这个解决方案 a)只有MySQL，不需要其他语言，并且 b)返回SQL结果，准备处理!

#Search multiple database tables and/or columns
#Version 0.1 - JK 2014-01
#USAGE: 1. set the search term @search, 2. set the scope by adapting the WHERE clause of the `information_schema`.`columns` query
#NOTE: This is a usage example and might be advanced by setting the scope through a variable, putting it all in a function, and so on...

#define the search term here (using rules for the LIKE command, e.g % as a wildcard)
SET @search = '%needle%';

#settings
SET SESSION group_concat_max_len := @@max_allowed_packet;

#ini variable
SET @sql = NULL;

#query for prepared statement
SELECT
    GROUP_CONCAT("SELECT '",`TABLE_NAME`,"' AS `table`, '",`COLUMN_NAME`,"' AS `column`, `",`COLUMN_NAME`,"` AS `value` FROM `",TABLE_NAME,"` WHERE `",COLUMN_NAME,"` LIKE '",@search,"'" SEPARATOR "\nUNION\n") AS col
INTO @sql
FROM `information_schema`.`columns`
WHERE TABLE_NAME IN
(
    SELECT TABLE_NAME FROM `information_schema`.`columns`
    WHERE
        TABLE_SCHEMA IN ("my_database")
        && TABLE_NAME IN ("my_table1", "my_table2") || TABLE_NAME LIKE "my_prefix_%"
);

#prepare and execute the statement
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

PHP函数:

function searchAllDB($search){
    global $mysqli;
    
    $out = Array();
    
    $sql = "show tables";
    $rs = $mysqli->query($sql);
    if($rs->num_rows > 0){
        while($r = $rs->fetch_array()){
            $table = $r[0];
            $sql_search = "select * from `".$table."` where ";
            $sql_search_fields = Array();
            $sql2 = "SHOW COLUMNS FROM `".$table."`";
            $rs2 = $mysqli->query($sql2);
            if($rs2->num_rows > 0){
                while($r2 = $rs2->fetch_array()){
                    $column = $r2[0];
                    $sql_search_fields[] = "`".$column."` like('%".$mysqli->real_escape_string($search)."%')";
                }
                $rs2->close();
            }
            $sql_search .= implode(" OR ", $sql_search_fields);
            $rs3 = $mysqli->query($sql_search);
            $out[$table] = $rs3->num_rows."\n";
            if($rs3->num_rows > 0){
                $rs3->close();
            }
        }
        $rs->close();
    }
    
    return $out;
}

print_r(searchAllDB("search string"));

您可以查看information_schema模式。它包含所有表和表中所有字段的列表。然后，您可以使用从该表中获得的信息运行查询。

涉及的表包括SCHEMATA、tables和COLUMNS。有一些外键，这样您就可以在模式中准确地构建表的创建方式。

我不知道这是否只在最近的版本中，但右键单击Navigator窗格中的Tables选项会弹出一个名为Search Table Data的选项。这将打开一个搜索框，您可以在其中填写搜索字符串并点击搜索。

您确实需要在左侧窗格中选择要搜索的表。但如果你按住shift键一次选择10个表，MySql可以在几秒钟内处理并返回结果。

对于任何正在寻找更好选择的人!：）

我使用Union将查询串在一起。不知道这是不是最有效的方法，但确实有效。

SELECT * FROM table1 WHERE name LIKE '%Bob%' Union
SELCET * FROM table2 WHERE name LIKE '%Bob%';

使用实例在CLI下搜索数据库所有表中的字符串。

mysqldump -u UserName --no-create-info --extended-insert=FALSE DBName -p | grep -i "searchingString"

Or,

mysqldump -u UserName --no-create-info --extended-insert=FALSE DBName -p | grep -i "searchingString" > searchingString.sql