建立在@user839791的答案上，但我又添加了一些东西。

@echo off
rem --Set variable below--
set var=condition

rem --Uncomment below line to display contents of variable--
::echo The variable is %var%

rem --Change condition to desired string below--
ECHO.%var%| FIND /I "condition">Nul && (  
  rem --Occurs if the string is found--
  Echo.Variable is "condition"
  color C
  pause
) || (
  rem --Occurs if the string isn't found--
  Echo.Variable is not "condition"
  color A
  pause
)

更好的答案是:

set "i=hello " world"
set i|find """" >nul && echo contains || echo not_contains

是的，我们可以在String中找到subString:

echo.%data% | FINDSTR /I "POS">Nul && (SET var=POS) || (SET noVar="variable not found")

echo.%data% | FINDSTR /I "TD1">Nul && (SET var=TD1) || (SET noVar="variable not found")

GOTO %var%

:POS   
echo processes inside POS  
GOTO END

:TD1   
echo processes inside TD1

:END

我给出这个答案可能有点晚了，但接受的答案只适用于检查“硬编码字符串”是否是搜索字符串的一部分。

对于动态搜索，你必须这样做:

SET searchString=abcd1234
SET key=cd123

CALL SET keyRemoved=%%searchString:%key%=%%

IF NOT "x%keyRemoved%"=="x%searchString%" (
    ECHO Contains.
)

注意:您可以将这两个变量作为参数。

ECHO %String%| FINDSTR /C:"%Substring%" && (Instructions)

您可以将源字符串输送到findstr，并检查ERRORLEVEL的值，以查看是否找到了模式字符串。值为0表示成功，并且找到了模式。这里有一个例子:

::
: Y.CMD - Test if pattern in string
: P1 - the pattern
: P2 - the string to check
::
@echo off

echo.%2 | findstr /C:"%1" 1>nul

if errorlevel 1 (
  echo. got one - pattern not found
) ELSE (
  echo. got zero - found pattern
)

当在CMD.EXE中运行时，我们得到:

C:\DemoDev>y pqrs "abc def pqr 123"
 got one - pattern not found

C:\DemoDev>y pqr "abc def pqr 123" 
 got zero - found pattern