对象,则通过. tostring(),或者其他一些用于各种基本类型的内置转换),然后在“哈希”中查找该字符串,而不散列它。对象相等性也不检查-如果两个不同的对象具有相同的字符串转换,它们将相互覆盖。

鉴于此,JavaScript中是否有有效的hashmap实现?

(例如,javascript hashmap的第二个谷歌结果对任何操作产生的实现都是O(n)。其他各种结果忽略了具有等效字符串表示的不同对象会相互覆盖这一事实。


当前回答

不幸的是,之前的答案都不适合我的情况:不同的键对象可能具有相同的散列代码。因此,我写了一个简单的类似java的HashMap版本:

function HashMap() {
    this.buckets = {};
}

HashMap.prototype.put = function(key, value) {
    var hashCode = key.hashCode();
    var bucket = this.buckets[hashCode];
    if (!bucket) {
        bucket = new Array();
        this.buckets[hashCode] = bucket;
    }
    for (var i = 0; i < bucket.length; ++i) {
        if (bucket[i].key.equals(key)) {
            bucket[i].value = value;
            return;
        }
    }
    bucket.push({ key: key, value: value });
}

HashMap.prototype.get = function(key) {
    var hashCode = key.hashCode();
    var bucket = this.buckets[hashCode];
    if (!bucket) {
        return null;
    }
    for (var i = 0; i < bucket.length; ++i) {
        if (bucket[i].key.equals(key)) {
            return bucket[i].value;
        }
    }
}

HashMap.prototype.keys = function() {
    var keys = new Array();
    for (var hashKey in this.buckets) {
        var bucket = this.buckets[hashKey];
        for (var i = 0; i < bucket.length; ++i) {
            keys.push(bucket[i].key);
        }
    }
    return keys;
}

HashMap.prototype.values = function() {
    var values = new Array();
    for (var hashKey in this.buckets) {
        var bucket = this.buckets[hashKey];
        for (var i = 0; i < bucket.length; ++i) {
            values.push(bucket[i].value);
        }
    }
    return values;
}

注意:键对象必须“实现”hashCode()和equals()方法。

其他回答

我已经实现了一个JavaScript HashMap,其代码可以从http://github.com/lambder/HashMapJS/tree/master获得

代码如下:

/*
 =====================================================================
 @license MIT
 @author Lambder
 @copyright 2009 Lambder.
 @end
 =====================================================================
 */
var HashMap = function() {
  this.initialize();
}

HashMap.prototype = {
  hashkey_prefix: "<#HashMapHashkeyPerfix>",
  hashcode_field: "<#HashMapHashkeyPerfix>",

  initialize: function() {
    this.backing_hash = {};
    this.code = 0;
  },
  /*
   Maps value to key returning previous association
   */
  put: function(key, value) {
    var prev;
    if (key && value) {
      var hashCode = key[this.hashcode_field];
      if (hashCode) {
        prev = this.backing_hash[hashCode];
      } else {
        this.code += 1;
        hashCode = this.hashkey_prefix + this.code;
        key[this.hashcode_field] = hashCode;
      }
      this.backing_hash[hashCode] = value;
    }
    return prev;
  },
  /*
   Returns value associated with given key
   */
  get: function(key) {
    var value;
    if (key) {
      var hashCode = key[this.hashcode_field];
      if (hashCode) {
        value = this.backing_hash[hashCode];
      }
    }
    return value;
  },
  /*
   Deletes association by given key.
   Returns true if the association existed, false otherwise
   */
  del: function(key) {
    var success = false;
    if (key) {
      var hashCode = key[this.hashcode_field];
      if (hashCode) {
        var prev = this.backing_hash[hashCode];
        this.backing_hash[hashCode] = undefined;
        if(prev !== undefined)
          success = true;
      }
    }
    return success;
  }
}

//// Usage

// Creation

var my_map = new HashMap();

// Insertion

var a_key = {};
var a_value = {struct: "structA"};
var b_key = {};
var b_value = {struct: "structB"};
var c_key = {};
var c_value = {struct: "structC"};

my_map.put(a_key, a_value);
my_map.put(b_key, b_value);
var prev_b = my_map.put(b_key, c_value);

// Retrieval

if(my_map.get(a_key) !== a_value){
  throw("fail1")
}
if(my_map.get(b_key) !== c_value){
  throw("fail2")
}
if(prev_b !== b_value){
  throw("fail3")
}

// Deletion

var a_existed = my_map.del(a_key);
var c_existed = my_map.del(c_key);
var a2_existed = my_map.del(a_key);

if(a_existed !== true){
  throw("fail4")
}
if(c_existed !== false){
  throw("fail5")
}
if(a2_existed !== false){
  throw("fail6")
}

