我在这段代码的输出中得到了很多小数(华氏到摄氏度转换器)。

我的代码目前看起来是这样的:

def main():
    printC(formeln(typeHere()))

def typeHere():
    global Fahrenheit
    try:
        Fahrenheit = int(raw_input("Hi! Enter Fahrenheit value, and get it in Celsius!\n"))
    except ValueError:
        print "\nYour insertion was not a digit!"
        print "We've put your Fahrenheit value to 50!"
        Fahrenheit = 50
    return Fahrenheit

def formeln(c):
    Celsius = (Fahrenheit - 32.00) * 5.00/9.00
    return Celsius

def printC(answer):
    answer = str(answer)
    print "\nYour Celsius value is " + answer + " C.\n"



main()

我的问题是,如何让程序把每个答案四舍五入到小数点后2位?


当前回答

你可以使用round函数。

round(80.23456, 3)

会给你80.234的答案吗

在你的情况下,使用

answer = str(round(answer, 2))

其他回答

截2指炎:

somefloat = 2.23134133
truncated = int( somefloat * 100 ) / 100  # 2.23

到目前为止我发现的最简单的解决方案,不知道为什么人们不使用它。

# Make sure the number is a float
a = 2324.55555
# Round it according to your needs
# dPoints is the decimals after the point
dPoints = 2
# this will round the float to 2 digits
a = a.__round__(dPoints)
if len(str(a).split(".")[1]) < dPoints:
    # But it will only keep one 0 if there is nothing,
    # So we add the extra 0s we need
    print(str(a)+("0"*(dPoints-1)))
else:
    print(a)

简单的例子

比尔= 10.24 打印(圆(10.241))

您可以使用四舍五入运算符最多为2小数

num = round(343.5544, 2)
print(num) // output is 343.55
float(str(round(answer, 2)))
float(str(round(0.0556781255, 2)))