你可以这样过滤:

const someArray = [{ 名称:“克里斯蒂安”, 行:“2、5、10” }， ｛ 名称:“约翰”, :“96”1,19日,26日 ｝ ]; var filtered = someArray.filter((el) => el.name != "Kristian"); console.log(过滤)

这个怎么样?

$.each(someArray, function(i){
    if(someArray[i].name === 'Kristian') {
        someArray.splice(i,1);
        return false;
    }
});

虽然这可能不适合这种情况，我发现前几天，如果你不需要改变数组的大小，你也可以使用delete关键字从数组中删除一个项目。

var myArray = [1,2,3];

delete myArray[1];

console.log(myArray[1]); //undefined

console.log(myArray.length); //3 - doesn't actually shrink the array down

你可以使用array.filter()。

如。

        someArray = [{name:"Kristian", lines:"2,5,10"},
                     {name:"John", lines:"1,19,26,96"}];

        someArray = someArray.filter(function(returnableObjects){
               return returnableObjects.name !== 'Kristian';
        });

        //someArray will now be = [{name:"John", lines:"1,19,26,96"}];

箭头功能:

someArray = someArray.filter(x => x.name !== 'Kristian')

你也可以用一些:

someArray = [{name:"Kristian", lines:"2,5,10"},
             {name:"John", lines:"1,19,26,96"}];

someArray.some(item => { 
    if(item.name === "Kristian") // Case sensitive, will only remove first instance
        someArray.splice(someArray.indexOf(item),1) 
})

如果你在数组中的对象上没有任何你知道的属性(或者可能是唯一的)，但是你有一个你想要删除的对象的引用，你可以执行下面unregisterObject方法中的操作:

let registeredObjects = []; function registerObject(someObject) { registeredObjects.push(someObject); } function unregisterObject(someObject) { registeredObjects = registeredObjects.filter(obj => obj !== someObject); } let myObject1 = {hidden: "someValue1"}; // Let's pretend we don't know the hidden attribute let myObject2 = {hidden: "someValue2"}; registerObject(myObject1); registerObject(myObject2); console.log(`There are ${registeredObjects.length} objects registered. They are: ${JSON.stringify(registeredObjects)}`); unregisterObject(myObject1); console.log(`There are ${registeredObjects.length} objects registered. They are: ${JSON.stringify(registeredObjects)}`);