当我运行一个简单的Ruby脚本时,将对象的字段转储到控制台的最简单方法是什么?

我正在寻找与PHP的print_r()类似的东西,它也将与数组一起工作。


当前回答

object.attribute_names

# => ["id", "name", "email", "created_at", "updated_at", "password_digest", "remember_token", "admin", "marketing_permissions", "terms_and_conditions", "disable", "black_list", "zero_cost", "password_reset_token", "password_reset_sent_at"]


object.attributes.values

# => [1, "tom", "tom@tom.com", Tue, 02 Jun 2015 00:16:03 UTC +00:00, Tue, 02 Jun 2015 00:22:35 UTC +00:00, "$2a$10$gUTr3lpHzXvCDhVvizo8Gu/MxiTrazOWmOQqJXMW8gFLvwDftF9Lm", "2dd1829c9fb3af2a36a970acda0efe5c1d471199", true, nil, nil, nil, nil, nil, nil, nil] 

其他回答

to_yaml方法有时似乎很有用:

$foo = {:name => "Clem", :age => 43}

puts $foo.to_yaml

返回

--- 
:age: 43
:name: Clem

(这是否依赖于某些YAML模块被加载?或者这通常是可行的?)

可能是:

puts variable.inspect

如果你只是在对象中寻找实例变量,这可能是有用的:

obj.instance_variables.each do |var|
  puts [var, obj.instance_variable_get(var).inspect].join(":")
end

或者作为一行代码用于复制和粘贴:

obj.instance_variables.each{ |var| puts [var, obj.instance_variable_get(var).inspect].join(":")}
p object

Ruby doc表示p。

p (* args) 对于每个对象,直接写入obj。检查之后 通过换行符转换到程序的标准输出。

object.attribute_names

# => ["id", "name", "email", "created_at", "updated_at", "password_digest", "remember_token", "admin", "marketing_permissions", "terms_and_conditions", "disable", "black_list", "zero_cost", "password_reset_token", "password_reset_sent_at"]


object.attributes.values

# => [1, "tom", "tom@tom.com", Tue, 02 Jun 2015 00:16:03 UTC +00:00, Tue, 02 Jun 2015 00:22:35 UTC +00:00, "$2a$10$gUTr3lpHzXvCDhVvizo8Gu/MxiTrazOWmOQqJXMW8gFLvwDftF9Lm", "2dd1829c9fb3af2a36a970acda0efe5c1d471199", true, nil, nil, nil, nil, nil, nil, nil]