results = []
chunk_size = 10
while(array.length > 0){
   results.push(array.splice(0, chunk_size))
}

对于功能性的解决方案，使用Ramda:

其中，popularProducts是输入数组，5是数据块大小

导入splitEvery from 'ramda/src/splitEvery' popularProducts splitEvery(5)。Map ((chunk, i) => { //用chunk做一些事情 })

在JS,

const splitInChunks = (arr,n) => {
  let chunksArr = [];
  if(arr !=null && arr!= undefined){
      for(i=0; i<arr.length;i+=n){
      if(arr.length-i>=n)
          chunksArr.push(arr.slice(i,i+n))
      else
           chunksArr.push(arr.slice(i,arr.length))
  }
  return chunksArr
  }
}

对源数组进行突变:

let a = [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ], aa = [], x
while((x = a.splice(0, 2)).length) aa.push(x)

// aa == [ [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], [ 7, 8 ], [ 9 ] ]
// a == []

不改变源数组:

let a = [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ], aa = []
for(let i = 0; i < a.length; i += 2) aa.push(a.slice(i, i + 2))

// aa == [ [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], [ 7, 8 ], [ 9 ] ]
// a == [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ]

一个很好的函数是:

function chunk(arr,times){
    if(times===null){var times = 10} //Fallback for users wanting to use the default of ten
   var tempArray = Array() //Array to be populated with chunks
    for(i=0;i<arr.length/times;i++){
     tempArray[i] = Array() //Sub-Arrays        //Repeats for each chunk         
   for(j=0;j<times;j++){
        if(!(arr[i*times+j]===undefined)){tempArray[i][j] = arr[i*times+j]//Populate Sub-  Arrays with chunks
    }
     else{
       j = times //Stop loop
       i = arr.length/times //Stop loop
  }
    }
     }
   return tempArray //Return the populated and chunked array
   }

用法如下:

chunk(array,sizeOfChunks)

我对它做了注释，这样你就能理解发生了什么。

(格式有点不对，我在移动设备上编程)

我只是在groupBy函数的帮助下写了这个。

// utils const group = (source) => ({ by: (grouping) => { const groups = source.reduce((accumulator, item) => { const name = JSON.stringify(grouping(item)); accumulator[name] = accumulator[name] || []; accumulator[name].push(item); return accumulator; }, {}); return Object.keys(groups).map(key => groups[key]); } }); const chunk = (source, size) => group(source.map((item, index) => ({ item, index }))) .by(x => Math.floor(x.index / size)) .map(x => x.map(v => v.item)); // 103 items const arr = [6,2,6,6,0,7,4,9,3,1,9,6,1,2,7,8,3,3,4,6,8,7,6,9,3,6,3,5,0,9,3,7,0,4,1,9,7,5,7,4,3,4,8,9,0,5,1,0,0,8,0,5,8,3,2,5,6,9,0,0,1,5,1,7,0,6,1,6,8,4,9,8,9,1,6,5,4,9,1,6,6,1,8,3,5,5,7,0,8,3,1,7,1,1,7,6,4,9,7,0,5,1,0]; const chunks = chunk(arr, 10); console.log(JSON.stringify(chunks));