第一个答案的简单破解

var getLocation = function(href=window.location.href) {
    var l = document.createElement("a");
    l.href = href;
    return l;
};

即使没有参数，也可以使用它来计算当前的主机名 getLocation()。Hostname将给出当前主机名

这不会解析查询和散列，但除此之外它工作得很好。

const getURIParts = (url) => { const matches = url.match(/^(\w+?:\/\/)?([\w-\.]+(?=\/?))?:?(\d*)?([^:]*)/) return { scheme: matches ? matches[1] : undefined, host: matches ? matches[2] : '', port: matches ? matches[3] : undefined, pathname: matches ? matches[4] : '' } } console.log(getURIParts("")) console.log(getURIParts("http://localhost/bla")) console.log(getURIParts("https://api.spotify.com/")) console.log(getURIParts("https://api.spotify.com")) console.log(getURIParts("wss://wss.slack.com/link/?ticket=1234-5678")) console.log(getURIParts("localhost")) console.log(getURIParts("localhost/bla")) console.log(getURIParts("localhost/")) console.log(getURIParts("api.spotify.com/bla/two")) console.log(getURIParts("api.spotify.com:8000/bla/two")) console.log(getURIParts("https://api.spotify.com:8800/")) console.log(getURIParts("/mp3-preview/f504e6b8e037771318656394f532dede4f9bcaea"))

以下是我从https://gist.github.com/1847816复制的一个版本，但经过重写，以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长，因此将有限数量的值复制到结果将有助于简化结果。

/**
 * See: https://gist.github.com/1847816
 * Parse a URI, returning an object similar to Location
 * Usage: var uri = parseUri("hello?search#hash")
 */
function parseUri(url) {

  var result = {};

  var anchor = document.createElement('a');
  anchor.href = url;

  var keys = 'protocol hostname host pathname port search hash href'.split(' ');
  for (var keyIndex in keys) {
    var currentKey = keys[keyIndex]; 
    result[currentKey] = anchor[currentKey];
  }

  result.toString = function() { return anchor.href; };
  result.requestUri = result.pathname + result.search;  
  return result;

}

那么简单的正则表达式呢?

url = "http://www.example.com/path/to/somwhere";
urlParts = /^(?:\w+\:\/\/)?([^\/]+)(.*)$/.exec(url);
hostname = urlParts[1]; // www.example.com
path = urlParts[2]; // /path/to/somwhere

怎么样?

'https://stackoverflow.com/questions/736513/how-do-i-parse-a-url-into-hostname-and-path-in-javascript'.split('//').pop() .split('/')[0]

结果:

“stackoverflow.com”

只需使用url.js库(用于web和node.js)。

https://github.com/websanova/js-url

url: http://example.com?param=test#param=again

url('?param'); // test
url('#param'); // again
url('protocol'); // http
url('port'); // 80
url('domain'); // example.com
url('tld'); // com

etc...