下面的代码只删除它在web目录中的第一个文件。我想删除web目录中的所有文件和文件夹，并保留web目录。我该怎么做呢?
- name: remove web dir contents
file: path='/home/mydata/web/{{ item }}' state=absent
with_fileglob:
- /home/mydata/web/*
注意:我已经尝试了rm -rf使用命令和shell，但他们不工作。也许我用错了。
任何正确方向上的帮助都将不胜感激。
我使用ansible 2.1.0.0
当前回答
- name: Files to delete search
find:
paths: /home/mydata/web/
file_type: any
register: files_to_delete
- name: Deleting files to delete
file:
path: '{{ item.path }}'
state: absent
with_items: "{{ files_to_delete.files }}"
其他回答
而Ansible仍在讨论实现state = empty https://github.com/ansible/ansible-modules-core/issues/902
my_folder: "/home/mydata/web/"
empty_path: "/tmp/empty"
- name: "Create empty folder for wiping."
file:
path: "{{ empty_path }}"
state: directory
- name: "Wipe clean {{ my_folder }} with empty folder hack."
synchronize:
mode: push
#note the backslash here
src: "{{ empty_path }}/"
dest: "{{ nl_code_path }}"
recursive: yes
delete: yes
delegate_to: "{{ inventory_hostname }}"
不过请注意，无论如何，使用synchronize你应该能够正确地同步你的文件(使用delete)。
- name: delete old data and clean cache
file:
path: "{{ item[0] }}"
state: "{{ item[1] }}"
with_nested:
- [ "/data/server/{{ app_name }}/webapps/", "/data/server/{{ app_name }}/work/" ]
- [ "absent", "directory" ]
ignore_errors: yes
使用文件glob也可以。你发布的代码有语法错误。我已经修改和测试这应该工作。
- name: remove web dir contents
file:
path: "{{ item }}"
state: absent
with_fileglob:
- "/home/mydata/web/*"
- name: Files to delete search
find:
paths: /home/mydata/web/
file_type: any
register: files_to_delete
- name: Deleting files to delete
file:
path: '{{ item.path }}'
state: absent
with_items: "{{ files_to_delete.files }}"
- name: Delete content & directory
file:
state: absent
path: /home/mydata/web/
注意:这也会删除目录。
