Android上的LocationManager API似乎对一个只需要偶尔粗略估计用户位置的应用程序来说有点麻烦。

我正在开发的应用程序本身并不是一个定位应用程序,但它确实需要获取用户的位置,以便显示附近企业的列表。它不需要担心用户是否在移动或类似的事情。

以下是我想做的:

向用户显示附近位置的列表。预加载用户的位置,以便在“活动X”中需要它时,它将可用。我并不特别关心更新的准确性或频率。只要不太远,只要抓住一个位置就足够了。也许如果我想变得更漂亮,我会每隔几分钟左右更新一次位置,但这不是一个很大的优先事项。适用于任何具有GPS或网络位置提供商的设备。

这似乎并不难,但在我看来,我必须组建两个不同的位置提供商(GPS和NETWORK),并管理每个提供商的生命周期。不仅如此,我还必须在多个活动中复制相同的代码以满足#2。过去,我曾尝试使用getBestProvider()将解决方案简化为仅使用一个位置提供程序,但这似乎只提供了最好的“理论”提供程序,而不是实际会为您提供最佳结果的提供程序。

有没有更简单的方法来实现这一点?


当前回答

这里有点晚了,但在这种情况下,我会使用谷歌地图API,并使用谷歌地图的纬度和经度API标记附近的位置。另外,如果你能在地图上显示他/她的位置,用户体验会更好。无需担心用户位置的更新或使用android api搜索。让谷歌地图为您处理内部内容。

@emmby可能已经在他的应用程序中解决了这个问题,但为了将来的参考,我向其他开发人员推荐的是查看谷歌地图API中的位置特定内容。

编辑:在谷歌地图中显示用户位置的链接

其他回答

其中一些人现在已经过时了,所以我回答说,

FusedLocationProviderClient fusedLocationProviderClient; //set global variable
Location currentLocation;//set global var
private boolean mLocationPermissionGranted; //set global var
 fusedLocationProviderClient = LocationServices.getFusedLocationProviderClient(getContext()); //write this oncreate
        fetchLastLocation();  // call the funct for current location
//here is the function
private void fetchLastLocation() {

    if (ActivityCompat.checkSelfPermission(getContext(), Manifest.permission.ACCESS_FINE_LOCATION)
            != PackageManager.PERMISSION_GRANTED) {

        ActivityCompat.requestPermissions(getActivity(),new String[]{
                Manifest.permission.ACCESS_FINE_LOCATION},REQUEST_CODE);
        return;
    }else {
        mLocationPermissionGranted=true;
    }
    Task<Location> task= fusedLocationProviderClient.getLastLocation();
    task.addOnSuccessListener(new OnSuccessListener<Location>() {
        @Override
        public void onSuccess(Location location) {
            if(location != null){
                currentLocation =location;
               Toast.makeText(getContext(), currentLocation.getLatitude()+"" +
                        " "+currentLocation.getLongitude(), 
                   Toast.LENGTH_SHORT).show();
//if you want to show in google maps
                SupportMapFragment supportMapFragment =(SupportMapFragment)
                        getChildFragmentManager().findFragmentById(R.id.map);
                supportMapFragment.getMapAsync(MapsFragment.this);
            }
        }
    });


}

对@Fedor解决方案的改进。我们可以使用位置管理器的requestSingleUpdate方法,而不是使用“0”时间间隔和“0”距离请求位置。更新的代码(kotlin版本)

import android.annotation.SuppressLint
import android.content.Context
import android.location.Criteria
import android.location.Location
import android.location.LocationListener
import android.location.LocationManager
import android.os.Bundle
import java.util.*

@SuppressLint("MissingPermission")
class AppLocationProvider {

  private lateinit var timer: Timer
  private var locationManager: LocationManager? = null
  private lateinit var locationCallBack: LocationCallBack
  private var gpsEnabled = false
  private var networkEnabled = false

  private var locationListener: LocationListener = object : LocationListener {

    override fun onLocationChanged(location: Location) {
      timer.cancel()
      locationCallBack.locationResult(location)
    }

    override fun onProviderDisabled(provider: String) {}
    override fun onProviderEnabled(provider: String) {}
    override fun onStatusChanged(provider: String, status: Int, extras: Bundle) {}
  }

  fun getLocation(context : Context, callBack: LocationCallBack): Boolean {
    locationCallBack = callBack
    if (locationManager == null)
      locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager?

