如何通过Java读取文件夹中的所有文件?这与哪个API无关。


当前回答

import java.io.File;


public class ReadFilesFromFolder {
  public static File folder = new File("C:/Documents and Settings/My Documents/Downloads");
  static String temp = "";

  public static void main(String[] args) {
    // TODO Auto-generated method stub
    System.out.println("Reading files under the folder "+ folder.getAbsolutePath());
    listFilesForFolder(folder);
  }

  public static void listFilesForFolder(final File folder) {

    for (final File fileEntry : folder.listFiles()) {
      if (fileEntry.isDirectory()) {
        // System.out.println("Reading files under the folder "+folder.getAbsolutePath());
        listFilesForFolder(fileEntry);
      } else {
        if (fileEntry.isFile()) {
          temp = fileEntry.getName();
          if ((temp.substring(temp.lastIndexOf('.') + 1, temp.length()).toLowerCase()).equals("txt"))
            System.out.println("File= " + folder.getAbsolutePath()+ "\\" + fileEntry.getName());
        }

      }
    }
  }
}

其他回答

package com.commandline.folder;

import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.stream.Stream;

public class FolderReadingDemo {
    public static void main(String[] args) {
        String str = args[0];
        final File folder = new File(str);
//      listFilesForFolder(folder);
        listFilesForFolder(str);
    }

    public static void listFilesForFolder(String str) {
        try (Stream<Path> paths = Files.walk(Paths.get(str))) {
            paths.filter(Files::isRegularFile).forEach(System.out::println);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    public static void listFilesForFolder(final File folder) {
        for (final File fileEntry : folder.listFiles()) {
            if (fileEntry.isDirectory()) {
                listFilesForFolder(fileEntry);
            } else {
                System.out.println(fileEntry.getName());
            }
        }
    }

}

您可以将文件路径设置为参数,并创建包含所有文件路径的列表,而不必手动将其放入列表中。然后使用for循环和读取器。txt文件示例:

public static void main(String[] args) throws IOException{    
File[] files = new File(args[0].replace("\\", "\\\\")).listFiles(new FilenameFilter() { @Override public boolean accept(File dir, String name) { return name.endsWith(".txt"); } });
    ArrayList<String> filedir = new ArrayList<String>();
    String FILE_TEST = null;
    for (i=0; i<files.length; i++){
            filedir.add(files[i].toString());
            CSV_FILE_TEST=filedir.get(i) 

        try(Reader testreader = Files.newBufferedReader(Paths.get(FILE_TEST));
            ){
              //write your stuff
                 }}}

我们可以使用org.apache.commons.io.FileUtils,使用listFiles()方法来读取给定文件夹中的所有文件。

eg:

FileUtils.listFiles(directory, new String[] {"ext1", "ext2"}, true)

这将读取给定目录中具有给定扩展名的所有文件,我们可以在数组中传递多个扩展名,并在文件夹中递归读取(true参数)。

防止listFiles()函数的nullpointerexception,并递归地从子目录中获取所有文件。

 public void listFilesForFolder(final File folder,List<File> fileList) {
    File[] filesInFolder = folder.listFiles();
    if (filesInFolder != null) {
        for (final File fileEntry : filesInFolder) {
            if (fileEntry.isDirectory()) {
            listFilesForFolder(fileEntry,fileList);
        } else {
            fileList.add(fileEntry);
        }
     }
    }
 }

 List<File> fileList = new List<File>();
 final File folder = new File("/home/you/Desktop");
 listFilesForFolder(folder);
    static File mainFolder = new File("Folder");
    public static void main(String[] args) {

        lf.getFiles(lf.mainFolder);
    }
    public void getFiles(File f) {
        File files[];
        if (f.isFile()) {
            String name=f.getName();

        } else {
            files = f.listFiles();
            for (int i = 0; i < files.length; i++) {
                getFiles(files[i]);
            }
        }
    }