让我们把你的优秀和最喜欢的扩展方法列一个列表。
要求是必须发布完整的代码，以及如何使用它的示例和解释。
基于对这个主题的高度兴趣，我在Codeplex上建立了一个名为extensionoverflow的开源项目。
请将您的回答标记为接受，以便将代码放入Codeplex项目。
请张贴完整的源代码，而不是一个链接。
Codeplex上新闻:
24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/
11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。
11.11.2008仍有发展空间。;-)现在就加入!
11.11.2008第三位贡献者加入了ExtensionOverflow，欢迎加入BKristensen
11.11.2008 FormatWith现在是实现和单元测试。
09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。
我们需要更多的开发人员。: -)
09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。
这是罗马数字的to-and-from。不常用，但可能很方便。用法:
if ("IV".IsValidRomanNumeral())
{
// Do useful stuff with the number 4.
}
Console.WriteLine("MMMDCCCLXXXVIII".ParseRomanNumeral());
Console.WriteLine(3888.ToRomanNumeralString());
源:
public static class RomanNumeralExtensions
{
private const int NumberOfRomanNumeralMaps = 13;
private static readonly Dictionary<string, int> romanNumerals =
new Dictionary<string, int>(NumberOfRomanNumeralMaps)
{
{ "M", 1000 },
{ "CM", 900 },
{ "D", 500 },
{ "CD", 400 },
{ "C", 100 },
{ "XC", 90 },
{ "L", 50 },
{ "XL", 40 },
{ "X", 10 },
{ "IX", 9 },
{ "V", 5 },
{ "IV", 4 },
{ "I", 1 }
};
private static readonly Regex validRomanNumeral = new Regex(
"^(?i:(?=[MDCLXVI])((M{0,3})((C[DM])|(D?C{0,3}))"
+ "?((X[LC])|(L?XX{0,2})|L)?((I[VX])|(V?(II{0,2}))|V)?))$",
RegexOptions.Compiled);
public static bool IsValidRomanNumeral(this string value)
{
return validRomanNumeral.IsMatch(value);
}
public static int ParseRomanNumeral(this string value)
{
if (value == null)
{
throw new ArgumentNullException("value");
}
value = value.ToUpperInvariant().Trim();
var length = value.Length;
if ((length == 0) || !value.IsValidRomanNumeral())
{
throw new ArgumentException("Empty or invalid Roman numeral string.", "value");
}
var total = 0;
var i = length;
while (i > 0)
{
var digit = romanNumerals[value[--i].ToString()];
if (i > 0)
{
var previousDigit = romanNumerals[value[i - 1].ToString()];
if (previousDigit < digit)
{
digit -= previousDigit;
i--;
}
}
total += digit;
}
return total;
}
public static string ToRomanNumeralString(this int value)
{
const int MinValue = 1;
const int MaxValue = 3999;
if ((value < MinValue) || (value > MaxValue))
{
throw new ArgumentOutOfRangeException("value", value, "Argument out of Roman numeral range.");
}
const int MaxRomanNumeralLength = 15;
var sb = new StringBuilder(MaxRomanNumeralLength);
foreach (var pair in romanNumerals)
{
while (value / pair.Value > 0)
{
sb.Append(pair.Key);
value -= pair.Value;
}
}
return sb.ToString();
}
}
有时使用自定义分隔符在列表中选中的元素上写出字符串是很方便的。
例如，如果你有一个List<Person>并且想要用逗号分隔姓氏，你可以这样做。
string result = string.Empty;
foreach (var person in personList) {
result += person.LastName + ", ";
}
result = result.Substring(0, result.Length - 2);
return result;
或者你可以使用这个方便的扩展方法
public static string Join<T>(this IEnumerable<T> collection, Func<T, string> func, string separator)
{
return String.Join(separator, collection.Select(func).ToArray());
}
像这样使用它
personList.Join(x => x.LastName, ", ");
这将产生相同的结果，在本例中是由逗号分隔的姓氏列表。
您可以从Random类中获得许多功能。
下面是我经常使用的一些扩展方法。有了这些，除了Next和NextDouble, Random类还提供了NextBool, NextChar, NextDateTime, NextTimeSpan, NextDouble(接受minValue和maxValue参数)，以及我个人最喜欢的NextString。还有更多(NextByte, NextShort, NextLong等);但这些主要是为了完整性，并不经常使用。所以我没有在这里包含它们(这段代码已经足够长了!)。
// todo: implement additional CharType values (e.g., AsciiAny)
public enum CharType {
AlphabeticLower,
AlphabeticUpper,
AlphabeticAny,
AlphanumericLower,
AlphanumericUpper,
AlphanumericAny,
Numeric
}
public static class RandomExtensions {
// 10 digits vs. 52 alphabetic characters (upper & lower);
// probability of being numeric: 10 / 62 = 0.1612903225806452
private const double AlphanumericProbabilityNumericAny = 10.0 / 62.0;
// 10 digits vs. 26 alphabetic characters (upper OR lower);
// probability of being numeric: 10 / 36 = 0.2777777777777778
private const double AlphanumericProbabilityNumericCased = 10.0 / 36.0;
public static bool NextBool(this Random random, double probability) {
return random.NextDouble() <= probability;
}
public static bool NextBool(this Random random) {
