我想匹配的只是一个URL的根，而不是一个文本字符串的整个URL。考虑到:
http://www.youtube.com/watch?v=ClkQA2Lb_iE
http://youtu.be/ClkQA2Lb_iE
http://www.example.com/12xy45
http://example.com/random
我想让最后2个实例解析到www.example.com或example.com域。
我听说正则表达式很慢，这将是我在页面上的第二个正则表达式，所以如果有办法做到没有正则表达式，请告诉我。
我正在寻找这个解决方案的JS/jQuery版本。
当前回答
代码:
var regex = /\w+.(com|co\.kr|be)/ig;
var urls = ['http://www.youtube.com/watch?v=ClkQA2Lb_iE',
'http://youtu.be/ClkQA2Lb_iE',
'http://www.example.com/12xy45',
'http://example.com/random'];
$.each(urls, function(index, url) {
var convertedUrl = url.match(regex);
console.log(convertedUrl);
});
结果:
youtube.com
youtu.be
example.com
example.com
其他回答
// use this if you know you have a subdomain
// www.domain.com -> domain.com
function getDomain() {
return window.location.hostname.replace(/([a-zA-Z0-9]+.)/,"");
}
解析域——一个非常可靠的轻量级库
NPM安装解析域
const { fromUrl, parseDomain } = require("parse-domain");
示例1
parseDomain(fromUrl("http://www.example.com/12xy45"))
{ type: 'LISTED',
hostname: 'www.example.com',
labels: [ 'www', 'example', 'com' ],
icann:
{ subDomains: [ 'www' ],
domain: 'example',
topLevelDomains: [ 'com' ] },
subDomains: [ 'www' ],
domain: 'example',
topLevelDomains: [ 'com' ] }
示例2
parseDomain(fromUrl("http://subsub.sub.test.ExAmPlE.coM/12xy45"))
{ type: 'LISTED',
hostname: 'subsub.sub.test.example.com',
labels: [ 'subsub', 'sub', 'test', 'example', 'com' ],
icann:
{ subDomains: [ 'subsub', 'sub', 'test' ],
domain: 'example',
topLevelDomains: [ 'com' ] },
subDomains: [ 'subsub', 'sub', 'test' ],
domain: 'example',
topLevelDomains: [ 'com' ] }
Why?
Depending on the use case and volume I strongly recommend against solving this problem yourself using regex or other string manipulation means. The core of this problem is that you need to know all the gtld and cctld suffixes to properly parse url strings into domain and subdomains, these suffixes are regularly updated. This is a solved problem and not one you want to solve yourself (unless you are google or something). Unless you need the hostname or domain name in a pinch don't try and parse your way out of this one.
简单来说，你可以这样做
var url = "http://www.someurl.com/support/feature"
function getDomain(url){
domain=url.split("//")[1];
return domain.split("/")[0];
}
eg:
getDomain("http://www.example.com/page/1")
output:
"www.example.com"
使用上述函数获取域名
好吧，使用正则表达式会容易得多:
mainUrl = "http://www.mywebsite.com/mypath/to/folder";
urlParts = /^(?:\w+\:\/\/)?([^\/]+)(.*)$/.exec(mainUrl);
host = Fragment[1]; // www.mywebsite.com
import URL from 'url';
const pathname = URL.parse(url).path;
console.log(url.replace(pathname, ''));
这样就兼顾了协议。
