我想从一个MySQL数据库的所有表的所有字段搜索一个给定的字符串,可能使用语法为:

SELECT * FROM * WHERE * LIKE '%stuff%'

有可能做这样的事情吗?


当前回答

我也做了我自己的mysql爬虫来搜索一些wordpress配置,在界面和数据库中都无法找到它,数据库转储太沉重和不可读。我得说我现在不能没有它。

它的工作原理类似于@Olivier,但它管理外来的数据库/表名,并且是像小丑一样安全。

<?php

$database = 'database';
$criteria = '*iemblo'; // you can use * and ? as jokers

$dbh = new PDO("mysql:host=127.0.0.1;dbname={$database};charset=utf8", 'root', '');
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

$tables = $dbh->query("SHOW TABLES");
while (($table = $tables->fetch(PDO::FETCH_NUM)) !== false)
{
    $fields = $dbh->prepare("SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = ? AND TABLE_NAME = ?");
    $fields->execute(array ($database, $table[0]));

    $ors = array ();
    while (($field = $fields->fetch(PDO::FETCH_NUM)) !== false)
    {
        $ors[] = str_replace("`", "``", $field[0]) . " LIKE REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(:search, '\\\\', '\\\\\\\\'), '%', '\\%'), '_', '\\_'), '*', '%'), '?', '_')";
    }

    $request = 'SELECT * FROM ';
    $request .= str_replace("`", "``", $table[0]);
    $request .= ' WHERE ';
    $request .= implode(' OR ', $ors);
    $rows = $dbh->prepare($request);

    $rows->execute(array ('search' => $criteria));

    $count = $rows->rowCount();
    if ($count == 0)
    {
        continue;
    }

    $str = "Table '{$table[0]}' contains {$count} rows matching '{$criteria}'.";
    echo str_repeat('-', strlen($str)), PHP_EOL;
    echo $str, PHP_EOL;
    echo str_repeat('-', strlen($str)), PHP_EOL;

    $counter = 1;
    while (($row = $rows->fetch(PDO::FETCH_ASSOC)) !== false)
    {
        $col = 0;
        $title = "Row #{$counter}:";
        echo $title;
        foreach ($row as $column => $value)
        {
            echo
            (($col++ > 0) ? str_repeat(' ', strlen($title) + 1) : ' '),
            $column, ': ',
            trim(preg_replace('!\s+!', ' ', str_replace(array ("\r", "\t", "\n"), array ("", "", " "), $value))),
            PHP_EOL;
        }
        echo PHP_EOL;
        $counter++;
    }
}

运行这个脚本可以输出如下内容:

---------------------------------------------------
Table 'customers' contains 1 rows matching '*iemblo'.
---------------------------------------------------
Row #1: email_client: my@email.com
        numero_client_compta: C05135
        nom_client: Tiemblo
        adresse_facturation_1: 151, My Street
        adresse_facturation_2: 
        ville_facturation: Nantes
        code_postal_facturation: 44300
        pays_facturation: FR
        numero_tva_client: 
        zone_geographique: UE
        prenom_client: Alain
        commentaires: 
        nom_societe: 
        email_facturation: my@email.com

其他回答

如果您不是在代码级别上使用它,只是想检查信息,您可以将整个数据库导出为SQL,然后在文本编辑器上搜索。

使用实例在CLI下搜索数据库所有表中的字符串。

mysqldump -u UserName --no-create-info --extended-insert=FALSE DBName -p | grep -i "searchingString"

Or,

mysqldump -u UserName --no-create-info --extended-insert=FALSE DBName -p | grep -i "searchingString" > searchingString.sql

PHP函数:

function searchAllDB($search){
    global $mysqli;
    
    $out = Array();
    
    $sql = "show tables";
    $rs = $mysqli->query($sql);
    if($rs->num_rows > 0){
        while($r = $rs->fetch_array()){
            $table = $r[0];
            $sql_search = "select * from `".$table."` where ";
            $sql_search_fields = Array();
            $sql2 = "SHOW COLUMNS FROM `".$table."`";
            $rs2 = $mysqli->query($sql2);
            if($rs2->num_rows > 0){
                while($r2 = $rs2->fetch_array()){
                    $column = $r2[0];
                    $sql_search_fields[] = "`".$column."` like('%".$mysqli->real_escape_string($search)."%')";
                }
                $rs2->close();
            }
            $sql_search .= implode(" OR ", $sql_search_fields);
            $rs3 = $mysqli->query($sql_search);
            $out[$table] = $rs3->num_rows."\n";
            if($rs3->num_rows > 0){
                $rs3->close();
            }
        }
        $rs->close();
    }
    
    return $out;
}

print_r(searchAllDB("search string"));

如果23个答案还不够,这里还有2个……根据数据库结构和内容,您可能会发现其中一个实际上是快速而简单的解决方案。

对于shell一行程序的爱好者,这里有一个很长的程序(实际上只有2行,使用变量):

cmd='mysql -u Username -pYour_Password -D Your_Database' # <-- Adapt this

$cmd -s -e 'SHOW TABLES' | while read table; do echo "=== $table ==="; $cmd -B -s -e "SELECT * FROM $table" | grep 'Your_Search'; done

或多行,使其更具可读性:

$cmd -s -e 'SHOW TABLES' \
| while read table; do
    echo "=== $table ===";
    $cmd -B -s -e "SELECT * FROM $table" \
    | grep 'Your_Search';
  done

-s(——silent)用于屏蔽列名标头 -B(——batch)转义像换行符这样的特殊字符,所以我们在使用grep时获得整个记录

对于Perl爱好者来说,这将允许您使用正则表达式:

# perl -MDBI -le '($db,$u,$p)=@ARGV; $dbh=DBI->connect("dbi:mysql:dbname=$db",$u,$p); foreach $table ($dbh->tables()) {print "$table\n"; foreach $r ($dbh->selectall_array("SELECT * FROM $table")) {$_=join("\t", @$r); print $_ if (/Your_Regex/);}}' Your_Database Username Your_Password

在“真正的”Perl脚本中可能是这样的:

#!/usr/bin/perl

use strict;
use open qw(:std :utf8);

use DBI;

my $db_host  = 'localhost';
my $db       = 'Your_Database';
my $db_user  = 'Username';
my $db_pass  = 'Your_Password';

my $search    = qr/Your_regex_Search/;


# https://metacpan.org/pod/DBD::mysql
my $dbh = DBI->connect( "dbi:mysql:dbname=$db;host=$db_host", $db_user, $db_pass,
                        { mysql_enable_utf8mb4 => 1 }
) or die "Can't connect: $DBI::errstr\n";


foreach my $table ( $dbh->tables() ) {
    my $sth = $dbh->prepare("SELECT * FROM $table")
        or die "Can't prepare: ", $dbh->errstr;

    $sth->execute
        or die "Can't execute: ", $sth->errstr;

    my @results;

    while (my @row = $sth->fetchrow()) {
        local $_ = join("\t", @row);
        if ( /$search/ ) {
            push @results, $_;
        }
    }

    $sth->finish;

    next unless @results;

    print "*** TABLE $table :\n",
          join("\n---------------\n", @results),
          "\n" . "=" x 20 . "\n";
}

$dbh->disconnect;

如果你安装了phpMyAdmin,使用它的“搜索”功能。

选择您的数据库 确保你有一个DB选择(即不是一个表,否则你会得到一个完全不同的搜索对话框) 点击“搜索”标签 选择您想要的搜索词 选择要搜索的表

我在250个表/10GB的数据库上使用过这个功能(在一个快速的服务器上),响应时间非常惊人。