我想知道boto3中是否存在一个键。我可以循环桶内容并检查键是否匹配。

但这似乎太长了,也太过分了。Boto3官方文档明确说明了如何做到这一点。

也许我忽略了最明显的一点。有人能告诉我怎么做吗?


当前回答

import boto3
client = boto3.client('s3')
s3_key = 'Your file without bucket name e.g. abc/bcd.txt'
bucket = 'your bucket name'
content = client.head_object(Bucket=bucket,Key=s3_key)
    if content.get('ResponseMetadata',None) is not None:
        print "File exists - s3://%s/%s " %(bucket,s3_key) 
    else:
        print "File does not exist - s3://%s/%s " %(bucket,s3_key)

其他回答

get()方法非常简单

import botocore
from boto3.session import Session
session = Session(aws_access_key_id='AWS_ACCESS_KEY',
                aws_secret_access_key='AWS_SECRET_ACCESS_KEY')
s3 = session.resource('s3')
bucket_s3 = s3.Bucket('bucket_name')

def not_exist(file_key):
    try:
        file_details = bucket_s3.Object(file_key).get()
        # print(file_details) # This line prints the file details
        return False
    except botocore.exceptions.ClientError as e:
        if e.response['Error']['Code'] == "NoSuchKey": # or you can check with e.reponse['HTTPStatusCode'] == '404'
            return True
        return False # For any other error it's hard to determine whether it exists or not. so based on the requirement feel free to change it to True/ False / raise Exception

print(not_exist('hello_world.txt')) 

如果您寻找一个与目录等效的键,那么您可能需要这种方法

session = boto3.session.Session()
resource = session.resource("s3")
bucket = resource.Bucket('mybucket')

key = 'dir-like-or-file-like-key'
objects = [o for o in bucket.objects.filter(Prefix=key).limit(1)]    
has_key = len(objects) > 0

这适用于父键或等同于文件的键或不存在的键。我尝试了上面喜欢的方法,但在父键上失败了。

FWIW,这里是我正在使用的非常简单的函数

import boto3

def get_resource(config: dict={}):
    """Loads the s3 resource.

    Expects AWS_ACCESS_KEY_ID and AWS_SECRET_ACCESS_KEY to be in the environment
    or in a config dictionary.
    Looks in the environment first."""

    s3 = boto3.resource('s3',
                        aws_access_key_id=os.environ.get(
                            "AWS_ACCESS_KEY_ID", config.get("AWS_ACCESS_KEY_ID")),
                        aws_secret_access_key=os.environ.get("AWS_SECRET_ACCESS_KEY", config.get("AWS_SECRET_ACCESS_KEY")))
    return s3


def get_bucket(s3, s3_uri: str):
    """Get the bucket from the resource.
    A thin wrapper, use with caution.

    Example usage:

    >> bucket = get_bucket(get_resource(), s3_uri_prod)"""
    return s3.Bucket(s3_uri)


def isfile_s3(bucket, key: str) -> bool:
    """Returns T/F whether the file exists."""
    objs = list(bucket.objects.filter(Prefix=key))
    return len(objs) == 1 and objs[0].key == key


def isdir_s3(bucket, key: str) -> bool:
    """Returns T/F whether the directory exists."""
    objs = list(bucket.objects.filter(Prefix=key))
    return len(objs) > 1

这里有一个对我有用的解决办法。需要注意的是,我事先知道密钥的确切格式,所以我只列出单个文件

import boto3

# The s3 base class to interact with S3
class S3(object):
  def __init__(self):
    self.s3_client = boto3.client('s3')

  def check_if_object_exists(self, s3_bucket, s3_key):
    response = self.s3_client.list_objects(
      Bucket = s3_bucket,
      Prefix = s3_key
      )
    if 'ETag' in str(response):
      return True
    else:
      return False

if __name__ == '__main__':
  s3  = S3()
  if s3.check_if_object_exists(bucket, key):
    print "Found S3 object."
  else:
    print "No object found."

假设您只是想检查一个键是否存在(而不是悄悄地覆盖它),首先进行这个检查。也会检查错误:

import boto3

def key_exists(mykey, mybucket):
    s3_client = boto3.client('s3')
    try:
        response = s3_client.list_objects_v2(Bucket=mybucket, Prefix=mykey)
        for obj in response['Contents']:
            if mykey == obj['Key']:
                return 'exists'
        return False  # no keys match
    except KeyError:
        return False  # no keys found
    except Exception as e:
        # Handle or log other exceptions such as bucket doesn't exist
        return e

key_check = key_exists('someprefix/myfile-abc123', 'my-bucket-name')
if key_check:
    if key_check == 'exists':
        print("key exists!")
    else:
        print(f"S3 ERROR: {e}")
else:
    print("safe to put new bucket object")
    # try:
    #     resp = s3_client.put_object(Body="Your string or file-like object",
    #                                 Bucket=mybucket,Key=mykey)
    # ...check resp success and ClientError exception for errors...