我们如何通过javascript窗口打开一个弹出窗口的中心。打开功能上的屏幕中心变量，以当前选择的屏幕分辨率?
当前回答
我的ES6 JavaScript版本。 工作良好的铬和铬双屏幕设置。
function openCenteredWindow({url, width, height}) {
const pos = {
x: (screen.width / 2) - (width / 2),
y: (screen.height/2) - (height / 2)
};
const features = `width=${width} height=${height} left=${pos.x} top=${pos.y}`;
return window.open(url, '_blank', features);
}
例子
openCenteredWindow({
url: 'https://stackoverflow.com/',
width: 500,
height: 600
}).focus();
其他回答
function fnPopUpWindow(pageId) {
popupwindow("hellowWorld.php?id="+pageId, "printViewer", "500", "300");
}
function popupwindow(url, title, w, h) {
var left = Math.round((screen.width/2)-(w/2));
var top = Math.round((screen.height/2)-(h/2));
return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, '
+ 'menubar=no, scrollbars=yes, resizable=no, copyhistory=no, width=' + w
+ ', height=' + h + ', top=' + top + ', left=' + left);
}
<a href="javascript:void(0);" onclick="fnPopUpWindow('10');">Print Me</a>
注意:你必须使用数学。Round用于获得宽度和高度的精确整数。
试着这样做:
function popupwindow(url, title, w, h) {
var left = (screen.width/2)-(w/2);
var top = (screen.height/2)-(h/2);
return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
}
我的ES6 JavaScript版本。 工作良好的铬和铬双屏幕设置。
function openCenteredWindow({url, width, height}) {
const pos = {
x: (screen.width / 2) - (width / 2),
y: (screen.height/2) - (height / 2)
};
const features = `width=${width} height=${height} left=${pos.x} top=${pos.y}`;
return window.open(url, '_blank', features);
}
例子
openCenteredWindow({
url: 'https://stackoverflow.com/',
width: 500,
height: 600
}).focus();
这取决于你的屏幕大小
<html>
<body>
<button onclick="openfunc()">Click here to open window at center</button>
<script>
function openfunc() {
windowWidth = 800;
windowHeight = 720;
var left = (screen.width - windowWidth) / 2;
var top = (screen.height - windowHeight) / 4;
var myWindow = window.open("https://www.google.com",'_blank','width=' + windowWidth + ', height=' + windowHeight + ', top=' + top + ', left=' + left);
}
</script>
</body>
</html>
由于在多显示器设置中确定当前屏幕中心的复杂性，一个更简单的选择是将弹出窗口置于父窗口的中央。简单地将父窗口作为另一个参数传递:
function popupWindow(url, windowName, win, w, h) {
const y = win.top.outerHeight / 2 + win.top.screenY - ( h / 2);
const x = win.top.outerWidth / 2 + win.top.screenX - ( w / 2);
return win.open(url, windowName, `toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width=${w}, height=${h}, top=${y}, left=${x}`);
}
实现:
popupWindow('google.com', 'test', window, 200, 100);
