假设我这里有一个字符串：
var fullName: String = "First Last"
我想在空白处拆分字符串，并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外，有时用户可能没有姓氏。
当前回答
我在寻找loosy拆分，例如PHP的分解，其中空序列包含在结果数组中，这对我很有用：
"First ".split(separator: " ", maxSplits: 1, omittingEmptySubsequences: false)
输出：
["First", ""]
其他回答
Swift 4、Xcode 10和iOS 12更新100%工作
let fullName = "First Last"
let fullNameArr = fullName.components(separatedBy: " ")
let firstName = fullNameArr[0] //First
let lastName = fullNameArr[1] //Last
有关更多信息，请参阅此处的Apple文档。
这是用于swift 4.2在20181206 1610的字符串和CSV文件
var dataArray : [[String]] = []
let path = Bundle.main.path(forResource: "csvfilename", ofType: "csv")
let url = URL(fileURLWithPath: path!)
do {
let data = try Data(contentsOf: url)
let content = String(data: data, encoding: .utf8)
let parsedCSV = content?.components(separatedBy: "\r\n").map{ $0.components(separatedBy: ";") }
for line in parsedCSV!
{
dataArray.append(line)
}
}
catch let jsonErr {
print("\n Error read CSV file: \n ", jsonErr)
}
print("\n MohNada 20181206 1610 - The final result is \(dataArray) \n ")
Xcode 8.0/Swift 3
let fullName = "First Last"
var fullNameArr = fullName.components(separatedBy: " ")
var firstname = fullNameArr[0] // First
var lastname = fullNameArr[1] // Last
漫长的道路：
var fullName: String = "First Last"
fullName += " " // this will help to see the last word
var newElement = "" //Empty String
var fullNameArr = [String]() //Empty Array
for Character in fullName.characters {
if Character == " " {
fullNameArr.append(newElement)
newElement = ""
} else {
newElement += "\(Character)"
}
}
var firsName = fullNameArr[0] // First
var lastName = fullNameArr[1] // Last
Swift的方法是使用全局拆分函数，如下所示：
var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
var firstName: String = fullNameArr[0]
var lastName: String? = fullNameArr.count > 1 ? fullNameArr[1] : nil
使用Swift 2
在Swift 2中，由于引入了内部CharacterView类型，拆分的使用变得有点复杂。这意味着String不再采用SequenceType或CollectionType协议，您必须改为使用.characts属性来访问String实例的CharacterView类型表示。（注意：CharacterView确实采用SequenceType和CollectionType协议）。
let fullName = "First Last"
let fullNameArr = fullName.characters.split{$0 == " "}.map(String.init)
// or simply:
// let fullNameArr = fullName.characters.split{" "}.map(String.init)
fullNameArr[0] // First
fullNameArr[1] // Last
作为WMios答案的替代方案，您还可以使用componentsSeparatedByCharactersSet，这在分隔符（空格、逗号等）较多的情况下非常方便。
使用您的特定输入：
let separators = NSCharacterSet(charactersInString: " ")
var fullName: String = "First Last";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["First", "Last"]
使用多个分隔符：
let separators = NSCharacterSet(charactersInString: " ,")
var fullName: String = "Last, First Middle";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["Last", "First", "Middle"]
