我如何在Swift中生成一个随机的字母数字字符串?
当前回答
迅速:
let randomString = NSUUID().uuidString
其他回答
Swift 2.2版本
// based on https://gist.github.com/samuel-mellert/20b3c99dec168255a046
// which is based on https://gist.github.com/szhernovoy/276e69eb90a0de84dd90
// Updated to work on Swift 2.2
func randomString(length: Int) -> String {
let charactersString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
let charactersArray : [Character] = Array(charactersString.characters)
var string = ""
for _ in 0..<length {
string.append(charactersArray[Int(arc4random()) % charactersArray.count])
}
return string
}
基本上调用这个方法,它将生成一个随机字符串,长度为传递给函数的整数。要更改可能的字符,只需编辑charactersString字符串。也支持unicode字符。
https://gist.github.com/gingofthesouth/54bea667b28a815b2fe33a4da986e327
SwifterSwift有这个实现
/// SwifterSwift: Create a new random string of given length.
///
/// String(randomOfLength: 10) -> "gY8r3MHvlQ"
///
/// - Parameter length: number of characters in string.
init(randomOfLength length: Int) {
guard length > 0 else {
self.init()
return
}
let base = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
var randomString = ""
for _ in 1...length {
randomString.append(base.randomElement()!)
}
self = randomString
}
我做了一些改变,并使用这个实现
static func random(randomOfLength length: Int) -> String {
guard length > 0 else { return "" }
let base = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
var randomString = ""
for _ in 1...length {
guard let randomCharacter = base.randomElement() else { continue }
randomString.append(randomCharacter)
}
return randomString
}
来自任何字符集的纯Swift随机字符串。
用法:CharacterSet.alphanumerics。randomString(长度:100)
extension CharacterSet {
/// extracting characters
/// https://stackoverflow.com/a/52133647/1033581
public func characters() -> [Character] {
return codePoints().compactMap { UnicodeScalar($0) }.map { Character($0) }
}
public func codePoints() -> [Int] {
var result: [Int] = []
var plane = 0
for (i, w) in bitmapRepresentation.enumerated() {
let k = i % 8193
if k == 8192 {
plane = Int(w) << 13
continue
}
let base = (plane + k) << 3
for j in 0 ..< 8 where w & 1 << j != 0 {
result.append(base + j)
}
}
return result
}
/// building random string of desired length
/// https://stackoverflow.com/a/42895178/1033581
public func randomString(length: Int) -> String {
let charArray = characters()
let charArrayCount = UInt32(charArray.count)
var randomString = ""
for _ in 0 ..< length {
randomString += String(charArray[Int(arc4random_uniform(charArrayCount))])
}
return randomString
}
}
characters()函数是我所知道的最快的实现。
斯威夫特5.0
// Generating Random String
func randomString(length: Int) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
return String((0..<length).map{ _ in letters.randomElement()! })
}
// Calling to string
label.text = randomString(length: 3)
我对这个问题的更快速的回答是:
func randomAlphanumericString(length: Int) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789".characters
let lettersLength = UInt32(letters.count)
let randomCharacters = (0..<length).map { i -> String in
let offset = Int(arc4random_uniform(lettersLength))
let c = letters[letters.startIndex.advancedBy(offset)]
return String(c)
}
return randomCharacters.joinWithSeparator("")
}