使用欧 6扩展操作员 。

比方说你想删除4。

let array = [1,2,3,4,5]
const index = array.indexOf(4)
let new_array = [...array.slice(0,index), ...array.slice(index+1, array.length)]
console.log(new_array)
=> [1, 2, 3, 5]

尝试使用删除运算符

例如:

const arr = [10, 20, 30, 40, 50, 60];
delete arr[2]; // It will Delete element present at index 2
console.log( arr ); // [10, 20, undefined , 40, 50, 60]

注:使用删除运算符将会在数组中留下空空空/ 空洞。 它不会提醒数组的长度。 要在元素被删除时更改数组的长度, 请使用复数法 。

希望这能解决你所有的问题

你可以轻而易举地用过滤过滤器方法 :

function remove(arrOriginal, elementToRemove){
    return arrOriginal.filter(function(el){return el !== elementToRemove});
}
console.log(remove([1, 2, 1, 0, 3, 1, 4], 1));

这将清除数组中的所有元素, 并且运行速度比slice和indexOf.

除了所有这些解决方案之外, 它也可以用阵列来完成. 减量...

const removeItem = 
    idx => 
    arr => 
    arr.reduce((acc, a, i) =>  idx === i ? acc : acc.concat(a), [])

const array = [1, 2, 3]
const index = 1

const newArray = removeItem(index)(array) 

console.log(newArray) // logs the following array to the console : [1, 3]

...或者一个循环函数(诚实地说不是那么优雅...也许有人有更好的循环解决方案? ? )...

const removeItemPrep = 
    acc => 
    i => 
    idx => 
    arr => 

    // If the index equals i, just feed in the unchanged accumulator(acc) else...
    i === idx ? removeItemPrep(acc)(i + 1)(idx)(arr) :

    // If the array length + 1 of the accumulator is smaller than the array length of the original array concatenate the array element at index i else... 
    acc.length + 1 < arr.length ? removeItemPrep(acc.concat(arr[i]))(i + 1)(idx)(arr) : 

    // return the accumulator
    acc 

const removeItem = removeItemPrep([])(0)

const array = [1, 2, 3]
const index = 1

const newArray = removeItem(index)(array) 

console.log(newArray) // logs the following array to the console : [1, 3]

我还有一个从阵列中移除的好办法:

var words = ['spray', 'limit', 'elite', 'exuberant', 'destruction', 'present'];

const result = words.filter(word => word.length > 6);

console.log(result);
// expected output: Array ["exuberant", "destruction", "present"]

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

const newArray = oldArray.filter(item => item !== removeItem);