我正在尝试使用Html。下拉列表扩展方法,但不知道如何与枚举一起使用它。

假设我有一个这样的枚举:

public enum ItemTypes
{
    Movie = 1,
    Game = 2,
    Book = 3
}

我如何去创建一个下拉与这些值使用Html。下拉列表扩展方法?

或者我最好的办法是简单地创建一个for循环并手动创建Html元素?


当前回答

在MVC4中,我会这样做

@Html.DropDownList("RefType", new SelectList(Enum.GetValues(typeof(WebAPIApp.Models.RefType))), " Select", new { @class = "form-control" })

public enum RefType
    {
        Web = 3,
        API = 4,
        Security = 5,
        FE = 6
    }

    public class Reference
    {
        public int Id { get; set; }
        public RefType RefType { get; set; }
    }

其他回答

我想以一种不同的方式回答这个问题,用户不需要在控制器或Linq表达式中做任何事情。这种方式……

我有一个ENUM

public enum AccessLevelEnum
    {
        /// <summary>
        /// The user cannot access
        /// </summary>
        [EnumMember, Description("No Access")]
        NoAccess = 0x0,

        /// <summary>
        /// The user can read the entire record in question
        /// </summary>
        [EnumMember, Description("Read Only")]
        ReadOnly = 0x01,

        /// <summary>
        /// The user can read or write
        /// </summary>
        [EnumMember, Description("Read / Modify")]
        ReadModify = 0x02,

        /// <summary>
        /// User can create new records, modify and read existing ones
        /// </summary>
        [EnumMember, Description("Create / Read / Modify")]
        CreateReadModify = 0x04,

        /// <summary>
        /// User can read, write, or delete
        /// </summary>
        [EnumMember, Description("Create / Read / Modify / Delete")]
        CreateReadModifyDelete = 0x08,

        /*/// <summary>
        /// User can read, write, or delete
        /// </summary>
        [EnumMember, Description("Create / Read / Modify / Delete / Verify / Edit Capture Value")]
        CreateReadModifyDeleteVerify = 0x16*/
    }

现在我可以使用这个enum简单地创建一个下拉列表。

@Html.DropDownList("accessLevel",new SelectList(AccessLevelEnum.GetValues(typeof(AccessLevelEnum))),new { @class = "form-control" })

OR

@Html.DropDownListFor(m=>m.accessLevel,new SelectList(AccessLevelEnum.GetValues(typeof(AccessLevelEnum))),new { @class = "form-control" })

如果你想让一个索引被选中,那么试试这个

@Html.DropDownListFor(m=>m.accessLevel,new SelectList(AccessLevelEnum.GetValues(typeof(AccessLevelEnum)) , AccessLevelEnum.NoAccess ),new { @class = "form-control" })

这里我使用了AccessLevelEnum。NoAccess作为默认选择下拉菜单的额外参数。

        ////  ViewModel

        public class RegisterViewModel
          {

        public RegisterViewModel()
          {
              ActionsList = new List<SelectListItem>();
          }

        public IEnumerable<SelectListItem> ActionsList { get; set; }

        public string StudentGrade { get; set; }

           }

       //// Enum Class

        public enum GradeTypes
             {
               A,
               B,
               C,
               D,
               E,
               F,
               G,
               H
            }

         ////Controller action 

           public ActionResult Student()
               {
    RegisterViewModel vm = new RegisterViewModel();
    IEnumerable<GradeTypes> actionTypes = Enum.GetValues(typeof(GradeTypes))
                                         .Cast<GradeTypes>();                  
    vm.ActionsList = from action in actionTypes
                     select new SelectListItem
                     {
                         Text = action.ToString(),
                         Value = action.ToString()
                     };
              return View(vm);
               }

         ////// View Action

   <div class="form-group">
                            <label class="col-lg-2 control-label" for="hobies">Student Grade:</label>
                            <div class="col-lg-10">
                               @Html.DropDownListFor(model => model.StudentGrade, Model.ActionsList, new { @class = "form-control" })
                            </div>

根据Simon的回答,类似的方法是从Resource文件中获取要显示的Enum值,而不是在Enum本身的描述属性中。如果你的网站需要用多种语言呈现,如果你有一个特定的枚举资源文件,这是很有帮助的,你可以更进一步,在你的Enum中只有Enum值,并从扩展中引用它们,如[EnumName]_[EnumValue] -最终更少的输入!

然后扩展看起来像:

public static IHtmlString EnumDropDownListFor<TModel, TEnum>(this HtmlHelper<TModel> html, Expression<Func<TModel, TEnum>> expression)
{            
    var metadata = ModelMetadata.FromLambdaExpression(expression, html.ViewData);

    var enumType = Nullable.GetUnderlyingType(metadata.ModelType) ?? metadata.ModelType;

    var enumValues = Enum.GetValues(enumType).Cast<object>();

    var items = from enumValue in enumValues                        
                select new SelectListItem
                {
                    Text = GetResourceValueForEnumValue(enumValue),
                    Value = ((int)enumValue).ToString(),
                    Selected = enumValue.Equals(metadata.Model)
                };


    return html.DropDownListFor(expression, items, string.Empty, null);
}

private static string GetResourceValueForEnumValue<TEnum>(TEnum enumValue)
{
    var key = string.Format("{0}_{1}", enumValue.GetType().Name, enumValue);

    return Enums.ResourceManager.GetString(key) ?? enumValue.ToString();
}

枚举中的资源。Resx文件看起来像这样 ItemTypes_Movie:电影

我喜欢做的另一件事是,与其直接调用扩展方法,不如使用@Html调用它。EditorFor(x => x.MyProperty),或者理想情况下只有整个表单,在一个整洁的@Html.EditorForModel()中。为此,我将字符串模板更改为如下所示

@using MVCProject.Extensions

@{
    var type = Nullable.GetUnderlyingType(ViewData.ModelMetadata.ModelType) ?? ViewData.ModelMetadata.ModelType;

    @(typeof (Enum).IsAssignableFrom(type) ? Html.EnumDropDownListFor(x => x) : Html.TextBoxFor(x => x))
}

如果你对此感兴趣,我在我的博客上给出了更详细的答案:

http://paulthecyclist.com/2013/05/24/enum-dropdown/

@Html.DropDownListFor(model => model.MaritalStatus, new List<SelectListItem> 
{  

new SelectListItem { Text = "----Select----", Value = "-1" },


new SelectListItem { Text = "Marrid", Value = "M" },


 new SelectListItem { Text = "Single", Value = "S" }

})

您希望使用类似Enum的东西。getvalue