return random.NextDouble() <= 0.5;
}
public static char NextChar(this Random random, CharType mode) {
switch (mode) {
case CharType.AlphabeticAny:
return random.NextAlphabeticChar();
case CharType.AlphabeticLower:
return random.NextAlphabeticChar(false);
case CharType.AlphabeticUpper:
return random.NextAlphabeticChar(true);
case CharType.AlphanumericAny:
return random.NextAlphanumericChar();
case CharType.AlphanumericLower:
return random.NextAlphanumericChar(false);
case CharType.AlphanumericUpper:
return random.NextAlphanumericChar(true);
case CharType.Numeric:
return random.NextNumericChar();
default:
return random.NextAlphanumericChar();
}
}
public static char NextChar(this Random random) {
return random.NextChar(CharType.AlphanumericAny);
}
private static char NextAlphanumericChar(this Random random, bool uppercase) {
bool numeric = random.NextBool(AlphanumericProbabilityNumericCased);
if (numeric)
return random.NextNumericChar();
else
return random.NextAlphabeticChar(uppercase);
}
private static char NextAlphanumericChar(this Random random) {
bool numeric = random.NextBool(AlphanumericProbabilityNumericAny);
if (numeric)
return random.NextNumericChar();
else
return random.NextAlphabeticChar(random.NextBool());
}
private static char NextAlphabeticChar(this Random random, bool uppercase) {
if (uppercase)
return (char)random.Next(65, 91);
else
return (char)random.Next(97, 123);
}
private static char NextAlphabeticChar(this Random random) {
return random.NextAlphabeticChar(random.NextBool());
}
private static char NextNumericChar(this Random random) {
return (char)random.Next(48, 58);
}
public static DateTime NextDateTime(this Random random, DateTime minValue, DateTime maxValue) {
return DateTime.FromOADate(
random.NextDouble(minValue.ToOADate(), maxValue.ToOADate())
);
}
public static DateTime NextDateTime(this Random random) {
return random.NextDateTime(DateTime.MinValue, DateTime.MaxValue);
}
public static double NextDouble(this Random random, double minValue, double maxValue) {
if (maxValue < minValue)
throw new ArgumentException("Minimum value must be less than maximum value.");
double difference = maxValue - minValue;
if (!double.IsInfinity(difference))
return minValue + (random.NextDouble() * difference);
else {
// to avoid evaluating to Double.Infinity, we split the range into two halves:
double halfDifference = (maxValue * 0.5) - (minValue * 0.5);
// 50/50 chance of returning a value from the first or second half of the range
if (random.NextBool())
return minValue + (random.NextDouble() * halfDifference);
else
return (minValue + halfDifference) + (random.NextDouble() * halfDifference);
}
}
public static string NextString(this Random random, int numChars, CharType mode) {
char[] chars = new char[numChars];
for (int i = 0; i < numChars; ++i)
chars[i] = random.NextChar(mode);
return new string(chars);
}
public static string NextString(this Random random, int numChars) {
return random.NextString(numChars, CharType.AlphanumericAny);
}
public static TimeSpan NextTimeSpan(this Random random, TimeSpan minValue, TimeSpan maxValue) {
return TimeSpan.FromMilliseconds(
random.NextDouble(minValue.TotalMilliseconds, maxValue.TotalMilliseconds)
);
}
public static TimeSpan NextTimeSpan(this Random random) {
return random.NextTimeSpan(TimeSpan.MinValue, TimeSpan.MaxValue);
}
}
二分查找:
public static T BinarySearch<T, TKey>(this IList<T> list, Func<T, TKey> keySelector, TKey key)
where TKey : IComparable<TKey>
{
int min = 0;
int max = list.Count;
int index = 0;
while (min < max)
{
int mid = (max + min) / 2;
T midItem = list[mid];
TKey midKey = keySelector(midItem);
int comp = midKey.CompareTo(key);
if (comp < 0)
{
min = mid + 1;
}
else if (comp > 0)
{
max = mid - 1;
}
else
{
return midItem;
}
}
if (min == max &&
keySelector(list[min]).CompareTo(key) == 0)
{
return list[min];
}
throw new InvalidOperationException("Item not found");
}
用法(假设列表按Id排序):
var item = list.BinarySearch(i => i.Id, 42);
它抛出InvalidOperationException的事实可能看起来很奇怪，但这就是Enumerable。第一种情况是没有匹配项。
