是否有一种方法可以在JavaScript中返回两个数组之间的差异?

例如:

var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];

// need ["c", "d"]

当前回答

function array_diff(a, b) {

    let array = [];
    for(let i = 0; i <a.length; i++) {
        let k = 0;
        for( let j = 0; j < b.length; j++) {
            if(a[i]!==b[j]) {
                k++;
            }
            if(k===b.length) {
                array = array.concat(a[i]);
            }
        }

        if(b.length ===0) {
            array = array.concat(a[i]);
        }
    }
    return array;
}

其他回答

以上Joshaven Potter的回答非常棒。但是它返回数组B中不在数组C中的元素,而不是反过来。例如,如果var a=[1,2,3,4,5,6]。diff([3、4、5、7]);然后它将输出:==>[1,2,6],而不是[1,2,6,7],这是两者之间的实际差异。你仍然可以使用上面的Potter代码,但也可以简单地向后做一次比较:

Array.prototype.diff = function(a) {
    return this.filter(function(i) {return !(a.indexOf(i) > -1);});
};

////////////////////  
// Examples  
////////////////////

var a=[1,2,3,4,5,6].diff( [3,4,5,7]);
var b=[3,4,5,7].diff([1,2,3,4,5,6]);
var c=a.concat(b);
console.log(c);

这应该输出:[1,2,6,7]

这是我用来获得两个数组之间的差异的函数-它适用于数值,字符串,混合num/字符串数组。在数组/多维数组中不是对象文字

function diff(arr1, arr2) {

    var x, 
        t;

    function uniq(a, b) {
        t = b;

        if( (b === 0 && x[b+1]!==a) || 
           (t > 0 && a !== x[b+1] && a !== x[b-1]) ) {
            return  a;
        }
    }


    x = arr1.concat(arr2).sort();

    return x.filter(uniq);
}

var a1 = ['a', 'b', 'e', 'c'],
    a2 = ['b', 'a', 'c', 'f' ];

diff(a1, a2);

我在这里读到的答案有很多问题,使得它们在实际编程应用中价值有限。

First and foremost, you're going to want to have a way to control what it means for two items in the array to be "equal". The === comparison is not going to cut it if you're trying to figure out whether to update an array of objects based on an ID or something like that, which frankly is probably one of the most likely scenarios in which you will want a diff function. It also limits you to arrays of things that can be compared with the === operator, i.e. strings, ints, etc, and that's pretty much unacceptable for grown-ups.

其次,diff操作有三种状态结果:

在第一个数组中但不在第二个数组中的元素 两个数组共用的元素 在第二个数组中但不在第一个数组中的元素

我认为这意味着你需要不少于2个循环,但我愿意接受肮脏的技巧,如果有人知道如何将其减少到一个。

这里是我拼凑的一些东西,我想强调的是,我绝对不在乎它在旧版本的Microshaft浏览器中不起作用。如果您在IE这样的较差的编码环境中工作,那么您就可以自行修改它,使其在您无法满意的限制范围内工作。

Array.defaultValueComparison = function(a, b) {
    return (a === b);
};

Array.prototype.diff = function(arr, fnCompare) {

    // validate params

    if (!(arr instanceof Array))
        arr = [arr];

    fnCompare = fnCompare || Array.defaultValueComparison;

    var original = this, exists, storage, 
        result = { common: [], removed: [], inserted: [] };

    original.forEach(function(existingItem) {

        // Finds common elements and elements that 
        // do not exist in the original array

        exists = arr.some(function(newItem) {
            return fnCompare(existingItem, newItem);
        });

        storage = (exists) ? result.common : result.removed;
        storage.push(existingItem);

    });

    arr.forEach(function(newItem) {

        exists = original.some(function(existingItem) {
            return fnCompare(existingItem, newItem);
        });

        if (!exists)
            result.inserted.push(newItem);

    });

    return result;

};

如果你想找出两个object数组之间的差异,你可以这样做:

let arrObj = [{id: 1},{id: 2},{id: 3}] let arrObj2 = [{id: 1},{id: 3}] let result = arrObj。filter(x => arrObj2.)每个(x2 => x2。Id == x.id) console.log(结果)

var arrayDifference = function(arr1, arr2){
  if(arr1 && arr1.length){
    if(arr2 && arr2.length > 0){
      for (var i=0, itemIndex; i<arr2.length; i++){
        itemIndex = arr1.indexOf(arr2[i]);
        if(itemIndex !== -1){
          arr1.splice(itemIndex, 1);
        }
      }
    }
    return arr1;
  }
  return [];
};

arrayDifference([1,2,3,4,5], [1,5,6]);