Try:

String[] val = { "helloword1", "orange", "grape", "pear" };
String sep = "";
string stringToCheck = "word1";

bool match = String.Join(sep,val).Contains(stringToCheck);
bool anothermatch = val.Any(s => s.Contains(stringToCheck));

使用LINQ和方法组将是最快和更紧凑的方法。

var arrayA = new[] {"element1", "element2"};
var arrayB = new[] {"element2", "element3"};

if (arrayB.Any(arrayA.Contains)) 
    return true;

int result = Array.BinarySearch(list.ToArray(), typedString, StringComparer.OrdinalIgnoreCase);

您也可以尝试这个解决方案。

string[] nonSupportedExt = { ".3gp", ".avi", ".opus", ".wma", ".wav", ".m4a", ".ac3", ".aac", ".aiff" };
        
bool valid = Array.Exists(nonSupportedExt,E => E == ".Aac".ToLower());

方法如下:

using System.Linq;

if(stringArray.Any(stringToCheck.Contains))

/* or a bit longer: (stringArray.Any(s => stringToCheck.Contains(s))) */

这个函数检查stringToCheck是否包含stringArray的子字符串。如果你想确保它包含所有的子字符串，将Any更改为all:

if(stringArray.All(stringToCheck.Contains))

这些解决方案大多数是正确的，但如果你需要检查值不区分大小写:

using System.Linq;
...
string stringToCheck = "text1text2text3";
string[] stringArray = { "text1", "someothertext"};

if(stringArray.Any(a=> String.Equals(a, stringToCheck, StringComparison.InvariantCultureIgnoreCase)) )
{
   //contains
}

if (stringArray.Any(w=> w.IndexOf(stringToCheck, StringComparison.InvariantCultureIgnoreCase)>=0))
{
   //contains
}

dotNetFiddle例子