在c#中合并2个或更多字典(Dictionary<TKey, TValue>)的最佳方法是什么?
(像LINQ这样的3.0特性就可以了)。
我正在考虑一个方法签名,如下所示:
public static Dictionary<TKey,TValue>
Merge<TKey,TValue>(Dictionary<TKey,TValue>[] dictionaries);
or
public static Dictionary<TKey,TValue>
Merge<TKey,TValue>(IEnumerable<Dictionary<TKey,TValue>> dictionaries);
关于重复键的处理:在发生冲突的情况下,保存到字典中的值并不重要,只要它是一致的。
使用扩展方法合并。当存在重复的键时,它不会抛出异常,而是用第二个字典中的键替换这些键。
internal static class DictionaryExtensions
{
public static Dictionary<T1, T2> Merge<T1, T2>(this Dictionary<T1, T2> first, Dictionary<T1, T2> second)
{
if (first == null) throw new ArgumentNullException("first");
if (second == null) throw new ArgumentNullException("second");
var merged = new Dictionary<T1, T2>();
first.ToList().ForEach(kv => merged[kv.Key] = kv.Value);
second.ToList().ForEach(kv => merged[kv.Key] = kv.Value);
return merged;
}
}
用法:
Dictionary<string, string> merged = first.Merge(second);
如果有多个键(“右”键取代“左”键),这不会爆炸,可以合并一些字典(如果需要),并保留类型(限制它需要一个有意义的默认公共构造函数):
public static class DictionaryExtensions
{
// Works in C#3/VS2008:
// Returns a new dictionary of this ... others merged leftward.
// Keeps the type of 'this', which must be default-instantiable.
// Example:
// result = map.MergeLeft(other1, other2, ...)
public static T MergeLeft<T,K,V>(this T me, params IDictionary<K,V>[] others)
where T : IDictionary<K,V>, new()
{
T newMap = new T();
foreach (IDictionary<K,V> src in
(new List<IDictionary<K,V>> { me }).Concat(others)) {
// ^-- echk. Not quite there type-system.
foreach (KeyValuePair<K,V> p in src) {
newMap[p.Key] = p.Value;
}
}
return newMap;
}
}
@user166390的回答版本增加了一个IEqualityComparer参数,以允许不区分大小写的键比较。
public static T MergeLeft<T, K, V>(this T me, params Dictionary<K, V>[] others)
where T : Dictionary<K, V>, new()
{
return me.MergeLeft(me.Comparer, others);
}
public static T MergeLeft<T, K, V>(this T me, IEqualityComparer<K> comparer, params Dictionary<K, V>[] others)
where T : Dictionary<K, V>, new()
{
T newMap = Activator.CreateInstance(typeof(T), new object[] { comparer }) as T;
foreach (Dictionary<K, V> src in
(new List<Dictionary<K, V>> { me }).Concat(others))
{
// ^-- echk. Not quite there type-system.
foreach (KeyValuePair<K, V> p in src)
{
newMap[p.Key] = p.Value;
}
}
return newMap;
}