我试图创建一个通用扩展，使用'TryParse'来检查字符串是否为给定类型:
public static bool Is<T>(this string input)
{
T notUsed;
return T.TryParse(input, out notUsed);
}
这将无法编译，因为它无法解析符号TryParse
据我所知，“TryParse”不是任何接口的一部分。
这有可能吗?
更新:
使用以下我想出的答案:
public static bool Is<T>(this string input)
{
try
{
TypeDescriptor.GetConverter(typeof(T)).ConvertFromString(input);
}
catch
{
return false;
}
return true;
}
它工作得很好，但我认为以这种方式使用异常对我来说不合适。
更新2:
修改为传递类型而不是使用泛型:
public static bool Is(this string input, Type targetType)
{
try
{
TypeDescriptor.GetConverter(targetType).ConvertFromString(input);
return true;
}
catch
{
return false;
}
}
我把一堆想法放在一起，最终得到了一个非常简短的解决方案。
这是一个字符串的扩展方法
enter code here
我在数值类型上使用与TryParse方法相同的足迹
/// <summary>
/// string.TryParse()
///
/// This generic extension method will take a string
/// make sure it is not null or empty
/// make sure it represents some type of number e.g. "123" not "abc"
/// It then calls the appropriate converter for the type of T
/// </summary>
/// <typeparam name="T">The type of the desired retrunValue e.g. int, float, byte, decimal...</typeparam>
/// <param name="targetText">The text to be converted</param>
/// <param name="returnValue">a populated value of the type T or the default(T) value which is likely to be 0</param>
/// <returns>true if the string was successfully parsed and converted otherwise false</returns>
/// <example>
/// float testValue = 0;
/// if ( "1234".TryParse<float>( out testValue ) )
/// {
/// doSomethingGood();
/// }
/// else
/// {
/// handleTheBadness();
/// }
/// </example>
public static bool TryParse<T>(this string targetText, out T returnValue )
{
bool returnStatus = false;
returnValue = default(T);
//
// make sure the string is not null or empty and likely a number...
// call whatever you like here or just leave it out - I would
// at least make sure the string was not null or empty
//
if ( ValidatedInputAnyWayYouLike(targetText) )
{
//
// try to catch anything that blows up in the conversion process...
//
try
{
var type = typeof(T);
var converter = TypeDescriptor.GetConverter(type);
if (converter != null && converter.IsValid(targetText))
{
returnValue = (T)converter.ConvertFromString(targetText);
returnStatus = true;
}
}
catch
{
// just swallow the exception and return the default values for failure
}
}
return (returnStatus);
}
'''
如果你设置使用TryParse，你可以使用反射并像这样做:
public static bool Is<T>(this string input)
{
var type = typeof (T);
var temp = default(T);
var method = type.GetMethod(
"TryParse",
new[]
{
typeof (string),
Type.GetType(string.Format("{0}&", type.FullName))
});
return (bool) method.Invoke(null, new object[] {input, temp});
}
有点晚了，但这是我想到的。无异常，一次性(每种类型)反射。
public static class Extensions {
public static T? ParseAs<T>(this string str) where T : struct {
T val;
return GenericHelper<T>.TryParse(str, out val) ? val : default(T?);
}
public static T ParseAs<T>(this string str, T defaultVal) {
T val;
return GenericHelper<T>.TryParse(str, out val) ? val : defaultVal;
}
private static class GenericHelper<T> {
public delegate bool TryParseFunc(string str, out T result);
private static TryParseFunc tryParse;
public static TryParseFunc TryParse {
get {
if (tryParse == null)
tryParse = Delegate.CreateDelegate(
typeof(TryParseFunc), typeof(T), "TryParse") as TryParseFunc;
return tryParse;
}
}
}
}
额外的类是必需的，因为泛型类中不允许使用扩展方法。这允许简单的使用，如下所示，并且只在第一次使用类型时命中反射。
"5643".ParseAs<int>()
