我如何添加一个颜色列到下面的数据框架,使颜色='绿色'如果设置== 'Z',和颜色='红色'否则?
Type Set
1 A Z
2 B Z
3 B X
4 C Y
我如何添加一个颜色列到下面的数据框架,使颜色='绿色'如果设置== 'Z',和颜色='红色'否则?
Type Set
1 A Z
2 B Z
3 B X
4 C Y
当前回答
一个使用np.select的更简洁的方法:
a = np.array([['A','Z'],['B','Z'],['B','X'],['C','Y']])
df = pd.DataFrame(a,columns=['Type','Set'])
conditions = [
df['Set'] == 'Z'
]
outputs = [
'Green'
]
# conditions Z is Green, Red Otherwise.
res = np.select(conditions, outputs, 'Red')
res
array(['Green', 'Green', 'Red', 'Red'], dtype='<U5')
df.insert(2, 'new_column',res)
df
Type Set new_column
0 A Z Green
1 B Z Green
2 B X Red
3 C Y Red
df.to_numpy()
array([['A', 'Z', 'Green'],
['B', 'Z', 'Green'],
['B', 'X', 'Red'],
['C', 'Y', 'Red']], dtype=object)
%%timeit conditions = [df['Set'] == 'Z']
outputs = ['Green']
np.select(conditions, outputs, 'Red')
134 µs ± 9.71 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each)
df2 = pd.DataFrame({'Type':list('ABBC')*1000000, 'Set':list('ZZXY')*1000000})
%%timeit conditions = [df2['Set'] == 'Z']
outputs = ['Green']
np.select(conditions, outputs, 'Red')
188 ms ± 26.5 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
其他回答
一个使用np.select的更简洁的方法:
a = np.array([['A','Z'],['B','Z'],['B','X'],['C','Y']])
df = pd.DataFrame(a,columns=['Type','Set'])
conditions = [
df['Set'] == 'Z'
]
outputs = [
'Green'
]
# conditions Z is Green, Red Otherwise.
res = np.select(conditions, outputs, 'Red')
res
array(['Green', 'Green', 'Red', 'Red'], dtype='<U5')
df.insert(2, 'new_column',res)
df
Type Set new_column
0 A Z Green
1 B Z Green
2 B X Red
3 C Y Red
df.to_numpy()
array([['A', 'Z', 'Green'],
['B', 'Z', 'Green'],
['B', 'X', 'Red'],
['C', 'Y', 'Red']], dtype=object)
%%timeit conditions = [df['Set'] == 'Z']
outputs = ['Green']
np.select(conditions, outputs, 'Red')
134 µs ± 9.71 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each)
df2 = pd.DataFrame({'Type':list('ABBC')*1000000, 'Set':list('ZZXY')*1000000})
%%timeit conditions = [df2['Set'] == 'Z']
outputs = ['Green']
np.select(conditions, outputs, 'Red')
188 ms ± 26.5 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
下面的方法比这里计时的方法慢,但是我们可以基于多个列的内容计算额外的列,并且可以为额外的列计算两个以上的值。
使用“Set”列的简单示例:
def set_color(row):
if row["Set"] == "Z":
return "red"
else:
return "green"
df = df.assign(color=df.apply(set_color, axis=1))
print(df)
Set Type color
0 Z A red
1 Z B red
2 X B green
3 Y C green
考虑到更多颜色和更多列的例子:
def set_color(row):
if row["Set"] == "Z":
return "red"
elif row["Type"] == "C":
return "blue"
else:
return "green"
df = df.assign(color=df.apply(set_color, axis=1))
print(df)
Set Type color
0 Z A red
1 Z B red
2 X B green
3 Y C blue
编辑(21/06/2019):使用plydata
也可以使用plydata来做这类事情(不过,这似乎比使用assign和apply还要慢)。
from plydata import define, if_else
简单的if_else:
df = define(df, color=if_else('Set=="Z"', '"red"', '"green"'))
print(df)
Set Type color
0 Z A red
1 Z B red
2 X B green
3 Y C green
嵌套if_else:
df = define(df, color=if_else(
'Set=="Z"',
'"red"',
if_else('Type=="C"', '"green"', '"blue"')))
print(df)
Set Type color
0 Z A red
1 Z B red
2 X B blue
3 Y C green
当你有一个或几个条件时,可以使用下面的简单语句:
df['color'] = np.select(condlist=[df['Set']=="Z", df['Set']=="Y"], choicelist=["green", "yellow"], default="red")
容易,很好去!
更多信息请访问:https://numpy.org/doc/stable/reference/generated/numpy.select.html
列表推导式是有条件地创建另一列的另一种方法。如果您在列中使用对象dtype,就像您的示例一样,列表推导式通常优于大多数其他方法。
示例列表理解:
df['color'] = ['red' if x == 'Z' else 'green' for x in df['Set']]
%时间它测试:
import pandas as pd
import numpy as np
df = pd.DataFrame({'Type':list('ABBC'), 'Set':list('ZZXY')})
%timeit df['color'] = ['red' if x == 'Z' else 'green' for x in df['Set']]
%timeit df['color'] = np.where(df['Set']=='Z', 'green', 'red')
%timeit df['color'] = df.Set.map( lambda x: 'red' if x == 'Z' else 'green')
1000 loops, best of 3: 239 µs per loop
1000 loops, best of 3: 523 µs per loop
1000 loops, best of 3: 263 µs per loop
另一种实现这一目标的方法是
df['color'] = df.Set.map( lambda x: 'red' if x == 'Z' else 'green')