在ECMAScript 6中,你可以使用WeakMap。

例子:

var wm1 = new WeakMap(),
    wm2 = new WeakMap(),
    wm3 = new WeakMap();
var o1 = {},
    o2 = function(){},
    o3 = window;

wm1.set(o1, 37);
wm1.set(o2, "azerty");
wm2.set(o1, o2); // A value can be anything, including an object or a function
wm2.set(o3, undefined);
wm2.set(wm1, wm2); // Keys and values can be any objects. Even WeakMaps!

wm1.get(o2); // "azerty"
wm2.get(o2); // Undefined, because there is no value for o2 on wm2
wm2.get(o3); // Undefined, because that is the set value

wm1.has(o2); // True
wm2.has(o2); // False
wm2.has(o3); // True (even if the value itself is 'undefined')

wm3.set(o1, 37);
wm3.get(o1); // 37
wm3.clear();
wm3.get(o1); // Undefined, because wm3 was cleared and there is no value for o1 anymore

wm1.has(o1);   // True
wm1.delete(o1);
wm1.has(o1);   // False

But:

因为引用是弱的,WeakMap键是不可枚举的(也就是说,没有方法给你一个键的列表)。

这是我的另一个地图实现。使用randomizer, 'generics'和'iterator' =)

var HashMap = function (TKey, TValue) {
    var db = [];
    var keyType, valueType;

    (function () {
        keyType = TKey;
        valueType = TValue;
    })();

    var getIndexOfKey = function (key) {
        if (typeof key !== keyType)
            throw new Error('Type of key should be ' + keyType);
        for (var i = 0; i < db.length; i++) {
            if (db[i][0] == key)
                return i;
        }
        return -1;
    }

    this.add = function (key, value) {
        if (typeof key !== keyType) {
            throw new Error('Type of key should be ' + keyType);
        } else if (typeof value !== valueType) {
            throw new Error('Type of value should be ' + valueType);
        }
        var index = getIndexOfKey(key);
        if (index === -1)
            db.push([key, value]);
        else
            db[index][1] = value;
        return this;
    }

    this.get = function (key) {
        if (typeof key !== keyType || db.length === 0)
            return null;
        for (var i = 0; i < db.length; i++) {
            if (db[i][0] == key)
                return db[i][1];
        }
        return null;
    }

    this.size = function () {
        return db.length;
    }

    this.keys = function () {
        if (db.length === 0)
            return [];
        var result = [];
        for (var i = 0; i < db.length; i++) {
            result.push(db[i][0]);
        }
        return result;
    }

    this.values = function () {
        if (db.length === 0)
            return [];
        var result = [];
        for (var i = 0; i < db.length; i++) {
            result.push(db[i][1]);
        }
        return result;
    }

    this.randomize = function () {
        if (db.length === 0)
            return this;
        var currentIndex = db.length, temporaryValue, randomIndex;
        while (0 !== currentIndex) {
            randomIndex = Math.floor(Math.random() * currentIndex);
            currentIndex--;
            temporaryValue = db[currentIndex];
            db[currentIndex] = db[randomIndex];
            db[randomIndex] = temporaryValue;
        }
        return this;
    }

    this.iterate = function (callback) {
        if (db.length === 0)
            return false;
        for (var i = 0; i < db.length; i++) {
            callback(db[i][0], db[i][1]);
        }
        return true;
    }
}

例子:

var a = new HashMap("string", "number");
a.add('test', 1132)
 .add('test14', 666)
 .add('1421test14', 12312666)
 .iterate(function (key, value) {console.log('a['+key+']='+value)});
/*
a[test]=1132
a[test14]=666
a[1421test14]=12312666 
*/
a.randomize();
/*
a[1421test14]=12312666
a[test]=1132
a[test14]=666
*/

下面是一种使用类似Java映射的简单而方便的方法:

var map = {
              'map_name_1': map_value_1,
              'map_name_2': map_value_2,
              'map_name_3': map_value_3,
              'map_name_4': map_value_4
          }

为了得到值:

alert(map['map_name_1']);    // Gives the value of map_value_1

... etc. ...

根据ECMAScript 2015 (ES6),标准JavaScript有一个Map实现。更多信息可以在这里找到。

基本用法:

var myMap = new Map();
var keyString = "a string",
    keyObj = {},
    keyFunc = function () {};

// Setting the values
myMap.set(keyString, "value associated with 'a string'");
myMap.set(keyObj, "value associated with keyObj");
myMap.set(keyFunc, "value associated with keyFunc");

myMap.size; // 3

// Getting the values
myMap.get(keyString);    // "value associated with 'a string'"
myMap.get(keyObj);       // "value associated with keyObj"
myMap.get(keyFunc);      // "value associated with keyFunc"