如何在Python中创建目录结构的zip存档?
当前回答
正如其他人所指出的,您应该使用zipfile。文档告诉哪些函数可用,但并没有真正解释如何使用它们压缩整个目录。我认为用一些示例代码来解释是最简单的:
import os
import zipfile
def zipdir(path, ziph):
# ziph is zipfile handle
for root, dirs, files in os.walk(path):
for file in files:
ziph.write(os.path.join(root, file),
os.path.relpath(os.path.join(root, file),
os.path.join(path, '..')))
with zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED) as zipf:
zipdir('tmp/', zipf)
其他回答
# import required python modules
# You have to install zipfile package using pip install
import os,zipfile
# Change the directory where you want your new zip file to be
os.chdir('Type your destination')
# Create a new zipfile ( I called it myfile )
zf = zipfile.ZipFile('myfile.zip','w')
# os.walk gives a directory tree. Access the files using a for loop
for dirnames,folders,files in os.walk('Type your directory'):
zf.write('Type your Directory')
for file in files:
zf.write(os.path.join('Type your directory',file))
要向生成的zip文件添加压缩,请查看此链接。
您需要更改:
zip = zipfile.ZipFile('Python.zip', 'w')
to
zip = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)
压缩文件或树(目录及其子目录)。
from pathlib import Path
from zipfile import ZipFile, ZIP_DEFLATED
def make_zip(tree_path, zip_path, mode='w', skip_empty_dir=False):
with ZipFile(zip_path, mode=mode, compression=ZIP_DEFLATED) as zf:
paths = [Path(tree_path)]
while paths:
p = paths.pop()
if p.is_dir():
paths.extend(p.iterdir())
if skip_empty_dir:
continue
zf.write(p)
要附加到现有存档,请传递mode='a',以创建新的存档mode='w'(上面的默认值)。因此,假设您希望将3个不同的目录树捆绑在同一归档文件下。
make_zip(path_to_tree1, path_to_arch, mode='w')
make_zip(path_to_tree2, path_to_arch, mode='a')
make_zip(path_to_file3, path_to_arch, mode='a')
这是一种现代方法,使用pathlib和上下文管理器。将文件直接放在zip文件中,而不是放在子文件夹中。
def zip_dir(filename: str, dir_to_zip: pathlib.Path):
with zipfile.ZipFile(filename, 'w', zipfile.ZIP_DEFLATED) as zipf:
# Use glob instead of iterdir(), to cover all subdirectories.
for directory in dir_to_zip.glob('**'):
for file in directory.iterdir():
if not file.is_file():
continue
# Strip the first component, so we don't create an uneeded subdirectory
# containing everything.
zip_path = pathlib.Path(*file.parts[1:])
# Use a string, since zipfile doesn't support pathlib directly.
zipf.write(str(file), str(zip_path))
我还有另一个代码示例可能会有所帮助,使用python3、pathlib和zipfile。它应该可以在任何操作系统中工作。
from pathlib import Path
import zipfile
from datetime import datetime
DATE_FORMAT = '%y%m%d'
def date_str():
"""returns the today string year, month, day"""
return '{}'.format(datetime.now().strftime(DATE_FORMAT))
def zip_name(path):
"""returns the zip filename as string"""
cur_dir = Path(path).resolve()
parent_dir = cur_dir.parents[0]
zip_filename = '{}/{}_{}.zip'.format(parent_dir, cur_dir.name, date_str())
p_zip = Path(zip_filename)
n = 1
while p_zip.exists():
zip_filename = ('{}/{}_{}_{}.zip'.format(parent_dir, cur_dir.name,
date_str(), n))
p_zip = Path(zip_filename)
n += 1
return zip_filename
def all_files(path):
"""iterator returns all files and folders from path as absolute path string
"""
for child in Path(path).iterdir():
yield str(child)
if child.is_dir():
for grand_child in all_files(str(child)):
yield str(Path(grand_child))
def zip_dir(path):
"""generate a zip"""
zip_filename = zip_name(path)
zip_file = zipfile.ZipFile(zip_filename, 'w')
print('create:', zip_filename)
for file in all_files(path):
print('adding... ', file)
zip_file.write(file)
zip_file.close()
if __name__ == '__main__':
zip_dir('.')
print('end!')
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