    //exceptions will be thrown if provider is not permitted.
    try {
      gpsEnabled = locationManager!!.isProviderEnabled(LocationManager.GPS_PROVIDER)
    } catch (ex: Exception) {
      ex.printStackTrace()
    }

    try {
      networkEnabled = locationManager!!.isProviderEnabled(LocationManager.NETWORK_PROVIDER)
    } catch (ex: Exception) {
      ex.printStackTrace()
    }

    //don't start listeners if no provider is enabled
    if (!gpsEnabled && !networkEnabled)
      return false

    val criteria = Criteria()
    if (gpsEnabled) {
      criteria.accuracy = Criteria.ACCURACY_FINE
    } else {
      criteria.accuracy = Criteria.ACCURACY_COARSE
    }
    locationManager!!.requestSingleUpdate(criteria, locationListener, null)

    timer = Timer()
    timer.schedule(GetLastKnownLocation(), 5000)
    return true
  }

  inner class GetLastKnownLocation : TimerTask() {

    override fun run() {
      locationManager!!.removeUpdates(locationListener)

      var netLoc: Location? = null
      var gpsLoc: Location? = null

      if (gpsEnabled)
        gpsLoc = locationManager!!.getLastKnownLocation(LocationManager.GPS_PROVIDER)
      if (networkEnabled)
        netLoc = locationManager!!.getLastKnownLocation(LocationManager.NETWORK_PROVIDER)

      //check which value use the latest one
      if (gpsLoc != null && netLoc != null) {
        if (gpsLoc.time > netLoc.time)
          locationCallBack.locationResult(gpsLoc)
        else
          locationCallBack.locationResult(netLoc)
        return
      }

      if (gpsLoc != null) {
        locationCallBack.locationResult(gpsLoc)
        return
      }
      if (netLoc != null) {
        locationCallBack.locationResult(netLoc)
        return
      }
      locationCallBack.locationResult(null)
    }
  }

  interface LocationCallBack {
    fun locationResult(location: Location?)
  }
}

要获取位置,只需调用getLocation方法-

AppLocationProvider().getLocation(context, object : AppLocationProvider.LocationCallBack {
  override fun locationResult(location: Location?) {
    // use location, this might get called in a different thread if a location is a last known location. In that case, you can post location on main thread
  }
})

注:在调用getLocation方法之前,必须授予所需的位置权限。

使用以下代码,它将提供可用的最佳提供商:

String locCtx = Context.LOCATION_SERVICE; 

LocationManager locationMgr = (LocationManager) ctx.getSystemService(locCtx);

Criteria criteria  = new Criteria();
criteria.setAccuracy(Criteria.ACCURACY_FINE);
criteria.setAltitudeRequired(false);
criteria.setBearingRequired(false);
criteria.setCostAllowed(true);
criteria.setPowerRequirement(Criteria.POWER_LOW);

String provider = locationMgr.getBestProvider(criteria, true);

System.out.println("Best Available provider::::"+provider);

你可以一直使用LocationManager.getLastKnownLocation(),但就像它说的那样,它可能已经过时了。

获取一般位置的一个简单方法是注册网络(通常很快)。

LocationManager locationManager = (LocationManager) this.getSystemService(Context.LOCATION_SERVICE);
locationManager.requestLocationUpdates(
     LocationManager.NETWORK_PROVIDER, 1000, 1000, this);

然后做

locationManager.removeUpdates(this);

在侦听器的onLocationChanged()方法中。

public static Location getBestLocation(Context ctxt) {
    Location gpslocation = getLocationByProvider(
        LocationManager.GPS_PROVIDER, ctxt);
    Location networkLocation = getLocationByProvider(
        LocationManager.NETWORK_PROVIDER, ctxt);
    Location fetchedlocation = null;
    // if we have only one location available, the choice is easy
    if (gpslocation != null) {
        Log.i("New Location Receiver", "GPS Location available.");
        fetchedlocation = gpslocation;
    } else {
        Log.i("New Location Receiver",
            "No GPS Location available. Fetching Network location lat="
                + networkLocation.getLatitude() + " lon ="
                + networkLocation.getLongitude());
        fetchedlocation = networkLocation;
    }
    return fetchedlocation;
}

/**
 * get the last known location from a specific provider (network/gps)
 */
private static Location getLocationByProvider(String provider, Context ctxt) {
    Location location = null;
    // if (!isProviderSupported(provider)) {
    // return null;
    // }
    LocationManager locationManager = (LocationManager) ctxt
            .getSystemService(Context.LOCATION_SERVICE);
    try {
        if (locationManager.isProviderEnabled(provider)) {
            location = locationManager.getLastKnownLocation(provider);
        }
    } catch (IllegalArgumentException e) {
        Log.i("New Location Receiver", "Cannot access Provider " + provider);
    }
    return location;
}