这将给你当月的最后一天。

注:在ios设备上包含时间。 # gshoanganh

var date = new Date();
console.log(new Date(date.getFullYear(), date.getMonth() + 1, 0, 23, 59, 59));

这对我很有用。 将提供给定年份和月份的最后一天:

var d = new Date(2012,02,0);
var n = d.getDate();
alert(n);

试试这个:

function _getEndOfMonth(time_stamp) {
    let time = new Date(time_stamp * 1000);
    let month = time.getMonth() + 1;
    let year = time.getFullYear();
    let day = time.getDate();
    switch (month) {
        case 1:
        case 3:
        case 5:
        case 7:
        case 8:
        case 10:
        case 12:
            day = 31;
            break;
        case 4:
        case 6:
        case 9:
        case 11:
            day = 30;
            break;
        case 2:
            if (_leapyear(year))
                day = 29;
            else
                day = 28;
            break
    }
    let m = moment(`${year}-${month}-${day}`, 'YYYY-MM-DD')
    return m.unix() + constants.DAY - 1;
}

function _leapyear(year) {
    return (year % 100 === 0) ? (year % 400 === 0) : (year % 4 === 0);
}

你可以通过下面的代码获取当月的第一个和最后一个日期:

var dateNow = new Date();  
var firstDate = new Date(dateNow.getFullYear(), dateNow.getMonth(), 1);  
var lastDate = new Date(dateNow.getFullYear(), dateNow.getMonth() + 1, 0);

或者如果你想用自定义格式格式化日期，那么你可以使用moment js

var dateNow= new Date();  
var firstDate=moment(new Date(dateNow.getFullYear(),dateNow.getMonth(), 1)).format("DD-MM-YYYY");  
var currentDate = moment(new Date()).format("DD-MM-YYYY"); //to  get the current date var lastDate = moment(new
 Date(dateNow.getFullYear(), dateNow.getMonth() + 1, 0)).format("DD-MM-YYYY"); //month last date

const today = new Date();

let beginDate = new Date();

let endDate = new Date();

// fist date of montg

beginDate = new Date(

  `${today.getFullYear()}-${today.getMonth() + 1}-01 00:00:00`

);

// end date of month 

// set next Month first Date

endDate = new Date(

  `${today.getFullYear()}-${today.getMonth() + 2}-01 :23:59:59`

);

// deducting 1 day

endDate.setDate(0);

对lebreeze提供的解决方案稍加修改:

function daysInMonth(iMonth, iYear)
{
    return new Date(iYear, iMonth, 0).getDate();
}