如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后,从他们的服务器重定向?

http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla

我尝试了以下路由配置,但:redirectParam没有捕获提到的参数:

<Router>
  <Route path="/" component={Main}>
    <Route path="signin" component={SignIn}>
      <Route path=":redirectParam" component={TwitterSsoButton} />
    </Route>
  </Route>
</Router>

当前回答

React路由器v3

使用React Router v3,你可以从this.props.location.search (?qs1=naisarg&qs2=parmar)获取查询字符串。例如,使用let params = queryString.parse(this.props.location.search),将给出{qs1: 'naisarg', qs2: 'parmar'}

React路由器v4

在React Router v4中,this.props.location.query不再存在。您需要使用this.props.location.search,并自己或使用现有的包(如query-string)解析查询参数。

例子

下面是一个使用React Router v4和query-string库的最小示例。

import { withRouter } from 'react-router-dom';
import queryString from 'query-string';
    
class ActivateAccount extends Component{
    someFunction(){
        let params = queryString.parse(this.props.location.search)
        ...
    }
    ...
}
export default withRouter(ActivateAccount);

理性的

React Router团队移除query属性的理由是:

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right". [...] The approach being taken for 4.0 is to strip out all the "batteries included" kind of features and get back to just basic routing. If you need query string parsing or async loading or Redux integration or something else very specific, then you can add that in with a library specifically for your use case. Less cruft is packed in that you don't need and you can customize things to your specific preferences and needs.

你可以在GitHub上找到完整的讨论。

其他回答

你也可以使用react-location-query包,例如:

  const [name, setName] = useLocationField("name", {
    type: "string",
    initial: "Rostyslav"
  });

  return (
    <div className="App">
      <h1>Hello {name}</h1>
      <div>
        <label>Change name: </label>
        <input value={name} onChange={e => setName(e.target.value)} />
      </div>
    </div>
  );

名称-获取价值 setName =设置值

这个包有很多选项,在Github上的文档中阅读更多

在需要访问可以使用的参数的组件中

this.props.location.state.from.search

这将显示整个查询字符串(在?标志)

React路由器v4

const urlParams = new URLSearchParams(this.props.location.search)
const key = urlParams.get('__firebase_request_key')

请注意,它目前还处于试验阶段。

查看浏览器兼容性:https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams/URLSearchParams#Browser_compatibility


最简单的解决方案!

在路由方面:

   <Route path="/app/someUrl/:id" exact component={binder} />

在react代码中:

componentDidMount() {
    var id = window.location.href.split('/')[window.location.href.split('/').length - 1];
    var queryString = "http://url/api/controller/" + id
    $.getJSON(queryString)
      .then(res => {
        this.setState({ data: res });
      });
  }

不是反应的方式,但我相信这个单行函数可以帮助你:)

const getQueryParams = (query = null) => [...(new URLSearchParams(query||window.location.search||"")).entries()].reduce((a,[k,v])=>(a[k]=v,a),{});

或:

const getQueryParams = (query = null) => (query||window.location.search.replace('?','')).split('&').map(e=>e.split('=').map(decodeURIComponent)).reduce((r,[k,v])=>(r[k]=v,r),{});

或完整版:

const getQueryParams = (query = null) => {
  return (
    (query || window.location.search.replace("?", ""))

      // get array of KeyValue pairs
      .split("&") 

      // Decode values
      .map((pair) => {
        let [key, val] = pair.split("=");

        return [key, decodeURIComponent(val || "")];
      })

      // array to object
      .reduce((result, [key, val]) => {
        result[key] = val;
        return result;
      }, {})
  );
};

例子: URL:…?= = 1 b =建发集团有限公司的测试 代码:

getQueryParams()
//=> {a: "1", b: "c", d: "test"}

getQueryParams('type=user&name=Jack&age=22')
//=> {type: "user", name: "Jack", age: "22" }