请问如何在ASP中获取客户端IP地址?NET时使用MVC 6。 请求。ServerVariables["REMOTE_ADDR"]无效。
当前回答
在。net 5中,我使用它通过AWS fargate上的容器来检索客户端IP。
public static class HttpContextExtensions
{
//https://gist.github.com/jjxtra/3b240b31a1ed3ad783a7dcdb6df12c36
public static IPAddress GetRemoteIPAddress(this HttpContext context, bool allowForwarded = true)
{
if (allowForwarded)
{
string header = (context.Request.Headers["CF-Connecting-IP"].FirstOrDefault() ?? context.Request.Headers["X-Forwarded-For"].FirstOrDefault());
if (IPAddress.TryParse(header, out IPAddress ip))
{
return ip;
}
}
return context.Connection.RemoteIpAddress;
}
}
你这样称呼它:
var ipFromExtensionMethod = HttpContext.GetRemoteIPAddress().ToString();
源
其他回答
API已经更新。不知道它什么时候改变了,但根据达米安·爱德华兹在12月底的说法,你现在可以这样做:
var remoteIpAddress = request.HttpContext.Connection.RemoteIpAddress;
也可以从外部服务获取IP。
public string GetIP()
{
HttpClient client = new HttpClient();
var result = client.GetStringAsync("https://jsonip.com/").Result;
var ip = JsonSerializer.Deserialize<RemoteIPDto>(result.ToString()).IP;
return ip;
}
RemoteIPDto类在哪里
public class RemoteIPDto
{
[JsonPropertyName("ip")]
public string IP { get; set; }
[JsonPropertyName("geo-ip")]
public string GeoIp { get; set; }
[JsonPropertyName("API Help")]
public string ApiHelp { get; set; }
}
从这个环节,就有了更好的解决方案。
在Startup.cs中,我们需要添加service-
public void ConfigureServices(IServiceCollection services)
{
........
services.AddHttpContextAccessor();
........
}
然后在任何控制器或任何地方,我们都需要像这样通过依赖注入来使用它
private IHttpContextAccessor HttpContextAccessor { get; }
public ApplicationDbContext(DbContextOptions<ApplicationDbContext> options, IWebHostEnvironment env, IHttpContextAccessor httpContextAccessor)
: base(options)
{
Environment = env;
HttpContextAccessor = httpContextAccessor;
//this.Database.EnsureCreated();
}
然后得到这样的IP
IPAddress userIp = HttpContextAccessor.HttpContext.Connection.RemoteIpAddress;
可以添加一些回退逻辑来处理负载均衡器的存在。
此外,通过检查,即使没有负载均衡器,X-Forwarded-For报头也会被设置(可能是因为额外的Kestrel层?):
public string GetRequestIP(bool tryUseXForwardHeader = true)
{
string ip = null;
// todo support new "Forwarded" header (2014) https://en.wikipedia.org/wiki/X-Forwarded-For
// X-Forwarded-For (csv list): Using the First entry in the list seems to work
// for 99% of cases however it has been suggested that a better (although tedious)
// approach might be to read each IP from right to left and use the first public IP.
// http://stackoverflow.com/a/43554000/538763
//
if (tryUseXForwardHeader)
ip = GetHeaderValueAs<string>("X-Forwarded-For").SplitCsv().FirstOrDefault();
// RemoteIpAddress is always null in DNX RC1 Update1 (bug).
if (ip.IsNullOrWhitespace() && _httpContextAccessor.HttpContext?.Connection?.RemoteIpAddress != null)
ip = _httpContextAccessor.HttpContext.Connection.RemoteIpAddress.ToString();
if (ip.IsNullOrWhitespace())
ip = GetHeaderValueAs<string>("REMOTE_ADDR");
// _httpContextAccessor.HttpContext?.Request?.Host this is the local host.
if (ip.IsNullOrWhitespace())
throw new Exception("Unable to determine caller's IP.");
return ip;
}
public T GetHeaderValueAs<T>(string headerName)
{
StringValues values;
if (_httpContextAccessor.HttpContext?.Request?.Headers?.TryGetValue(headerName, out values) ?? false)
{
string rawValues = values.ToString(); // writes out as Csv when there are multiple.
if (!rawValues.IsNullOrWhitespace())
return (T)Convert.ChangeType(values.ToString(), typeof(T));
}
return default(T);
}
public static List<string> SplitCsv(this string csvList, bool nullOrWhitespaceInputReturnsNull = false)
{
if (string.IsNullOrWhiteSpace(csvList))
return nullOrWhitespaceInputReturnsNull ? null : new List<string>();
return csvList
.TrimEnd(',')
.Split(',')
.AsEnumerable<string>()
.Select(s => s.Trim())
.ToList();
}
public static bool IsNullOrWhitespace(this string s)
{
return String.IsNullOrWhiteSpace(s);
}
假设_httpContextAccessor通过DI提供。
要在。net Core中获取IP地址和主机名,在控制器中输入以下代码:
var addlist = Dns.GetHostEntry(Dns.GetHostName());
string GetHostName = addlist.HostName.ToString();
string GetIPV6 = addlist.AddressList[0].ToString();
string GetIPV4 = addlist.AddressList[1].ToString();
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