是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
当前回答
为了获得对称差异,您需要以两种方式比较数组(或在多个数组的情况下以所有方式比较)
ES7 (ECMAScript 2016)
// diff between just two arrays:
function arrayDiff(a, b) {
return [
...a.filter(x => !b.includes(x)),
...b.filter(x => !a.includes(x))
];
}
// diff between multiple arrays:
function arrayDiff(...arrays) {
return [].concat(...arrays.map( (arr, i) => {
const others = arrays.slice(0);
others.splice(i, 1);
const unique = [...new Set([].concat(...others))];
return arr.filter(x => !unique.includes(x));
}));
}
ES6(2015年ECMAScript)
// diff between just two arrays:
function arrayDiff(a, b) {
return [
...a.filter(x => b.indexOf(x) === -1),
...b.filter(x => a.indexOf(x) === -1)
];
}
// diff between multiple arrays:
function arrayDiff(...arrays) {
return [].concat(...arrays.map( (arr, i) => {
const others = arrays.slice(0);
others.splice(i, 1);
const unique = [...new Set([].concat(...others))];
return arr.filter(x => unique.indexOf(x) === -1);
}));
}
ES5 (ECMAScript 5.1)
// diff between just two arrays:
function arrayDiff(a, b) {
var arrays = Array.prototype.slice.call(arguments);
var diff = [];
arrays.forEach(function(arr, i) {
var other = i === 1 ? a : b;
arr.forEach(function(x) {
if (other.indexOf(x) === -1) {
diff.push(x);
}
});
})
return diff;
}
// diff between multiple arrays:
function arrayDiff() {
var arrays = Array.prototype.slice.call(arguments);
var diff = [];
arrays.forEach(function(arr, i) {
var others = arrays.slice(0);
others.splice(i, 1);
var otherValues = Array.prototype.concat.apply([], others);
var unique = otherValues.filter(function (x, j) {
return otherValues.indexOf(x) === j;
});
diff = diff.concat(arr.filter(x => unique.indexOf(x) === -1));
});
return diff;
}
例子:
// diff between two arrays:
const a = ['a', 'd', 'e'];
const b = ['a', 'b', 'c', 'd'];
arrayDiff(a, b); // (3) ["e", "b", "c"]
// diff between multiple arrays
const a = ['b', 'c', 'd', 'e', 'g'];
const b = ['a', 'b'];
const c = ['a', 'e', 'f'];
arrayDiff(a, b, c); // (4) ["c", "d", "g", "f"]
对象数组之间的差异
function arrayDiffByKey(key, ...arrays) {
return [].concat(...arrays.map( (arr, i) => {
const others = arrays.slice(0);
others.splice(i, 1);
const unique = [...new Set([].concat(...others))];
return arr.filter( x =>
!unique.some(y => x[key] === y[key])
);
}));
}
例子:
const a = [{k:1}, {k:2}, {k:3}];
const b = [{k:1}, {k:4}, {k:5}, {k:6}];
const c = [{k:3}, {k:5}, {k:7}];
arrayDiffByKey('k', a, b, c); // (4) [{k:2}, {k:4}, {k:6}, {k:7}]
其他回答
修正了一下最佳答案
function arr_diff(a1, a2)
{
var a=[], diff=[];
for(var i=0;i<a1.length;i++)
a[a1[i]]=a1[i];
for(var i=0;i<a2.length;i++)
if(a[a2[i]]) delete a[a2[i]];
else a[a2[i]]=a2[i];
for(var k in a)
diff.push(a[k]);
return diff;
}
这将考虑当前的元素类型。B /c当我们创建一个[a1[i]]时,它将一个值从原始值转换为字符串,因此我们失去了实际值。
adaen对post(比较两个包含整数的数组JavaScript)的响应是关闭的:
有几个选项:
您可以将第二个数组的所有条目添加到hashmap中。然后遍历第一个数组中的条目,并记录hashmap中不存在的条目。
const arrOne = [2,3,10,7,9,15,7,15,21,1];
const arrTwo = [3,15,1,2,21];
const hash = {};
arrTwo.forEach(a => hash[a]++);
arrOne.filter(a => typeof hash[a] === 'undefined').forEach(a => console.log(a));
另一个选择是对两个数组进行排序。然后迭代第二个数组。在其中,迭代第一个数组。当您遇到第一个数组中的条目小于第二个数组中的下一个条目但不等于它时,您将它们注销。
const arrOne = [2,3,10,7,9,15,7,15,21,1].sort((a,b)=>a-b);
const arrTwo = [3,15,1,2,21].sort((a,b)=>a-b);
var i1 = 0;
for(var i2 = 0; i2 < arrTwo.length; i2++) {
while(arrOne[i1] < arrTwo[i2+1]) {
if(arrOne[i1] != arrTwo[i2]) {
console.log(arrOne[i1]);
}
i1++;
}
}
快速的解决方案。尽管似乎其他人已经发布了相同方法的不同变体。我不确定这是否适合大型数组,但它适用于不大于10或15的数组。
差b - a
for(var i = 0; i < b.length; i++){
for(var j = 0; j < a.length; j ++){
var loc = b.indexOf(a[j]);
if(loc > -1){
b.splice(loc, 1);
}
}
}
/ / es6方法
function diff(a, b) {
var u = a.slice(); //dup the array
b.map(e => {
if (u.indexOf(e) > -1) delete u[u.indexOf(e)]
else u.push(e) //add non existing item to temp array
})
return u.filter((x) => {return (x != null)}) //flatten result
}
数据:
var new_storage = JSON.parse('[{"id_order":"0003"},{"id_order":"0004"},{"id_order":"0006"}]');
var old_storage = JSON.parse('[{"id_order":"0001"},{"id_order":"0002"},{"id_order":"0003"},{"id_order":"0004"},{"id_order":"0005"}]');
使用过滤器:
var diff = new_storage
.filter(x => {if(!(old_storage.filter(y => y.id_order==x.id_order)).length){return x}})
.concat(old_storage
.filter(x => {if(!(new_storage.filter(y => y.id_order==x.id_order)).length){return x}})
)
console.log(JSON.stringify(diff))
两个数组的结果不同
[{"id_order":"0006"},{"id_order":"0001"},{"id_order":"0002"},{"id_order":"0005"}]