我一直在寻找一种简单的Java算法来生成伪随机字母数字字符串。在我的情况下,它将被用作唯一的会话/密钥标识符,“很可能”在超过50万代的时间内是唯一的(我的需求实际上不需要更复杂的东西)。

理想情况下,我可以根据我的独特性需求指定长度。例如,生成的长度为12的字符串可能看起来像“AEYGF7K0DM1X”。


当前回答

最佳随机字符串生成器方法

public class RandomStringGenerator{

    private static int randomStringLength = 25 ;
    private static boolean allowSpecialCharacters = true ;
    private static String specialCharacters = "!@$%*-_+:";
    private static boolean allowDuplicates = false ;

    private static boolean isAlphanum = false;
    private static boolean isNumeric = false;
    private static boolean isAlpha = false;
    private static final String alphabet = "abcdefghijklmnopqrstuvwxyz";
    private static boolean mixCase = false;
    private static final String capAlpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    private static final String num = "0123456789";

    public static String getRandomString() {
        String returnVal = "";
        int specialCharactersCount = 0;
        int maxspecialCharacters = randomStringLength/4;

        try {
            StringBuffer values = buildList();
            for (int inx = 0; inx < randomStringLength; inx++) {
                int selChar = (int) (Math.random() * (values.length() - 1));
                if (allowSpecialCharacters)
                {
                    if (specialCharacters.indexOf("" + values.charAt(selChar)) > -1)
                    {
                        specialCharactersCount ++;
                        if (specialCharactersCount > maxspecialCharacters)
                        {
                            while (specialCharacters.indexOf("" + values.charAt(selChar)) != -1)
                            {
                                selChar = (int) (Math.random() * (values.length() - 1));
                            }
                        }
                    }
                }
                returnVal += values.charAt(selChar);
                if (!allowDuplicates) {
                    values.deleteCharAt(selChar);
                }
            }
        } catch (Exception e) {
            returnVal = "Error While Processing Values";
        }
        return returnVal;
    }

    private static StringBuffer buildList() {
        StringBuffer list = new StringBuffer(0);
        if (isNumeric || isAlphanum) {
            list.append(num);
        }
        if (isAlpha || isAlphanum) {
            list.append(alphabet);
            if (mixCase) {
                list.append(capAlpha);
            }
        }
        if (allowSpecialCharacters)
        {
            list.append(specialCharacters);
        }
        int currLen = list.length();
        String returnVal = "";
        for (int inx = 0; inx < currLen; inx++) {
            int selChar = (int) (Math.random() * (list.length() - 1));
            returnVal += list.charAt(selChar);
            list.deleteCharAt(selChar);
        }
        list = new StringBuffer(returnVal);
        return list;
    }   

}

其他回答

这是算盘常用的一行:

String.valueOf(CharStream.random('0', 'z').filter(c -> N.isLetterOrDigit(c)).limit(12).toArray())

随机并不意味着它必须是唯一的。要获取唯一字符串,请使用:

N.uuid() // E.g.: "e812e749-cf4c-4959-8ee1-57829a69a80f". length is 36.
N.guid() // E.g.: "0678ce04e18945559ba82ddeccaabfcd". length is 32 without '-'
import java.util.Random;

public class passGen{
    // Version 1.0
    private static final String dCase = "abcdefghijklmnopqrstuvwxyz";
    private static final String uCase = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    private static final String sChar = "!@#$%^&*";
    private static final String intChar = "0123456789";
    private static Random r = new Random();
    private static StringBuilder pass = new StringBuilder();

    public static void main (String[] args) {
        System.out.println ("Generating pass...");
        while (pass.length () != 16){
            int rPick = r.nextInt(4);
            if (rPick == 0){
                int spot = r.nextInt(26);
                pass.append(dCase.charAt(spot));
            } else if (rPick == 1) {
                int spot = r.nextInt(26);
                pass.append(uCase.charAt(spot));
            } else if (rPick == 2) {
                int spot = r.nextInt(8);
                pass.append(sChar.charAt(spot));
            } else {
                int spot = r.nextInt(10);
                pass.append(intChar.charAt(spot));
            }
        }
        System.out.println ("Generated Pass: " + pass.toString());
    }
}

这只是将密码添加到字符串中。。。是的,效果很好。过来看。。。这很简单;我写的。

使用Apache Commons库,可以在一行中完成:

import org.apache.commons.lang.RandomStringUtils;
RandomStringUtils.randomAlphanumeric(64);

文档

public static String randomSeriesForThreeCharacter() {
    Random r = new Random();
    String value = "";
    char random_Char ;
    for(int i=0; i<10; i++)
    {
        random_Char = (char) (48 + r.nextInt(74));
        value = value + random_char;
    }
    return value;
}

此外,您可以通过ASCII表中的数据生成任何小写或大写字母,甚至特殊字符。例如,生成从A(DEC 65)到Z(DEC 90)的大写字母:

String generateRandomStr(int min, int max, int size) {
    String result = "";
    for (int i = 0; i < size; i++) {
        result += String.valueOf((char)(new Random().nextInt((max - min) + 1) + min));
    }
    return result;
}

generateRandomStr(65、90、100)的生成输出;:

TVLPFQJCYFXQDCQSLKUKKILKKHAUFYEXLUQFHDWNMRBIRRRWNXNNZQTINZPCTKLHGHVYWRKEOYNSOFPZBGEECFMCOKWHLHCEWLDZ