当你只想做一个try-except而不处理异常时,你在Python中如何做呢?
下面的方法是正确的吗?
try:
shutil.rmtree(path)
except:
pass
当你只想做一个try-except而不处理异常时,你在Python中如何做呢?
下面的方法是正确的吗?
try:
shutil.rmtree(path)
except:
pass
当前回答
在Python中,我们处理异常的方式与其他语言类似,但区别在于语法上的不同,例如,
try:
#Your code in which exception can occur
except <here we can put in a particular exception name>:
# We can call that exception here also, like ZeroDivisionError()
# now your code
# We can put in a finally block also
finally:
# Your code...
其他回答
try:
doSomething()
except Exception:
pass
or
try:
doSomething()
except:
pass
不同的是第二个也会捕捉KeyboardInterrupt, SystemExit和类似的东西,它们直接从BaseException派生,而不是Exception。
详见文档:
试着声明 异常
然而,捕捉每个错误通常是糟糕的实践——参见为什么“except: pass”是一个糟糕的编程实践?
当你只想做一个try catch而不处理异常时, 用Python怎么做?
这将帮助你打印异常是什么:(即尝试catch而不处理异常并打印异常。)
import sys
try:
doSomething()
except:
print "Unexpected error:", sys.exc_info()[0]
在Python中,我们处理异常的方式与其他语言类似,但区别在于语法上的不同,例如,
try:
#Your code in which exception can occur
except <here we can put in a particular exception name>:
# We can call that exception here also, like ZeroDivisionError()
# now your code
# We can put in a finally block also
finally:
# Your code...
我通常会这样做:
try:
doSomething()
except:
_ = ""
当你只想做一个try catch而不处理异常时,你在Python中如何做呢?
这取决于你对“处理”的定义。
如果你想抓住它不采取任何行动,你张贴的代码将工作。
如果你的意思是你想对一个异常采取行动,而不阻止该异常上升到堆栈,那么你想要这样的东西:
try:
do_something()
except:
handle_exception()
raise #re-raise the exact same exception that was thrown