我想在一个特定的日期上加上一天。我该怎么做呢?

Date dt = new Date();

现在我想在这个日期上加一天。


当前回答

Java 1.8版本对数据时间API进行了很好的更新。

下面是一段代码:

    LocalDate lastAprilDay = LocalDate.of(2014, Month.APRIL, 30);
    System.out.println("last april day: " + lastAprilDay);
    LocalDate firstMay = lastAprilDay.plusDays(1);
    System.out.println("should be first may day: " + firstMay);
    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd");
    String formatDate = formatter.format(firstMay);
    System.out.println("formatted date: " + formatDate);

输出:

last april day: 2014-04-30
should be first may day: 2014-05-01
formatted date: 01

要了解更多信息,请参阅此类的Java文档:

LocalDate DateTimeFormatter

其他回答

这将使任何日期加1

String untildate="2011-10-08";//can take any date in current format    
SimpleDateFormat dateFormat = new SimpleDateFormat( "yyyy-MM-dd" );   
Calendar cal = Calendar.getInstance();    
cal.setTime( dateFormat.parse(untildate));    
cal.add( Calendar.DATE, 1 );    
String convertedDate=dateFormat.format(cal.getTime());    
System.out.println("Date increase by one.."+convertedDate);

我更喜欢用joda来计算日期和时间,因为它可读性更好:

Date tomorrow = now().plusDays(1).toDate();

Or

endOfDay(now().plus(days(1))).toDate()
startOfDay(now().plus(days(1))).toDate()

java8时间API:

Instant now = Instant.now(); //current date
Instant after= now.plus(Duration.ofDays(300));
Date dateAfter = Date.from(after);

我发现了一个简单的方法,可以向Date对象添加任意时间

Date d = new Date(new Date().getTime() + 86400000)

地点:

86 400 000 ms = 1 Day  : 24*60*60*1000
 3 600 000 ms = 1 Hour :    60*60*1000

我将向您展示如何在Java 8中做到这一点。给你:

public class DemoDate {
    public static void main(String[] args) {
        LocalDate today = LocalDate.now();
        System.out.println("Current date: " + today);

        //add 1 day to the current date
        LocalDate date1Day = today.plus(1, ChronoUnit.DAYS);
        System.out.println("Date After 1 day : " + date1Day);
    }
}

输出:

Current date: 2016-08-15
Date After 1 day : 2016-08-16