我这样做(检索一个特定的get-parameter，这里'parameterName'):

var parameterValue = decodeURIComponent(window.location.search.match(/(\?|&)parameterName\=([^&]*)/)[2]);

一种更花哨的方法::)

var options = window.location.search.slice(1)
                      .split('&')
                      .reduce(function _reduce (/*Object*/ a, /*String*/ b) {
                        b = b.split('=');
                        a[b[0]] = decodeURIComponent(b[1]);
                        return a;
                      }, {});

这个函数使用正则表达式，如果参数不存在或没有任何值，则返回null:

function getQuery(q) {
   return (window.location.search.match(new RegExp('[?&]' + q + '=([^&]+)')) || [, null])[1];
}

在这里，我用这段代码将GET参数转换为一个对象，以便更容易地使用它们。

// Get Nav URL
function getNavUrl() {
    // Get URL
    return window.location.search.replace("?", "");
};

function getParameters(url) {
    // Params obj
    var params = {};
    // To lowercase
    url = url.toLowerCase();
    // To array
    url = url.split('&');

    // Iterate over URL parameters array
    var length = url.length;
    for(var i=0; i<length; i++) {
        // Create prop
        var prop = url[i].slice(0, url[i].search('='));
        // Create Val
        var value = url[i].slice(url[i].search('=')).replace('=', '');
        // Params New Attr
        params[prop] = value;
    }
    return params;
};

// Call of getParameters
console.log(getParameters(getNavUrl()));

这个解决方案处理URL解码:

var params = function() {
    function urldecode(str) {
        return decodeURIComponent((str+'').replace(/\+/g, '%20'));
    }

    function transformToAssocArray( prmstr ) {
        var params = {};
        var prmarr = prmstr.split("&");
        for ( var i = 0; i < prmarr.length; i++) {
            var tmparr = prmarr[i].split("=");
            params[tmparr[0]] = urldecode(tmparr[1]);
        }
        return params;
    }

    var prmstr = window.location.search.substr(1);
    return prmstr != null && prmstr != "" ? transformToAssocArray(prmstr) : {};
}();

用法:

console.log('someParam GET value is', params['someParam']);

你应该使用URL和URLSearchParams本地函数:

let url = new url ("https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8&q=mdn%20query%20string") let params = new URLSearchParams(url.search); Let sourceid = params.get('sourceid') // 'chrome-instant' Let q = params.get('q') // 'mdn查询字符串' 让ie = params.has('ie') // true params.append(“平”、“乒乓球”) console.log (sourceid) console.log (q) console.log (ie) console.log (params.toString ()) console.log (params.get(“平”))

https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams https://polyfill.io/v2/docs/features/