如何在Python中复制文件?
当前回答
首先,我对shutil方法做了详尽的备忘单,供您参考。
shutil_methods =
{'copy':['shutil.copyfileobj',
'shutil.copyfile',
'shutil.copymode',
'shutil.copystat',
'shutil.copy',
'shutil.copy2',
'shutil.copytree',],
'move':['shutil.rmtree',
'shutil.move',],
'exception': ['exception shutil.SameFileError',
'exception shutil.Error'],
'others':['shutil.disk_usage',
'shutil.chown',
'shutil.which',
'shutil.ignore_patterns',]
}
其次,举例说明复制方法:
shutil.copyfileobj(fsrc,fdst[,length])操纵打开的对象在[3]中:src='~/Documents/Head+First+SQL.pdf'在[4]中:dst='~/desktop'在[5]中:shutil.copyfileobj(src,dst)AttributeError:“str”对象没有属性“read”#复制文件对象在[7]中:open(src,'rb')为f1,open(os.path.join(dst,'test.pdf'),'wb')为f2:…:shutil.copyfileobj(f1,f2)在[8]中:os.stat(os.path.join(dst,'test.pdf'))输出[8]:os.stat_result(st_mode=33188,st_ino=8598319475,st_dev=16777220,st_nlink=1,st_uid=501,st_gid=20,st_size=13507926,st_atime=1516067347,st_mime=1516067335,st_ctime=1516087345)shutil.copyfile(src,dst,*,follow_symlinks=True)复制并重命名在[9]中:shutil.copyfile(src,dst)IsADirectoryError:[Erno 21]是一个目录:~/desktop'#所以dst应该是文件名而不是目录名shutil.copy()复制而不预先保存元数据在[10]中:shutil.copy(src,dst)输出[10]:~/desktop/Head+First+SQL.pdf'#检查其元数据在[25]中:os.stat(src)输出[25]:os.stat_result(st_mode=33188,st_ino=597749,st_dev=16777220,st_nlink=1,st_uid=501,st_gid=20,st_size=13507926,st_atime=1516066425,st_mtime=1493698739,st_ctime=1514871215)在[26]中:os.stat(os.path.join(dst,'Head+First+SQL.pdf'))输出[26]:os.stat_result(st_mode=33188,st_ino=8598313736,st_dev=16777220,st_nlink=1,st_uid=501,st_gid=20,st_size=13507926,st_atime=1516066427,st_mtime=1516086425,st_ctime=151066425)#st_atime、st_mtime、st_ctime已更改shutil.copy2()复制并保留元数据在[30]中:shutil.copy2(src,dst)输出[30]:~/desktop/Head+First+SQL.pdf'在[31]中:os.stat(src)输出[31]:os.stat_result(st_mode=33188,st_ino=597749,st_dev=16777220,st_nlink=1,st_uid=501,st_gid=20,st_size=13507926,st_atime=1516067055,st_mtime=1493698739,st_ctime=1514871215)在[32]中:os.stat(os.path.join(dst,'Head+First+SQL.pdf'))输出[32]:os.stat_result(st_mode=33188,st_ino=8598313736,st_dev=16777220,st_nlink=1,st_uid=501,st_gid=20,st_size=13507926,st_atime=1516067063,st_mtime=1493698739,st_ctime=1516087055)#保留时间(_m)shutil.copytree()递归复制以src为根的整个目录树,返回目标目录。
其他回答
使用subprocess.call复制文件
from subprocess import call
call("cp -p <file> <file>", shell=True)
这是一个利用“shutil.copyfileobj”的答案,它非常高效。我在不久前创建的一个工具中使用了它。我最初没有写这篇文章,但我稍微修改了一下。
def copyFile(src, dst, buffer_size=10485760, perserveFileDate=True):
'''
@param src: Source File
@param dst: Destination File (not file path)
@param buffer_size: Buffer size to use during copy
@param perserveFileDate: Preserve the original file date
'''
# Check to make sure destination directory exists. If it doesn't create the directory
dstParent, dstFileName = os.path.split(dst)
if(not(os.path.exists(dstParent))):
os.makedirs(dstParent)
# Optimize the buffer for small files
buffer_size = min(buffer_size,os.path.getsize(src))
if(buffer_size == 0):
buffer_size = 1024
if shutil._samefile(src, dst):
raise shutil.Error("`%s` and `%s` are the same file" % (src, dst))
for fn in [src, dst]:
try:
st = os.stat(fn)
except OSError:
# File most likely does not exist
pass
else:
# XXX What about other special files? (sockets, devices...)
if shutil.stat.S_ISFIFO(st.st_mode):
raise shutil.SpecialFileError("`%s` is a named pipe" % fn)
with open(src, 'rb') as fsrc:
with open(dst, 'wb') as fdst:
shutil.copyfileobj(fsrc, fdst, buffer_size)
if(perserveFileDate):
shutil.copystat(src, dst)
复制文件是一个相对简单的操作,如下面的示例所示,但是您应该使用shutilstdlib模块。
def copyfileobj_example(source, dest, buffer_size=1024*1024):
"""
Copy a file from source to dest. source and dest
must be file-like objects, i.e. any object with a read or
write method, like for example StringIO.
"""
while True:
copy_buffer = source.read(buffer_size)
if not copy_buffer:
break
dest.write(copy_buffer)
如果要按文件名复制,可以执行以下操作:
def copyfile_example(source, dest):
# Beware, this example does not handle any edge cases!
with open(source, 'rb') as src, open(dest, 'wb') as dst:
copyfileobj_example(src, dst)
目录和文件复制示例,来自Tim Golden的Python Stuff:
import os
import shutil
import tempfile
filename1 = tempfile.mktemp (".txt")
open (filename1, "w").close ()
filename2 = filename1 + ".copy"
print filename1, "=>", filename2
shutil.copy (filename1, filename2)
if os.path.isfile (filename2): print "Success"
dirname1 = tempfile.mktemp (".dir")
os.mkdir (dirname1)
dirname2 = dirname1 + ".copy"
print dirname1, "=>", dirname2
shutil.copytree (dirname1, dirname2)
if os.path.isdir (dirname2): print "Success"
Use
open(destination, 'wb').write(open(source, 'rb').read())
以读取模式打开源文件,以写入模式写入目标文件。
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