从这个问题中: https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411

我在@Aaron Bertrand提供的答案中添加了记录计数，该答案列出了所有数据库和所有表。

DECLARE @src NVARCHAR(MAX), @sql NVARCHAR(MAX);

SELECT @sql = N'', @src = N' UNION ALL 
SELECT ''$d'' as ''database'', 
    s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
    t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
    ind.rows as record_count
  FROM [$d].sys.schemas AS s
  INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
  INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
  where ind.indid < 2';

SELECT @sql = @sql + REPLACE(@src, '$d', name)
  FROM sys.databases
  WHERE database_id > 4
    AND [state] = 0
    AND HAS_DBACCESS(name) = 1;

SET @sql = STUFF(@sql, 1, 10, CHAR(13) + CHAR(10));

PRINT @sql;
--EXEC sys.sp_executesql @sql;

首先想到的是使用sp_msForEachTable

exec sp_msforeachtable 'select count(*) from ?'

但是它没有列出表名，所以可以扩展到

exec sp_msforeachtable 'select parsename(''?'', 1),  count(*) from ?'

这里的问题是，如果数据库有超过100个表，你会得到以下错误消息:

查询已超过最大值 可以的结果集的数目 显示在结果网格中。只有 前100个结果集是 显示在网格中。

所以我最终使用表变量来存储结果

declare @stats table (n sysname, c int)
insert into @stats
    exec sp_msforeachtable 'select parsename(''?'', 1),  count(*) from ?'
select 
    * 
from @stats
order by c desc

接受的答案在Azure SQL上不适合我，这里有一个，它非常快，完全符合我的要求:

select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
  ON t.object_id = s.object_id
    and t.type_desc = 'USER_TABLE'
    and t.name not like '%dss%'
    and s.index_id = 1
order by s.row_count desc

如果你使用的是SQL Server 2005及以上版本，你也可以使用这个:

SELECT 
    t.NAME AS TableName,
    i.name as indexName,
    p.[Rows],
    sum(a.total_pages) as TotalPages, 
    sum(a.used_pages) as UsedPages, 
    sum(a.data_pages) as DataPages,
    (sum(a.total_pages) * 8) / 1024 as TotalSpaceMB, 
    (sum(a.used_pages) * 8) / 1024 as UsedSpaceMB, 
    (sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
WHERE 
    t.NAME NOT LIKE 'dt%' AND
    i.OBJECT_ID > 255 AND   
    i.index_id <= 1
GROUP BY 
    t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY 
    object_name(i.object_id) 

在我看来，它比sp_msforeachtable输出更容易处理。

以下是我对这个问题的看法。它包含所有模式，只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;

如果您使用MySQL >4。X你可以用这个:

select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";

请记住，对于某些存储引擎，TABLE_ROWS只是一个近似值。