从数据库表生成类

如何从SQL Server表对象生成类?

我说的不是使用ORM。我只需要创建实体(简单类)。喜欢的东西:

    public class Person 
    {
        public string Name { get;set; }
        public string Phone { get;set; }
    }

给定一个表，比如:

+----+-------+----------------+
| ID | Name  |     Phone      |
+----+-------+----------------+
|  1 | Alice | (555) 555-5550 |
|  2 | Bob   | (555) 555-5551 |
|  3 | Cathy | (555) 555-5552 |
+----+-------+----------------+

当前回答

Oracle DB的另一个解决方案-> c#

单查询无功能无步骤 Mulitple表

添加DataAnnotations

(例子) (需要) (表) (StringLength) (列) 可以为空

查询

https://gist.github.com/omansak/f19eefffd2d639ac72a1f4b506d8471a

输出

[Table("AGENTS")]
public class Agents
{
    [Key]
    [Required]
    [Column("INT_ID", TypeName = "NUMBER(10,0)", Order = 1)]
    public long IntId { get; set; }
    [Key]
    [Required]
    [StringLength(15)]
    [Column("REFERENCE_CODE", TypeName = "VARCHAR2(15)", Order = 2)]
    public string ReferenceCode { get; set; }
    [Required]
    [Column("PARENT_INT_ID", TypeName = "NUMBER(10,0)", Order = 3)]
    public long ParentIntId { get; set; }
    [Required]
    [StringLength(200)]
    [Column("TITLE", TypeName = "VARCHAR2(200)", Order = 4)]
    public string Title { get; set; }
    [Required]
    [Column("START_DATE", TypeName = "DATE", Order = 5)]
    public DateTime StartDate { get; set; }
    [Required]
    [Column("END_DATE", TypeName = "DATE", Order = 6)]
    public DateTime EndDate { get; set; }
    [Required]
    [StringLength(1)]
    [Column("AGENT_TYPE", TypeName = "VARCHAR2(1)", Order = 7)]
    public string AgentType { get; set; }
    [Required]
    [Column("CREATE_DATE", TypeName = "DATE", Order = 8)]
    public DateTime CreateDate { get; set; }
    [Required]
    [StringLength(32)]
    [Column("CREATE_USER", TypeName = "VARCHAR2(32)", Order = 9)]
    public string CreateUser { get; set; }
    [StringLength(200)]
    [Column("RESPONSIBLE_CONTACT", TypeName = "VARCHAR2(200)", Order = 10)]
    public string ResponsibleContact { get; set; }
    [StringLength(100)]
    [Column("RESPONSIBLE_TITLE", TypeName = "VARCHAR2(100)", Order = 11)]
    public string ResponsibleTitle { get; set; }
    [StringLength(100)]
    [Column("AGENCY_PLATE_NO", TypeName = "VARCHAR2(100)", Order = 12)]
    public string AgencyPlateNo { get; set; }
    [Column("AGENCY_COVER_AMOUNT", TypeName = "NUMBER(24,2)", Order = 13)]
    public double? AgencyCoverAmount { get; set; }
    [StringLength(100)]
    [Column("MERSIS_NO", TypeName = "VARCHAR2(100)", Order = 14)]
    public string MersisNo { get; set; }
    [StringLength(100)]
    [Column("TECH_PERSONEL_NO", TypeName = "VARCHAR2(100)", Order = 15)]
    public string TechPersonelNo { get; set; }
    [StringLength(100)]
    [Column("TECH_PERSONEL_NAME", TypeName = "VARCHAR2(100)", Order = 16)]
    public string TechPersonelName { get; set; }
    [Column("COVER_END_DATE", TypeName = "DATE", Order = 17)]
    public DateTime? CoverEndDate { get; set; }
    [Column("BRANCH_NUMBER", TypeName = "NUMBER(10,0)", Order = 18)]
    public long? BranchNumber { get; set; }
    [Column("ACTION_NUMBER", TypeName = "NUMBER(10,0)", Order = 19)]
    public long? ActionNumber { get; set; }
    [Column("CLUB_PARTICIPATION_COUNT", TypeName = "NUMBER(10,0)", Order = 20)]
    public long? ClubParticipationCount { get; set; }
    [Column("AGENCY_CONTRACT_DATE", TypeName = "DATE", Order = 21)]
    public DateTime? AgencyContractDate { get; set; }
    [StringLength(200)]
    [Column("KEP_ADDRESS", TypeName = "VARCHAR2(200)", Order = 22)]
    public string KepAddress { get; set; }
}

2021-08-23 13:39:30

其他回答

Postgres DB -> c#的另一个解决方案

兼容NpgSQL 添加DataAnnotations

    SELECT
            CASE 
                WHEN c.is_nullable ='NO'  THEN '[Required]'||chr(10)
                ELSE '' END
            ||CASE 
                WHEN c.data_type = 'character varying' THEN format('[StringLength(%s)]',c.character_maximum_length)||chr(10)
                ELSE '' END
            ||'public '
            ||CASE 
                WHEN c.data_type = 'integer' THEN 'int'
                WHEN c.data_type = 'boolean' THEN 'bool'
                WHEN c.data_type = 'double precision' THEN 'double'
                WHEN c.data_type = 'uuid' THEN 'Guid'
                WHEN c.data_type = 'character varying' THEN 'string'
                WHEN c.data_type = 'timestamp without time zone' THEN 'DateTime'    
                WHEN c.data_type = 'bigint' THEN 'long'   
                WHEN c.data_type = 'bytea' THEN 'byte[]'    
            ELSE 'object' END
            ||CASE
                WHEN c.is_nullable='YES' AND NOT  c.data_type = 'character varying' THEN '? '
                ELSE ' ' END
            ||c.column_name||' {get;set;}'
            ,c.*
    FROM information_schema."columns" c
    WHERE 1=1
    AND c.table_name='YOUR_TABLE_NAME'

2021-06-14 20:12:07

我只是想表达我的意见

0) QueryFirst https://marketplace.visualstudio.com/items?itemName=bbsimonbb.QueryFirst Query-first is a visual studio extension for working intelligently with SQL in C# projects. Use the provided .sql template to develop your queries. When you save the file, Query-first runs your query, retrieves the schema and generates two classes and an interface: a wrapper class with methods Execute(), ExecuteScalar(), ExecuteNonQuery() etc, its corresponding interface, and a POCO encapsulating a line of results.

1) Sql2Objects 从查询结果开始创建类(但不是DAL)

2) https://learn.microsoft.com/en-us/ef/ef6/resources/tools

3) https://visualstudiomagazine.com/articles/2012/12/11/sqlqueryresults-code-generation.aspx

4) http://www.codesmithtools.com/product/generator#features

2018-08-21 16:13:06

我很困惑你想要从这里得到什么，但这里是在设计你想要设计的东西时的一般选择。

在Visual Studio版本中使用内置的ORM。自己编写一个，类似于您的代码示例。通常情况下，如果你不确定怎么做，教程是你最好的朋友。使用另一种ORM，如NHibernate。

2011-05-03 17:24:21

商业化，但codessmith Generator做到了:http://www.codesmithtools.com/product/generator

2011-05-03 17:22:38

有点晚了，但我已经创建了一个web工具来帮助创建一个c#(或其他)对象从SQL结果，SQL表和SQL SP。

sql2object.com