按数组中的对象分组最有效的方法是什么?

例如,给定此对象数组:

[ 
    { Phase: "Phase 1", Step: "Step 1", Task: "Task 1", Value: "5" },
    { Phase: "Phase 1", Step: "Step 1", Task: "Task 2", Value: "10" },
    { Phase: "Phase 1", Step: "Step 2", Task: "Task 1", Value: "15" },
    { Phase: "Phase 1", Step: "Step 2", Task: "Task 2", Value: "20" },
    { Phase: "Phase 2", Step: "Step 1", Task: "Task 1", Value: "25" },
    { Phase: "Phase 2", Step: "Step 1", Task: "Task 2", Value: "30" },
    { Phase: "Phase 2", Step: "Step 2", Task: "Task 1", Value: "35" },
    { Phase: "Phase 2", Step: "Step 2", Task: "Task 2", Value: "40" }
]

我正在表格中显示这些信息。我想通过不同的方法进行分组,但我想对值求和。

我将Undercore.js用于其groupby函数,这很有用,但并不能完成全部任务,因为我不希望它们“拆分”,而是“合并”,更像SQL groupby方法。

我要找的是能够合计特定值(如果需要)。

因此,如果我按阶段分组,我希望收到:

[
    { Phase: "Phase 1", Value: 50 },
    { Phase: "Phase 2", Value: 130 }
]

如果我组了阶段/步骤,我会收到:

[
    { Phase: "Phase 1", Step: "Step 1", Value: 15 },
    { Phase: "Phase 1", Step: "Step 2", Value: 35 },
    { Phase: "Phase 2", Step: "Step 1", Value: 55 },
    { Phase: "Phase 2", Step: "Step 2", Value: 75 }
]

是否有一个有用的脚本,或者我应该坚持使用Undercore.js,然后遍历生成的对象,自己计算总数?


当前回答

常量动物=[{type:'狗',品种:“水坑”},{type:'狗',品种:“拉布拉多”},{类型:'cat',品种:“暹罗”},{type:'狗',品种:“法国斗牛犬”},{类型:'cat',品种:'泥'}];var groupBy=(arr,prop)=>{return arr.reduce((objs,obj)=>{const key=obj[prop];if(键){让fi=objs.findIndex(x=>x.key==key);如果(fi>=0){objs[fi].values=[…objs[fi].values,obj];}其他{对象.推送({key:键,值:[obj]})}}返回对象;}, []);}console.log(groupBy(动物,“类型”))

其他回答

var newArr = data.reduce((acc, cur) => {
    const existType = acc.find(a => a.Phase === cur.Phase);
    if (existType) {
        existType.Value += +cur.Value;
        return acc;
    }

    acc.push({
        Phase: cur.Phase,
        Value: +cur.Value
    });
    return acc;
}, []);

您可以在数组上使用forEach并构造一组新的项。以下是如何使用FlowType注释实现这一点

// @flow

export class Group<T> {
  tag: number
  items: Array<T>

  constructor() {
    this.items = []
  }
}

const groupBy = (items: Array<T>, map: (T) => number) => {
  const groups = []

  let currentGroup = null

  items.forEach((item) => {
    const tag = map(item)

    if (currentGroup && currentGroup.tag === tag) {
      currentGroup.items.push(item)
    } else {
      const group = new Group<T>()
      group.tag = tag
      group.items.push(item)
      groups.push(group)

      currentGroup = group
    }
  })

  return groups
}

export default groupBy

玩笑测试可以是这样的

// @flow

import groupBy from './groupBy'

test('groupBy', () => {
  const items = [
    { name: 'January', month: 0 },
    { name: 'February', month: 1 },
    { name: 'February 2', month: 1 }
  ]

  const groups = groupBy(items, (item) => {
    return item.month
  })

  expect(groups.length).toBe(2)
  expect(groups[1].items[1].name).toBe('February 2')
})

如果您需要通过以下方式进行多组:


    const populate = (entireObj, keys, item) => {
    let keysClone = [...keys],
        currentKey = keysClone.shift();

    if (keysClone.length > 0) {
        entireObj[item[currentKey]] = entireObj[item[currentKey]] || {}
        populate(entireObj[item[currentKey]], keysClone, item);
    } else {
        (entireObj[item[currentKey]] = entireObj[item[currentKey]] || []).push(item);
    }
}

export const groupBy = (list, key) => {
    return list.reduce(function (rv, x) {

        if (typeof key === 'string') (rv[x[key]] = rv[x[key]] || []).push(x);

        if (typeof key === 'object' && key.length) populate(rv, key, x);

        return rv;

