$Menu = new Admin_Model_DbTable_Menu(); 
$row = $Menu->fetchRow($Menu->select()->where('id = ?', $id));
$Addmenu = new Admin_Form_Addmenu(); 
$Addmenu->populate($row->toArray());

下面是一些代码:

function object_to_array($data) {
    if ((! is_array($data)) and (! is_object($data)))
        return 'xxx'; // $data;

    $result = array();

    $data = (array) $data;
    foreach ($data as $key => $value) {
        if (is_object($value))
            $value = (array) $value;
        if (is_array($value))
            $result[$key] = object_to_array($value);
        else
            $result[$key] = $value;
    }
    return $result;
}

这个答案只是这篇文章的不同答案的联合，但它是将具有简单值或数组的公有或私有属性的PHP对象转换为关联数组的解决方案…

function object_to_array($obj)
{
    if (is_object($obj))
        $obj = (array)$this->dismount($obj);
    if (is_array($obj)) {
        $new = array();
        foreach ($obj as $key => $val) {
            $new[$key] = $this->object_to_array($val);
        }
    }
    else
        $new = $obj;
    return $new;
}

function dismount($object)
{
    $reflectionClass = new \ReflectionClass(get_class($object));
    $array = array();
    foreach ($reflectionClass->getProperties() as $property) {
        $property->setAccessible(true);
        $array[$property->getName()] = $property->getValue($object);
        $property->setAccessible(false);
    }
    return $array;
}

我在Laravel Collections中测试了它，这工作得很好。

function objectToArray($data)
{
    if (is_array($data) || is_object($data))
    {
        $result = [];
        foreach ($data as $key => $value)
        {
            $result[$key] = (is_array($data) || is_object($data)) ? objectToArray($value) : $value;
        }
        return $result;
    }
    return $data;
}

@SpYk3HH的简短解决方案

function objectToArray($o)
{
    $a = array();
    foreach ($o as $k => $v)
        $a[$k] = (is_array($v) || is_object($v)) ? objectToArray($v): $v;

    return $a;
}

get_object_vars($obj)怎么样?如果您只想访问对象的公共属性，它似乎很有用。

看到get_object_vars。