如下所示,Javascript中的"0"为false:
>>> "0" == false
true
>>> false == "0"
true
那么下面为什么打印“哈”呢?
>>> if ("0") console.log("ha")
ha
如下所示,Javascript中的"0"为false:
>>> "0" == false
true
>>> false == "0"
true
那么下面为什么打印“哈”呢?
>>> if ("0") console.log("ha")
ha
当前回答
这就是为什么你应该尽可能使用严格相等===或严格相等!== =的原因
"100" == 100
为True,因为这只检查值,而不是数据类型
"100" === 100
检查值和数据类型
其他回答
==相等运算符在将参数转换为数字后求值。 因此字符串0" 0"被转换为数字数据类型,布尔值false被转换为数字0。 所以
"0" == false // true
同样适用于'
False == "0" //true
===严格的相等性检查使用原始数据类型计算参数
"0" === false // false,因为"0"是字符串,false是布尔值
同样适用于
False === "0" // False
In
if(“0”) console.log(“ha”);
String "0"不与任何参数进行比较,并且String在与任何参数进行比较之前都是真值。 就像
if (true) console.log (" ha ");
But
If (0) console.log("ha");//空控制台行,因为0是假的
`
我也有同样的问题,我找到了一个可行的解决方案如下:
原因是
if (0) means false, if (-1, or any other number than 0) means true. following value are not truthy, null, undefined, 0, ""empty string, false, NaN
永远不要使用id之类的数字类型
if (id) {}
对于可能值为0的id类型,我们不能使用if (id){},因为if(0)将意味着false,无效,这是我们想要的,它意味着有效为true id数。
所以对于id类型,我们必须使用以下方法:
if ((Id !== undefined) && (Id !== null) && (Id !== "")){
} else {
}
对于其他字符串类型,我们可以使用if (string){},因为null, undefined,空字符串都将计算为false,这是正确的。
if (string_type_variable) { }
The "if" expression tests for truthiness, while the double-equal tests for type-independent equivalency. A string is always truthy, as others here have pointed out. If the double-equal were testing both of its operands for truthiness and then comparing the results, then you'd get the outcome you were intuitively assuming, i.e. ("0" == true) === true. As Doug Crockford says in his excellent JavaScript: the Good Parts, "the rules by which [== coerces the types of its operands] are complicated and unmemorable.... The lack of transitivity is alarming." It suffices to say that one of the operands is type-coerced to match the other, and that "0" ends up being interpreted as a numeric zero, which is in turn equivalent to false when coerced to boolean (or false is equivalent to zero when coerced to a number).
显示问题的表格:
和= =
这个故事的寓意使用===
表生成credit: https://github.com/dorey/JavaScript-Equality-Table
在JS中,“==”符号不检查变量的类型。因此,“0”= 0 = false(在JS中为0 = false),在这种情况下将返回true,但如果使用“===”,结果将为false。
当你使用"if"时,在以下情况下它将是"false":
[0, false, '', null, undefined, NaN] // null = undefined, 0 = false
So
if("0") = if( ("0" !== 0) && ("0" !== false) && ("0" !== "") && ("0" !== null) && ("0" !== undefined) && ("0" !== NaN) )
= if(true && true && true && true && true && true)
= if(true)