    }, {});
}

const myPets = [
    {name: 'yaya', type: 'cat', color: 'gray'},
    {name: 'bingbang', type: 'cat', color: 'sliver'},
    {name: 'junior-bingbang', type: 'cat', color: 'sliver'},
    {name: 'jindou', type: 'cat', color: 'golden'},
    {name: 'dahuzi', type: 'dog', color: 'brown'},
];

// run 
groupBy(myPets, ['type', 'color']));

// you will get object like: 

const afterGroupBy = {
    "cat": {
        "gray": [
            {
                "name": "yaya",
                "type": "cat",
                "color": "gray"
            }
        ],
        "sliver": [
            {
                "name": "bingbang",
                "type": "cat",
                "color": "sliver"
            },
            {
                "name": "junior-bingbang",
                "type": "cat",
                "color": "sliver"
            }
        ],
        "golden": [
            {
                "name": "jindou",
                "type": "cat",
                "color": "golden"
            }
        ]
    },
    "dog": {
        "brown": [
            {
                "name": "dahuzi",
                "type": "dog",
                "color": "brown"
            }
        ]
    }
};

下面的函数允许对任意字段进行groupBy(和求和值-OP需要的)。在解决方案中,我们定义cmp函数来根据分组字段比较两个对象。在设w=。。。我们创建子集对象x字段的副本。在y[sumBy]=+y[sumBy]+(+x[sumBy])中,我们使用“+”将字符串转换为数字。

function groupBy(data, fields, sumBy='Value') {
  let r=[], cmp= (x,y) => fields.reduce((a,b)=> a && x[b]==y[b], true);
  data.forEach(x=> {
    let y=r.find(z=>cmp(x,z));
    let w= [...fields,sumBy].reduce((a,b) => (a[b]=x[b],a), {})
    y ? y[sumBy]=+y[sumBy]+(+x[sumBy]) : r.push(w);
  });
  return r;
}

常量d=[{阶段:“阶段1”,步骤:“步骤1”,任务:“任务1”,值:“5”},{阶段:“阶段1”,步骤:“步骤1”,任务:“任务2”,值:“10”},{阶段:“阶段1”,步骤:“步骤2”,任务:“任务1”,值:“15”},{阶段:“阶段1”,步骤:“步骤2”,任务:“任务2”,值:“20”},{阶段:“阶段2”,步骤:“步骤1”,任务:“任务1”,值:“25”},{阶段:“阶段2”,步骤:“步骤1”,任务:“任务2”,值:“30”},{阶段:“阶段2”,步骤:“步骤2”,任务:“任务1”,值:“35”},{阶段:“阶段2”,步骤:“步骤2”,任务:“任务2”,值:“40”}];函数groupBy(数据,字段,sumBy='Value'){设r=[],cmp=(x,y)=>fields.reduce((a,b)=>a&&x[b]==y[b],true);data.forEach(x=>{设y=r.find(z=>cmp(x,z));设w=[…fields,sumBy].reduce((a,b)=>(a[b]=x[b],a),{})yy[sumBy]=+y[sumBy]+(+x[sumBy]):r.push(w);});返回r;}//测试let p=(t,o)=>console.log(t,JSON.stringify(o));console.log('GROUP BY:');p(“相”,组By(d,[“相”]));p(“步骤”,组By(d,[“步骤”]));p(“阶段-步骤”,组By(d,[“阶段”,“步骤”]));p(“阶段任务”,groupBy(d,[“阶段”,“任务”]));p(“步骤任务”,groupBy(d,[“步骤”,“任务”]));p(“阶段-步骤-任务”,groupBy(d,[“阶段”,“步骤”,“任务”]));

此解决方案采用任意函数(而不是键),因此比上述解决方案更灵活,并允许箭头函数,这与LINQ中使用的lambda表达式类似:

Array.prototype.groupBy = function (funcProp) {
    return this.reduce(function (acc, val) {
        (acc[funcProp(val)] = acc[funcProp(val)] || []).push(val);
        return acc;
    }, {});
};

注意:是否要扩展Array的原型取决于您。

大多数浏览器支持的示例:

[{a:1,b:"b"},{a:1,c:"c"},{a:2,d:"d"}].groupBy(function(c){return c.a;})

使用箭头函数(ES6)的示例:

[{a:1,b:"b"},{a:1,c:"c"},{a:2,d:"d"}].groupBy(c=>c.a)

以上两个示例都返回:

{
  "1": [{"a": 1, "b": "b"}, {"a": 1, "c": "c"}],
  "2": [{"a": 2, "d": "d"}]
}