请看这个例子。它可能对你有帮助。

#include <iostream>
#include <sstream>

using namespace std;

int main ()
{
    string tmps;
    istringstream is ("the dellimiter is the space");
    while (is.good ()) {
        is >> tmps;
        cout << tmps << "\n";
    }
    return 0;
}

这是一个简单的循环，只对标准库文件进行标记

#include <iostream.h>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <conio.h>
class word
    {
     public:
     char w[20];
     word()
      {
        for(int j=0;j<=20;j++)
        {w[j]='\0';
      }
   }



};

void main()
  {
    int i=1,n=0,j=0,k=0,m=1;
    char input[100];
    word ww[100];
    gets(input);

    n=strlen(input);


    for(i=0;i<=m;i++)
      {
        if(context[i]!=' ')
         {
            ww[k].w[j]=context[i];
            j++;

         }
         else
        {
         k++;
         j=0;
         m++;
        }

   }
 }

/// split a string into multiple sub strings, based on a separator string
/// for example, if separator="::",
///
/// s = "abc" -> "abc"
///
/// s = "abc::def xy::st:" -> "abc", "def xy" and "st:",
///
/// s = "::abc::" -> "abc"
///
/// s = "::" -> NO sub strings found
///
/// s = "" -> NO sub strings found
///
/// then append the sub-strings to the end of the vector v.
/// 
/// the idea comes from the findUrls() function of "Accelerated C++", chapt7,
/// findurls.cpp
///
void split(const string& s, const string& sep, vector<string>& v)
{
    typedef string::const_iterator iter;
    iter b = s.begin(), e = s.end(), i;
    iter sep_b = sep.begin(), sep_e = sep.end();

    // search through s
    while (b != e){
        i = search(b, e, sep_b, sep_e);

        // no more separator found
        if (i == e){
            // it's not an empty string
            if (b != e)
                v.push_back(string(b, e));
            break;
        }
        else if (i == b){
            // the separator is found and right at the beginning
            // in this case, we need to move on and search for the
            // next separator
            b = i + sep.length();
        }
        else{
            // found the separator
            v.push_back(string(b, i));
            b = i;
        }
    }
}

boost库很好，但并不总是可用的。手工做这些事情也是很好的脑力锻炼。这里我们只使用STL中的std::search()算法，参见上面的代码。

您可以简单地使用正则表达式库并使用正则表达式解决该问题。

使用表达式(\w+)和\1中的变量(或$1，取决于正则表达式的库实现)。

下面是一个示例标记器类，它可以实现您想要的功能

//Header file
class Tokenizer 
{
    public:
        static const std::string DELIMITERS;
        Tokenizer(const std::string& str);
        Tokenizer(const std::string& str, const std::string& delimiters);
        bool NextToken();
        bool NextToken(const std::string& delimiters);
        const std::string GetToken() const;
        void Reset();
    protected:
        size_t m_offset;
        const std::string m_string;
        std::string m_token;
        std::string m_delimiters;
};

//CPP file
const std::string Tokenizer::DELIMITERS(" \t\n\r");

Tokenizer::Tokenizer(const std::string& s) :
    m_string(s), 
    m_offset(0), 
    m_delimiters(DELIMITERS) {}

Tokenizer::Tokenizer(const std::string& s, const std::string& delimiters) :
    m_string(s), 
    m_offset(0), 
    m_delimiters(delimiters) {}

bool Tokenizer::NextToken() 
{
    return NextToken(m_delimiters);
}

bool Tokenizer::NextToken(const std::string& delimiters) 
{
    size_t i = m_string.find_first_not_of(delimiters, m_offset);
    if (std::string::npos == i) 
    {
        m_offset = m_string.length();
        return false;
    }

    size_t j = m_string.find_first_of(delimiters, i);
    if (std::string::npos == j) 
    {
        m_token = m_string.substr(i);
        m_offset = m_string.length();
        return true;
    }

    m_token = m_string.substr(i, j - i);
    m_offset = j;
    return true;
}

例子:

std::vector <std::string> v;
Tokenizer s("split this string", " ");
while (s.NextToken())
{
    v.push_back(s.GetToken());
}

Boost::tokenizer是您的好朋友，但是请考虑使用wstring/wchar_t而不是传统的string/char类型，使您的代码在国际化(i18n)问题上具有可移植性。

#include <iostream>
#include <boost/tokenizer.hpp>
#include <string>

using namespace std;
using namespace boost;

typedef tokenizer<char_separator<wchar_t>,
                  wstring::const_iterator, wstring> Tok;

int main()
{
  wstring s;
  while (getline(wcin, s)) {
    char_separator<wchar_t> sep(L" "); // list of separator characters
    Tok tok(s, sep);
    for (Tok::iterator beg = tok.begin(); beg != tok.end(); ++beg) {
      wcout << *beg << L"\t"; // output (or store in vector)
    }
    wcout << L"\n";
  }
  return 0;
}