当我试图从一个片段导航到另一个片段时,我遇到了新的Android导航架构组件的问题,我得到了这个奇怪的错误:
java.lang.IllegalArgumentException: navigation destination XXX
is unknown to this NavController
其他导航都很好,除了这个。
我使用Fragment的findNavController()函数来访问NavController。
任何帮助都将不胜感激。
当我试图从一个片段导航到另一个片段时,我遇到了新的Android导航架构组件的问题,我得到了这个奇怪的错误:
java.lang.IllegalArgumentException: navigation destination XXX
is unknown to this NavController
其他导航都很好,除了这个。
我使用Fragment的findNavController()函数来访问NavController。
任何帮助都将不胜感激。
当前回答
在思考了Ian Lake在推特上的建议后,我想出了以下方法。将NavControllerWrapper定义如下:
class NavControllerWrapper constructor(
private val navController: NavController
) {
fun navigate(
@IdRes from: Int,
@IdRes to: Int
) = navigate(
from = from,
to = to,
bundle = null
)
fun navigate(
@IdRes from: Int,
@IdRes to: Int,
bundle: Bundle?
) = navigate(
from = from,
to = to,
bundle = bundle,
navOptions = null,
navigatorExtras = null
)
fun navigate(
@IdRes from: Int,
@IdRes to: Int,
bundle: Bundle?,
navOptions: NavOptions?,
navigatorExtras: Navigator.Extras?
) {
if (navController.currentDestination?.id == from) {
navController.navigate(
to,
bundle,
navOptions,
navigatorExtras
)
}
}
fun navigate(
@IdRes from: Int,
directions: NavDirections
) {
if (navController.currentDestination?.id == from) {
navController.navigate(directions)
}
}
fun navigateUp() = navController.navigateUp()
fun popBackStack() = navController.popBackStack()
}
然后在导航代码中:
val navController = navControllerProvider.getNavController()
navController.navigate(from = R.id.main, to = R.id.action_to_detail)
其他回答
在思考了Ian Lake在推特上的建议后,我想出了以下方法。将NavControllerWrapper定义如下:
class NavControllerWrapper constructor(
private val navController: NavController
) {
fun navigate(
@IdRes from: Int,
@IdRes to: Int
) = navigate(
from = from,
to = to,
bundle = null
)
fun navigate(
@IdRes from: Int,
@IdRes to: Int,
bundle: Bundle?
) = navigate(
from = from,
to = to,
bundle = bundle,
navOptions = null,
navigatorExtras = null
)
fun navigate(
@IdRes from: Int,
@IdRes to: Int,
bundle: Bundle?,
navOptions: NavOptions?,
navigatorExtras: Navigator.Extras?
) {
if (navController.currentDestination?.id == from) {
navController.navigate(
to,
bundle,
navOptions,
navigatorExtras
)
}
}
fun navigate(
@IdRes from: Int,
directions: NavDirections
) {
if (navController.currentDestination?.id == from) {
navController.navigate(directions)
}
}
fun navigateUp() = navController.navigateUp()
fun popBackStack() = navController.popBackStack()
}
然后在导航代码中:
val navController = navControllerProvider.getNavController()
navController.navigate(from = R.id.main, to = R.id.action_to_detail)
我写了这个扩展
fun Fragment.navigateAction(action: NavDirections) {
val navController = this.findNavController()
if (navController.currentDestination?.getAction(action.actionId) == null) {
return
} else {
navController.navigate(action)
}
}
在我的情况下,我通过验证所有导航操作都正确地管理到各自的图形中,并更新了设备后退按钮的代码来解决这个问题,如下所示:
onBackPressedDispatcher.addCallback(this /* lifecycle owner */, object : OnBackPressedCallback(true) {
override fun handleOnBackPressed() {
// Back is pressed... Finishing the activity
if (navHostFragment.childFragmentManager.backStackEntryCount == 0) {
// First fragment is open, backstack is empty
finish()
} else {
navHostFragment.navController.popBackStack()
}
}
})
在我的例子中,如果用户非常非常快地点击同一个视图两次,这个崩溃就会发生。所以你需要实现某种逻辑来防止多次快速点击……这很烦人,但似乎是必要的。
你可以在这里阅读更多关于防止这种情况的内容:Android防止双击按钮
编辑3/19/2019:为了进一步澄清一点,这个崩溃不是仅仅通过“非常非常快地单击同一个视图两次”就可以完全重现的。或者,您可以使用两个手指同时单击两个(或更多)视图,其中每个视图都有自己的导航。当你有一个项目列表时,这尤其容易做到。以上关于多次点击预防的信息将处理这种情况。
编辑4/16/2020:以防你对上面的Stack Overflow帖子不太感兴趣,我包括了我自己的(Kotlin)解决方案,我已经使用了很长一段时间了。
OnSingleClickListener.kt
class OnSingleClickListener : View.OnClickListener {
private val onClickListener: View.OnClickListener
constructor(listener: View.OnClickListener) {
onClickListener = listener
}
constructor(listener: (View) -> Unit) {
onClickListener = View.OnClickListener { listener.invoke(it) }
}
override fun onClick(v: View) {
val currentTimeMillis = System.currentTimeMillis()
if (currentTimeMillis >= previousClickTimeMillis + DELAY_MILLIS) {
previousClickTimeMillis = currentTimeMillis
onClickListener.onClick(v)
}
}
companion object {
// Tweak this value as you see fit. In my personal testing this
// seems to be good, but you may want to try on some different
// devices and make sure you can't produce any crashes.
private const val DELAY_MILLIS = 200L
private var previousClickTimeMillis = 0L
}
}
ViewExt.kt
fun View.setOnSingleClickListener(l: View.OnClickListener) {
setOnClickListener(OnSingleClickListener(l))
}
fun View.setOnSingleClickListener(l: (View) -> Unit) {
setOnClickListener(OnSingleClickListener(l))
}
HomeFragment.kt
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
settingsButton.setOnSingleClickListener {
// navigation call here
}
}
在调用navigate之前检查currentDestination可能会有帮助。
例如,如果您在导航图fragmentA和fragmentB上有两个片段目的地,并且从fragmentA到fragmentB只有一个动作。当你已经在fragmentB上时,调用navigate(R.id.action_fragmentA_to_fragmentB)将导致IllegalArgumentException。因此,在导航之前,你应该总是检查currentDestination。
if (navController.currentDestination?.id == R.id.fragmentA) {
navController.navigate(R.id.action_fragmentA_to_fragmentB)
}