我使用AJAX获取了以下对象,并将它们存储在数组中:

var homes = [
    {
        "h_id": "3",
        "city": "Dallas",
        "state": "TX",
        "zip": "75201",
        "price": "162500"
    }, {
        "h_id": "4",
        "city": "Bevery Hills",
        "state": "CA",
        "zip": "90210",
        "price": "319250"
    }, {
        "h_id": "5",
        "city": "New York",
        "state": "NY",
        "zip": "00010",
        "price": "962500"
    }
];

如何创建一个函数,仅使用JavaScript按price属性按升序或降序对对象进行排序?


当前回答

这里是以上所有答案的顶点。

Fiddle验证:http://jsfiddle.net/bobberino/4qqk3/

var sortOn = function (arr, prop, reverse, numeric) {

    // Ensure there's a property
    if (!prop || !arr) {
        return arr
    }

    // Set up sort function
    var sort_by = function (field, rev, primer) {

        // Return the required a,b function
        return function (a, b) {

            // Reset a, b to the field
            a = primer(a[field]), b = primer(b[field]);

            // Do actual sorting, reverse as needed
            return ((a < b) ? -1 : ((a > b) ? 1 : 0)) * (rev ? -1 : 1);
        }

    }

    // Distinguish between numeric and string to prevent 100's from coming before smaller
    // e.g.
    // 1
    // 20
    // 3
    // 4000
    // 50

    if (numeric) {

        // Do sort "in place" with sort_by function
        arr.sort(sort_by(prop, reverse, function (a) {

            // - Force value to a string.
            // - Replace any non numeric characters.
            // - Parse as float to allow 0.02 values.
            return parseFloat(String(a).replace(/[^0-9.-]+/g, ''));

        }));
    } else {

        // Do sort "in place" with sort_by function
        arr.sort(sort_by(prop, reverse, function (a) {

            // - Force value to string.
            return String(a).toUpperCase();

        }));
    }


}

其他回答

homes.sort(function(a, b){
  var nameA=a.prices.toLowerCase(), nameB=b.prices.toLowerCase()
  if (nameA < nameB) //sort string ascending
    return -1 
  if (nameA > nameB)
    return 1
  return 0 //default return value (no sorting)
})

您可以将JavaScript排序方法与回调函数一起使用:

function compareASC(homeA, homeB)
{
    return parseFloat(homeA.price) - parseFloat(homeB.price);
}

function compareDESC(homeA, homeB)
{
    return parseFloat(homeB.price) - parseFloat(homeA.price);
}

// Sort ASC
homes.sort(compareASC);

// Sort DESC
homes.sort(compareDESC);

这可以通过一个简单的单行值of()排序函数实现。运行下面的代码片段以查看演示。

var家=[{“h_id”:“3”,“城市”:“达拉斯”,“状态”:“TX”,“zip”:“75201”,“价格”:“162500”}, {“h_id”:“4”,“城市”:“贝弗利山”,“状态”:“CA”,“zip”:“90210”,“price”:“319250”}, {“h_id”:“5”,“城市”:“纽约”,“州”:“NY”,“zip”:“00010”,“价格”:“962500”}];console.log(“要首先对降序/最高排序,请使用运算符'<'”);homes.sort(函数(a,b){return a.price.valueOf()<b.price.vvalueOf(;});console.log(homes);console.log(“要首先对升序/最低排序,请使用运算符'>'”);homes.sort(函数(a,b){return a.price.valueOf()>b.price.vvalueOf(;});console.log(homes);

仅对于元素值的普通数组:

function sortArrayOfElements(arrayToSort) {
    function compareElements(a, b) {
        if (a < b)
            return -1;
        if (a > b)
            return 1;
        return 0;
    }

    return arrayToSort.sort(compareElements);
}

e.g. 1:
var array1 = [1,2,545,676,64,2,24]
output : [1, 2, 2, 24, 64, 545, 676]

var array2 = ["v","a",545,676,64,2,"24"]
output: ["a", "v", 2, "24", 64, 545, 676]

对于对象数组:

function sortArrayOfObjects(arrayToSort, key) {
    function compareObjects(a, b) {
        if (a[key] < b[key])
            return -1;
        if (a[key] > b[key])
            return 1;
        return 0;
    }

    return arrayToSort.sort(compareObjects);
}

e.g. 1: var array1= [{"name": "User4", "value": 4},{"name": "User3", "value": 3},{"name": "User2", "value": 2}]

output : [{"name": "User2", "value": 2},{"name": "User3", "value": 3},{"name": "User4", "value": 4}]

要对其进行排序,需要创建一个接受两个参数的比较器函数。然后用比较器函数调用排序函数,如下所示:

// a and b are object elements of your array
function mycomparator(a,b) {
  return parseInt(a.price, 10) - parseInt(b.price, 10);
}
homes.sort(mycomparator);

如果要按升序排序,请切换负号两边的表达式。