我如何上传一个文件与JS获取API?

我还在试着接受这件事。

我可以让用户选择文件(甚至多个)与文件输入:

<form>
  <div>
    <label>Select file to upload</label>
    <input type="file">
  </div>
  <button type="submit">Convert</button>
</form>

我可以用<填充事件处理程序>来捕获提交事件。但是一旦我这样做了，我如何使用fetch发送文件?

fetch('/files', {
  method: 'post',
  // what goes here? What is the "body" for this? content-type header?
}).then(/* whatever */);

当前回答

要提交单个文件，你可以直接使用输入的.files数组中的file对象作为fetch()初始化器中body:的值:

const myInput = document.getElementById('my-input');

// Later, perhaps in a form 'submit' handler or the input's 'change' handler:
fetch('https://example.com/some_endpoint', {
  method: 'POST',
  body: myInput.files[0],
});

这是因为File继承自Blob，而Blob是在Fetch标准中定义的允许的BodyInit类型之一。

2018-01-23 19:52:51

其他回答

这是我的代码:

html:

2019-12-13 10:07:45

对我来说，问题是我正在使用response.blob()填充表单数据。显然你不能这样做，至少用react native，所以我最终使用

data.append('fileData', {
  uri : pickerResponse.uri,
  type: pickerResponse.type,
  name: pickerResponse.fileName
 });

Fetch似乎可以识别该格式，并将文件发送到uri指向的位置。

2018-11-03 03:03:57

这是一个带有注释的基本示例。上传功能就是你要找的:

// Select your input type file and store it in a variable
const input = document.getElementById('fileinput');

// This will upload the file after having read it
const upload = (file) => {
  fetch('http://www.example.net', { // Your POST endpoint
    method: 'POST',
    headers: {
      // Content-Type may need to be completely **omitted**
      // or you may need something
      "Content-Type": "You will perhaps need to define a content-type here"
    },
    body: file // This is your file object
  }).then(
    response => response.json() // if the response is a JSON object
  ).then(
    success => console.log(success) // Handle the success response object
  ).catch(
    error => console.log(error) // Handle the error response object
  );
};

// Event handler executed when a file is selected
const onSelectFile = () => upload(input.files[0]);

// Add a listener on your input
// It will be triggered when a file will be selected
input.addEventListener('change', onSelectFile, false);

2016-03-18 10:31:20

添加php端点示例会很好。这就是js:

const uploadinput = document.querySelector('#uploadinputid');
const uploadBtn = document.querySelector('#uploadBtnid');
uploadBtn.addEventListener('click',uploadFile);

async function uploadFile(){
    const formData = new FormData();
    formData.append('nameusedinFormData',uploadinput.files[0]);    
    try{
        const response = await fetch('server.php',{
            method:'POST',
            body:formData
        } );
        const result = await response.json();
        console.log(result);
    }catch(e){
        console.log(e);

    }
}

这就是php:

$file = $_FILES['nameusedinFormData'];
$temp = $file['tmp_name'];
$target_file = './targetfilename.jpg';
move_uploaded_file($_FILES["image"]["tmp_name"], $target_file);

2021-05-03 10:56:20

我是这样做的:

var input = document.querySelector('input[type="file"]')

var data = new FormData()
data.append('file', input.files[0])
data.append('user', 'hubot')

fetch('/avatars', {
  method: 'POST',
  body: data
})

2016-11-27 08:05:51

我如何上传一个文件与JS获取API?

推荐文章

标签

最新文章