是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?

没有jQuery,没有其他框架-只有纯JavaScript:)


当前回答

Use:

Object.keys(obj).reduce(function(a,k){a.push(k+'='+encodeURIComponent(obj[k]));return a},[]).join('&')

我喜欢这句话,但我敢打赌,如果它在语义上符合公认的答案,它将是一个更受欢迎的答案:

function serialize( obj ) {
    let str = '?' + Object.keys(obj).reduce(function(a, k){
        a.push(k + '=' + encodeURIComponent(obj[k]));
        return a;
    }, []).join('&');
    return str;
}

其他回答

可以将具有未定义属性的对象传递给此函数。如果属性存在,它将被转换为查询字符串并返回查询字符串。

函数convertToQueryString(props) { const objQueryString ={…道具}; for (objQueryString中的const键){ If (!key) { 删除objQueryString(例子); } } const params = JSON.stringify(objQueryString); Const qs =参数 .replace (/[/''""{}]/ 克,”) .replace (/ [:] / g, ' = ') .replace (/, / g, ' & '); console.log (qs) 返回qs; } convertToQueryString({order: undefined, limit: 5, page: 1})

参考答案@user187291,添加“isArray”作为参数,使要转换的JSON嵌套数组。

data : {
                    staffId : "00000001",
                    Detail : [ {
                        "identityId" : "123456"
                    }, {
                        "identityId" : "654321"
                    } ],

                }

要得到结果:

staffId=00000001&Detail[0].identityId=123456&Detail[1].identityId=654321

serialize = function(obj, prefix, isArray) {
        var str = [],p = 0;
        for (p in obj) {
            if (obj.hasOwnProperty(p)) {
                var k, v;
                if (isArray)
                    k = prefix ? prefix + "[" + p + "]" : p, v = obj[p];
                else
                    k = prefix ? prefix + "." + p + "" : p, v = obj[p];

                if (v !== null && typeof v === "object") {
                    if (Array.isArray(v)) {
                        serialize(v, k, true);
                    } else {
                        serialize(v, k, false);
                    }
                } else {
                    var query = k + "=" + v;
                    str.push(query);
                }
            }
        }
        return str.join("&");
    };

    serialize(data, "prefix", false);

我为此写了一个包:object-query-string:)

它支持嵌套对象、数组、自定义编码函数等。它是轻量级的,不支持jquery。

// TypeScript
import { queryString } from 'object-query-string';

// Node.js
const { queryString } = require("object-query-string");

const query = queryString({
    filter: {
        brands: ["Audi"],
        models: ["A4", "A6", "A8"],
        accidentFree: true
    },
    sort: 'mileage'
});

返回

filter[brands][]=Audi&filter[models][]=A4&filter[models][]=A6&filter[models][]=A8&filter[accidentFree]=true&sort=milage
 let data = {
    id:1,
    name:'Newuser'
    };
const getqueryParam = data => {
  let datasize = Object.keys(data).length;
  let initial = '?';

  Object.keys(data).map(function (key, index) {
    initial = initial.concat(`${key}=${data[key]}`);
    index != datasize - 1 && (initial = initial.concat('&'));
  });
  console.log(initial, 'MyqueryString');
  return initial;
};

console.log(getqueryParam(data))//You can get the query string here

If you have baseUrl means to get full query use 

baseUrl concat (getqueryParam(数据)。

PHP符号的TypeScript版本(没有URL转义版本)

/**
 * Converts an object into a Cookie-like string.
 * @param toSerialize object or array to be serialized
 * @param prefix used in deep objects to describe the final query parameter
 * @returns ampersand separated key=value pairs
 *
 * Example:
 * ```js
 * serialize({hello:[{world: "nice"}]}); // outputs  "hello[0][world]=nice"
 * ```
 * ---
 * Adapted to TS from a StackOverflow answer https://stackoverflow.com/a/1714899/4537906
 */
const serialize = (toSerialize: unknown = {}, prefix?: string) => {
  const keyValuePairs = [];

  Object.keys(toSerialize).forEach((attribute) => {
    if (Object.prototype.hasOwnProperty.call(toSerialize, attribute)) {
      const key = prefix ? `${prefix}[${attribute}]` : attribute;
      const value = toSerialize[attribute];
      const toBePushed =
        value !== null && typeof value === "object"
          ? serialize(value, key)
          : `${key}=${value}`;
      keyValuePairs.push(toBePushed);
    }
  });

  return keyValuePairs.join("&");
};