如何通过Java读取文件夹中的所有文件?这与哪个API无关。


当前回答

java.io.FileFilter的用法很好,见https://stackoverflow.com/a/286001/146745

File fl = new File(dir);
File[] files = fl.listFiles(new FileFilter() {          
    public boolean accept(File file) {
        return file.isFile();
    }
});

其他回答

void getFiles(){
        String dirPath = "E:/folder_name";
        File dir = new File(dirPath);
        String[] files = dir.list();
        if (files.length == 0) {
            System.out.println("The directory is empty");
        } else {
            for (String aFile : files) {
                System.out.println(aFile);
            }
        }
    }

给定一个baseDir,列出它下面的所有文件和目录,迭代编写。

    public static List<File> listLocalFilesAndDirsAllLevels(File baseDir) {

    List<File>  collectedFilesAndDirs   = new ArrayList<>();
    Deque<File> remainingDirs           = new ArrayDeque<>();

    if(baseDir.exists()) {
        remainingDirs.add(baseDir);

        while(!remainingDirs.isEmpty()) {
            File dir = remainingDirs.removeLast();
            List<File> filesInDir = Arrays.asList(dir.listFiles());
            for(File fileOrDir : filesInDir)  {
                collectedFilesAndDirs.add(fileOrDir);
                if(fileOrDir.isDirectory()) {
                    remainingDirs.add(fileOrDir);
                }
            }
        }
    }

    return collectedFilesAndDirs;
}
import java.io.File;
import java.util.ArrayList;
import java.util.List;

public class AvoidNullExp {

public static void main(String[] args) {

    List<File> fileList =new ArrayList<>();
     final File folder = new File("g:/master");
     new AvoidNullExp().listFilesForFolder(folder, fileList);
}

    public void listFilesForFolder(final File folder,List<File> fileList) {
        File[] filesInFolder = folder.listFiles();
        if (filesInFolder != null) {
            for (final File fileEntry : filesInFolder) {
                if (fileEntry.isDirectory()) {
                    System.out.println("DIR : "+fileEntry.getName());
                listFilesForFolder(fileEntry,fileList);
            } else {
                System.out.println("FILE : "+fileEntry.getName());
                fileList.add(fileEntry);
            }
         }
        }
     }


}

从Test文件夹中列出类路径内的文件

import java.io.File;
import java.io.IOException;

public class Hello {

    public static void main(final String[] args) throws IOException {

        System.out.println("List down all the files present on the server directory");
        File file1 = new File("/prog/FileTest/src/Test");
        File[] files = file1.listFiles();
        if (null != files) {
            for (int fileIntList = 0; fileIntList < files.length; fileIntList++) {
                String ss = files[fileIntList].toString();
                if (null != ss && ss.length() > 0) {
                    System.out.println("File: " + (fileIntList + 1) + " :" + ss.substring(ss.lastIndexOf("\\") + 1, ss.length()));
                }
            }
        }


    }


}

这将很好地工作:

private static void addfiles(File inputValVal, ArrayList<File> files)
{
  if(inputVal.isDirectory())
  {
    ArrayList <File> path = new ArrayList<File>(Arrays.asList(inputVal.listFiles()));

    for(int i=0; i<path.size(); ++i)
    {
        if(path.get(i).isDirectory())
        {
            addfiles(path.get(i),files);
        }
        if(path.get(i).isFile())
        {
            files.add(path.get(i));
        }
     }

    /*  Optional : if you need to have the counts of all the folders and files you can create 2 global arrays 
        and store the results of the above 2 if loops inside these arrays */
   }

   if(inputVal.isFile())
   {
     files.add(inputVal);
   }

}