假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
当前回答
我在寻找loosy拆分,例如PHP的分解,其中空序列包含在结果数组中,这对我很有用:
"First ".split(separator: " ", maxSplits: 1, omittingEmptySubsequences: false)
输出:
["First", ""]
其他回答
我有一个场景,其中多个控制字符可以出现在我要拆分的字符串中。我只是让苹果处理这一部分,而不是维护一系列这些。
以下功能适用于iOS 10上的Swift 3.0.1:
let myArray = myString.components(separatedBy: .controlCharacters)
在Swift 4.2和Xcode 10中
//This is your str
let str = "This is my String" //Here replace with your string
选项1
let items = str.components(separatedBy: " ")//Here replase space with your value and the result is Array.
//Direct single line of code
//let items = "This is my String".components(separatedBy: " ")
let str1 = items[0]
let str2 = items[1]
let str3 = items[2]
let str4 = items[3]
//OutPut
print(items.count)
print(str1)
print(str2)
print(str3)
print(str4)
print(items.first!)
print(items.last!)
选项2
let items = str.split(separator: " ")
let str1 = String(items.first!)
let str2 = String(items.last!)
//Output
print(items.count)
print(items)
print(str1)
print(str2)
选项3
let arr = str.split {$0 == " "}
print(arr)
选项4
let line = "BLANCHE: I don't want realism. I want magic!"
print(line.split(separator: " "))
// Prints "["BLANCHE:", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]"
通过Apple文档。。。。
let line = "BLANCHE: I don't want realism. I want magic!"
print(line.split(separator: " "))
// Prints "["BLANCHE:", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]"
print(line.split(separator: " ", maxSplits: 1))//This can split your string into 2 parts
// Prints "["BLANCHE:", " I don\'t want realism. I want magic!"]"
print(line.split(separator: " ", maxSplits: 2))//This can split your string into 3 parts
print(line.split(separator: " ", omittingEmptySubsequences: false))//array contains empty strings where spaces were repeated.
// Prints "["BLANCHE:", "", "", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]"
print(line.split(separator: " ", omittingEmptySubsequences: true))//array not contains empty strings where spaces were repeated.
print(line.split(separator: " ", maxSplits: 4, omittingEmptySubsequences: false))
print(line.split(separator: " ", maxSplits: 3, omittingEmptySubsequences: true))
只需在fullName上调用componentsSeparatedByString方法
import Foundation
var fullName: String = "First Last"
let fullNameArr = fullName.componentsSeparatedByString(" ")
var firstName: String = fullNameArr[0]
var lastName: String = fullNameArr[1]
Swift 3更新+
import Foundation
let fullName = "First Last"
let fullNameArr = fullName.components(separatedBy: " ")
let name = fullNameArr[0]
let surname = fullNameArr[1]
大多数这些答案都假设输入包含一个空格,而不是空白,并且只有一个空格。如果你能安全地做出这样的假设,那么(来自bennett的)公认的答案是相当优雅的,也是我在可能的时候会采用的方法。
当我们无法做出这一假设时,一个更稳健的解决方案需要涵盖以下大多数答案没有考虑的情况:
制表符/换行符/空格(空白),包括重复出现的字符前导/尾随空格Apple/Linux(\n)和Windows(\r\n)换行符
为了涵盖这些情况,此解决方案使用正则表达式将所有空格(包括重复出现的字符和Windows换行符)转换为单个空格,然后修剪,然后拆分为单个空格:
斯威夫特3:
let searchInput = " First \r\n \n \t\t\tMiddle Last "
let searchTerms = searchInput
.replacingOccurrences(
of: "\\s+",
with: " ",
options: .regularExpression
)
.trimmingCharacters(in: .whitespaces)
.components(separatedBy: " ")
// searchTerms == ["First", "Middle", "Last"]
只有拆分才是正确的答案,这里有两个以上空格的差异。
雨燕5
var temp = "Hello world ni hao"
let arr = temp.components(separatedBy: .whitespacesAndNewlines)
// ["Hello", "world", "", "", "", "", "ni", "hao"]
let arr2 = temp.components(separatedBy: " ")
// ["Hello", "world", "", "", "", "", "ni", "hao"]
let arr3 = temp.split(whereSeparator: {$0 == " "})
// ["Hello", "world", "ni", "hao"]