似乎应该有一种比以下更简单的方法:
import string
s = "string. With. Punctuation?" # Sample string
out = s.translate(string.maketrans("",""), string.punctuation)
有?
似乎应该有一种比以下更简单的方法:
import string
s = "string. With. Punctuation?" # Sample string
out = s.translate(string.maketrans("",""), string.punctuation)
有?
当前回答
我通常用这样的词:
>>> s = "string. With. Punctuation?" # Sample string
>>> import string
>>> for c in string.punctuation:
... s= s.replace(c,"")
...
>>> s
'string With Punctuation'
其他回答
下面是Python 3.5的一行代码:
import string
"l*ots! o(f. p@u)n[c}t]u[a'ti\"on#$^?/".translate(str.maketrans({a:None for a in string.punctuation}))
我喜欢使用这样的函数:
def scrub(abc):
while abc[-1] is in list(string.punctuation):
abc=abc[:-1]
while abc[0] is in list(string.punctuation):
abc=abc[1:]
return abc
考虑unicode。代码已在python3中检查。
from unicodedata import category
text = 'hi, how are you?'
text_without_punc = ''.join(ch for ch in text if not category(ch).startswith('P'))
为了方便使用,我总结了Python 2和Python 3中从字符串中删除标点符号的注意事项。有关详细说明,请参阅其他答案。
Python 2
import string
s = "string. With. Punctuation?"
table = string.maketrans("","")
new_s = s.translate(table, string.punctuation) # Output: string without punctuation
Python 3
import string
s = "string. With. Punctuation?"
table = str.maketrans(dict.fromkeys(string.punctuation)) # OR {key: None for key in string.punctuation}
new_s = s.translate(table) # Output: string without punctuation
为什么你们都不用这个?
''.join(filter(str.isalnum, s))
太慢了?