获得当前系统时间毫秒的最佳方法是什么?
当前回答
获取当前日期的毫秒数。
斯威夫特4 +:
func currentTimeInMilliSeconds()-> Int
{
let currentDate = Date()
let since1970 = currentDate.timeIntervalSince1970
return Int(since1970 * 1000)
}
其他回答
到目前为止,我发现gettimeofday在iOS (iPad)上是一个很好的解决方案,当你想执行一些间隔评估(比如帧速率,渲染帧的计时……):
#include <sys/time.h>
struct timeval time;
gettimeofday(&time, NULL);
long millis = (time.tv_sec * 1000) + (time.tv_usec / 1000);
It may be useful to know about CodeTimestamps, which provide a wrapper around mach-based timing functions. This gives you nanosecond-resolution timing data - 1000000x more precise than milliseconds. Yes, a million times more precise. (The prefixes are milli, micro, nano, each 1000x more precise than the last.) Even if you don't need CodeTimestamps, check out the code (it's open source) to see how they use mach to get the timing data. This would be useful when you need more precision and want a faster method call than the NSDate approach.
http://eng.pulse.me/line-by-line-speed-analysis-for-ios-apps/
这基本上和@TristanLorach发布的答案是一样的,只是为Swift 3重新编码:
/// Method to get Unix-style time (Java variant), i.e., time since 1970 in milliseconds. This
/// copied from here: http://stackoverflow.com/a/24655601/253938 and here:
/// http://stackoverflow.com/a/7885923/253938
/// (This should give good performance according to this:
/// http://stackoverflow.com/a/12020300/253938 )
///
/// Note that it is possible that multiple calls to this method and computing the difference may
/// occasionally give problematic results, like an apparently negative interval or a major jump
/// forward in time. This is because system time occasionally gets updated due to synchronization
/// with a time source on the network (maybe "leap second"), or user setting the clock.
public static func currentTimeMillis() -> Int64 {
var darwinTime : timeval = timeval(tv_sec: 0, tv_usec: 0)
gettimeofday(&darwinTime, nil)
return (Int64(darwinTime.tv_sec) * 1000) + Int64(darwinTime.tv_usec / 1000)
}
func currentmicrotimeTimeMillis() -> Int64{
let nowDoublevaluseis = NSDate().timeIntervalSince1970
return Int64(nowDoublevaluseis*1000)
}
如果你不想包含Quartz框架,[NSDate timeintervalsincerely eferencedate]是另一个选项。它返回一个double,表示秒数。
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